sc coin

/* (Amazing question) I thought it was a problem with the mother function at the beginning, but I can solve it with the mother function, but it definitely times out. Later, Baidu found the following solution:# Include # Include Using namespace STD;Int A [32768];Int main (){Int N, I;A [0] = 0;For (I = 1; I {If (I % 6 = 1 I! = 1)A [I] = A [I-1] + (I/6 );ElseA [I] = A [I-1] + (I/6 + 1 );}While (scanf ("% d", N )! = EOF)Printf ("% d/N", a [n]);Return 0;} If (I % 6 = 1 I! = 1)A [I] = A [I-1]

Time limit:1000ms Memory limit:32768kb 64bit IO format:%i64d %i64uSubmit StatusDescriptionIn a country there are only 1 cents, 2 cents, 3 cents, and there are many ways to exchange money n coins. Please write a procedure to figure out how many kinds of methods are in common. InputOnly one positive integer per line n,n less than 32768. OutputFor each input, the output conversion method number. Sample Input293412553 Sample Output71883113137761 Although this is a knapsack problem, but the Vegetable

Tips for solving problems: (Frog jump Step: There are N-step, frogs can jump one step at a time can also jump two-step, ask how good the total number of Jump method) 1, before the idea of this problem was mistaken, thought is a recursive, like a frog jumping steps, with Fibonacci solution. But the Fibonacci will definitely go beyond the scope. In turn thinking of their own thinking is actually wrong. Frog jump step In fact, to distinguish between the order, such as three steps, first jump two an

Poj 1013 Counterfeit dollar Time limit:1000 ms Memory limit:10000 K Total submissions:27117 Accepted:8460 DescriptionSally Jones has a dozen Voyageur silver dollars. however, only eleven of the coins are true silver dollars; one coin is counterfeit even though its color and size make it indistinguishable from the real silver dollars. the counterfeit coin has a different

Coin Change Time Limit: 3000MS Memory Limit: Unknown 64bit IO Format: %lld %llu Suppose there is 5 types of coins:50-cent, 25-cent, 10-cent, 5-cent, and 1-cent. We want to make changes with these coins for a given amount of money.For example, if we had one cents, then we can make changes with one 10-cent coin and one 1-cent

Coin ChangeTime limit:1000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 16592 Accepted Submission (s): 5656Problem Descriptionsuppose There is 5 types of coins:50-cent, 25-cent, 10-cent, 5-cent, and 1-cent. We want to make changes with these coins for a given amount of money.For example, if we had one cents, then we can make changes with one 10-cent coin and one 1-cent

Test instructions did not understand, there is no consideration of special circumstances 0, resulting in my contribution 7 times WA, thanks to Mau Mau reminderCoin Test time limit: theMs | Memory Limit:65535KB Difficulty:1 Describe As is known To all,if you throw a coin up and let it droped on the desk there is usually three results. Yes,just believe what I say ~it can is the right side or the other side or standing on the de

) { e.printStackTrace(); } }} However, Sleep Sort cannot Sort negative numbers and floating-point numbers. Of course, for negative numbers, you can add a huge number to change to a positive number. But it must be slow. In addition, if the system thread sleep precision is insufficient, the sorting speed is certainly inferior to those of the traditional sorting methods. Coin Simulation Problem description: The probability of a

HDU 2069 Coin Change functions HDU 2069 Coin Change functions This question is a little more complex than a common primary function to solve the problem. The number of components is limited and the number of combinations cannot exceed 100 coins. Therefore, c1 and c2 are defined as two-dimensional arrays, c1 [I] [j] indicates c1 [Result] [number of results], and then a loop of traversal numbers is added.

if(Y[v] = =-1||DFS (Y[v])) the { +Y[V] = u; X[u] = v;return true; - } $ } $ } - - return false; the } - Wuyi voidHungaryvoid) the { -Sort (p+1, p+1+N); memset (Svis,0,sizeof(Svis)); WuUN =0; - for(intI=1; ii) About { $ if(Svis[i]! =0|| P[i].rk%4>1)Continue; -Svis[i] =-1; Mp[++un] =i; - for(intj=1; jj) - { A if(Svis[j] = =-1|| P[j].rk%41)Continue; + if(ABS (P[I].RK-P[J].RK)! =2)Continue

I learned this before when I thought about greedy algorithms. In fact, the application of greedy algorithms is a prerequisite. Under the current situation, for example, the values of common 1, 2, and 5, 10 are carefully designed. In fact, most of them should use dynamic planning. Of course, this article only uses search. For details, refer to the following connection. For example, values 1 2 and 2 1 are the same. In integer decomposition, the array is incremented. For example, 10 is used to brea

Topic Links:http://www.lightoj.com/volume_showproblem.php?problem=1235Title Description:Give n coins, each coin use up to two times, ask can form K value?Problem Solving Ideas:Because K chicken big, although n is very small, but 2^n is very big, cannot use the knapsack to do O (NK) complexity. If the violent enumeration complexity immediately soared to O (2^ (n+1)).So the introduction of a new algorithm, binary lookup: The value to be enumerated, the

DescriptionCoin shopping A total of 4 kinds of coins. The denominations were c1,c2,c3,c4. Someone went to the store to buy something and went to tot. Each time with a di ci coin, buy something of Si value. How many methods of payment do you have each time?InputThe first line C1,c2,c3,c4,tot under the Tot line d1,d2,d3,d4,sOutputNumber of methods per timeSample Input1 2 5) 10 23 2 3) 1 102 2 2Sample Output4-HINTData sizedi,stotSolution: Because the dat

Description of the n kinds of coins, the face value of the a[1],a[2],a[3]......a[n], each has an infinite number of. Given a nonnegative integer s, how many coins can be selected to make the face value and exactly s? Output coin number min and max input format 1th row nLine 2nd S3rd to n+2 behavior n different face value output format 1th behavior minimum2nd Behavior Max Test Sample 1 input 3 6 1 2 3 Output 2 6 R

Coin Exchange IssuesTime limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others)Total submission (s): 9699 Accepted Submission (s): 5898Problem description in a country only 1 points, 2 points, 3 cent coins, the exchange of money n into coins there are many kinds of laws. Please compile the procedure to calculate the total number of different methods.Input has only one positive integer n,n less than 32768 per line.Output corresponds

This is avery good blog post: http://www.cnblogs.com/python27/archive/2013/09/05/3303721.html#include using namespacestd;intdp[10000][10000];intcoin[]={0,1,5,Ten, -, -};voidFdintx) { for(intI=0; i5; i++) dp[i][0]=1; for(intI=1; i5; i++) for(intj=1; j) for(intk=0; k) Dp[i][j]+=dp[i-1][j-k*Coin[i]];}intMain () {intx; FD (7489); while(~SCANF ("%d",x)) printf ("%d\n", dp[5][x]); return 0;}Coi