StreamReader (This.txtpath);
String line;
int count = 0;
while (line = Sr. ReadLine ())!= null)
{
Line + + "fuck";
count++;
}
return count;
}
public string readtxttohtml ()
{
String line;//one line of text
int ptr = 0;//row count
int TTP = maximum number of pages after paging 1;//
StreamReader sr = new StreamReader (Txtpath);
String htmlstr = "";//for storing HTML code
Htmlstr = "#" + TTP
subject (MA): connects to the database on the same host as the database and CGI programs running on the WEB server of the local machine through socket, and accesses the database at the same time, communicate with each TSA through socket. Receive configuration modifications sent by CGI, distribute the modified configuration files in the database to TSA, receive data, data requests, and alarms sent by
Evaluation Address: https://cn.vjudge.net/problem/CSU-1632Descriptionin the string, all occurrences of at least 2 number of sub-strings of the secondInputfirst act an integer T (t represents the number of use case groups, with each group of use cases occupying a length of 100000 the stringOutputFor each set of use cases, output the number of substrings that appear at least two times in the stringSample Input3AabaabAaaaaAaAaASample Output545SolutionAns=sum ( max (height (i)-height (i-1), 0) )#inc
Ideas:First questionBuilt suffix array after prefix and pitch n-sa[i]-ht[i]+1 two pointsSecond questionTwo-point judgment is the number of repetitionsHow to judge, find it, sweep ht down, sum+= it with K.Attention is equal to plus one kind of various pits dad detailsDie..//by Siriusren#include using namespacestd;Const intn=1000050;intn,cnta[n],cntb[n],a[n],b[n],rk[n],sa[n],tsa[n],ht[n],t,k;Long LongSum[n],sum1[n];CharS[n];voidSA () { for(intI=1; i; f
OutputI0O7SJHINTThe length of the data string for 100% does not exceed 100000.The first twice times and then constructs the suffix array,those that meet the conditions are those +n-1 points in SA that are 1#include 2#include 3#include 4#include 5#include 6 7 #defineN 2000078 using namespacestd;9InlineintRead ()Ten { One intx=0, f=1;CharCh=GetChar (); A while(ch'0'|| Ch>'9'){if(ch=='-') f=-1; ch=GetChar ();} - while(ch>='0'ch'9') {x= (x3) + (x1) +ch-'0'; ch=GetChar ();} - retur
all the same: take the small side of the same, all the same will be taken at random.The process of comparison can be violent, or it can be a suffix array.Common Greedy Code:#include #include#include#includeusing namespacestd;Const intmaxn= .;CharC[MAXN];BOOLLeft (intLintR) { while(l1) { if(c[l]!=C[r])returnc[l]C[r]; L++; r--; } return true;}intMain () {intn,cnt; scanf ("%d",N); for(intI=1; iC[i]; intL=1, R=n; Cnt=0; while(lR) { if(Left (l,r)) cout]; Elsecout]; CNT++; if(c
bit of attention, the dictionary ordering note the starting position of the same substring order, its order is the reverse of the enumeration order. In other words, we avoid falling into another hole when we are bypassing a pit.Finally, HBW mentions a method of optimizing the random string suffix array to O (n), and when the rank array has a maximum value of n, it simply break off, seemingly a simple and useful optimization#include #include#include#include#includeusing namespacestd;#defineMAXN
appears in a string that exceeds m (can be crossed), without output none, with the output length, and the last occurrence.Ideas:Find the suffix array, binary length, get the length, as for the last position, need to enumerate each position, that is greater than mid ht[i], corresponding to the sa[i], and sa[i-1].#include #include#include#include#include#includestring>#includeusing namespacestd;Const intmaxn=40010;CharCH[MAXN];intm;intMaxintXintY) {if(x>y)returnXreturny;}structsa{intRANK[MAXN],SA
"bzoj3238" [Ahoi2013] Difference descriptionInputOne line, a string sOutputA row, an integer that represents the value evaluatedSample InputCacaoSample Output WuExercisesWhat is the LCP of any two strings, just asA, b so if A==b is Len (a)Otherwise set sa[a]1#include 2#include 3#include 4#include 5#include 6 7 #defineN 5000078 #definell Long Long9 using namespacestd;TenInlineintRead () One { A intx=0, f=1;CharCh=GetChar (); - while(ch'0'|| Ch>'9'){if(ch=='-') f=-1; ch=GetChar ();} -
Method for installing the R language package, r Language
How to install the R package:
1. Online Installation
On the R console, enter install. packages ("TSA") # install TSA
Install. packages ("TSA", contriburl = "url", dependencies = TRUE) # install TSA
2. Manual installation (offline installation)
In Wi
1. About this article When transmitting information using the TCP (class TcpClient), UDP (class UdpClient) protocol under C #, you need to convert the information to an array of type byte to send. This article implements two conversions of object and byte arrays and a way to convert a file to a byte array. Data of the underlying type, which can be converted using functions in the Bitconverter class. 2.object and byte[] conversion: Serialization and deserialization using IFormatter serialize and
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