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Asp.net+ajax text file static paging implementation code _AJAX related

StreamReader (This.txtpath); String line; int count = 0; while (line = Sr. ReadLine ())!= null) { Line + + "fuck"; count++; } return count; } public string readtxttohtml () { String line;//one line of text int ptr = 0;//row count int TTP = maximum number of pages after paging 1;// StreamReader sr = new StreamReader (Txtpath); String htmlstr = "";//for storing HTML code Htmlstr = "#" + TTP

UNIX host Security Management System

subject (MA): connects to the database on the same host as the database and CGI programs running on the WEB server of the local machine through socket, and accesses the database at the same time, communicate with each TSA through socket. Receive configuration modifications sent by CGI, distribute the modified configuration files in the database to TSA, receive data, data requests, and alarms sent by

CSU-1632 repeated substrings[suffix array to find the number of substrings that occur repeatedly]

Evaluation Address: https://cn.vjudge.net/problem/CSU-1632Descriptionin the string, all occurrences of at least 2 number of sub-strings of the secondInputfirst act an integer T (t represents the number of use case groups, with each group of use cases occupying a length of 100000 the stringOutputFor each set of use cases, output the number of substrings that appear at least two times in the stringSample Input3AabaabAaaaaAaAaASample Output545SolutionAns=sum ( max (height (i)-height (i-1), 0) )#inc

1500 suffix sort

output is 3, 1, 4, 2.Category labelsTags Click here to expandSuffix Tree Group tree structure//suffix array template title#include #includeusing namespacestd;Const intn=1e5+7;intLen,maxx,sa[n],tsa[n],rank[n],trank[n],c[n];CharS[n];voidDA () {intp; Memset (c,0,sizeofc); maxx= the; for(intI=1; i; for(intI=2; i1]; for(inti=len;i;i--) sa[c[rank[i]]--]=i; trank[sa[1]]=p=1; for(intI=2; i){ if(rank[sa[i]]!=rank[sa[i-1]]) p++; Trank[sa[i]]=Q; }

Suffix array two • Repeat Melody 2

#includestring>#includeSet>#include#include#include#include#include#include#defineRep (I,m,n) for (i=m;i#defineRSP (It,s) for (Set#defineMoD 1000000007#defineINF 0x3f3f3f3f#defineVI vector#definePB Push_back#defineMP Make_pair#defineFi first#defineSe Second#definell Long Long#definePi ACOs (-1.0)#definePII pair#defineLson L, Mid, Ls[rt]#defineRson mid+1, R, Rs[rt]#defineSYS system ("pause")#defineFreopen freopen ("In.txt", "R", stdin)Const intmaxn=1e5+Ten;using namespacestd;ll gcd (ll p,ll q) {r

Bzoj 3998 suffix Array

Ideas:First questionBuilt suffix array after prefix and pitch n-sa[i]-ht[i]+1 two pointsSecond questionTwo-point judgment is the number of repetitionsHow to judge, find it, sweep ht down, sum+= it with K.Attention is equal to plus one kind of various pits dad detailsDie..//by Siriusren#include using namespacestd;Const intn=1000050;intn,cnta[n],cntb[n],a[n],b[n],rk[n],sa[n],tsa[n],ht[n],t,k;Long LongSum[n],sum1[n];CharS[n];voidSA () { for(intI=1; i; f

[JSOI2007] character encryption cipher SA

OutputI0O7SJHINTThe length of the data string for 100% does not exceed 100000.The first twice times and then constructs the suffix array,those that meet the conditions are those +n-1 points in SA that are 1#include 2#include 3#include 4#include 5#include 6 7 #defineN 2000078 using namespacestd;9InlineintRead ()Ten { One intx=0, f=1;CharCh=GetChar (); A while(ch'0'|| Ch>'9'){if(ch=='-') f=-1; ch=GetChar ();} - while(ch>='0'ch'9') {x= (x3) + (x1) +ch-'0'; ch=GetChar ();} - retur

Poj3617:best Cow Line (greedy && suffix array)

all the same: take the small side of the same, all the same will be taken at random.The process of comparison can be violent, or it can be a suffix array.Common Greedy Code:#include #include#include#includeusing namespacestd;Const intmaxn= .;CharC[MAXN];BOOLLeft (intLintR) { while(l1) { if(c[l]!=C[r])returnc[l]C[r]; L++; r--; } return true;}intMain () {intn,cnt; scanf ("%d",N); for(intI=1; iC[i]; intL=1, R=n; Cnt=0; while(lR) { if(Left (l,r)) cout]; Elsecout]; CNT++; if(c

Bzoj 2251: [2010Beijing Wc] Alien Contact suffix array

bit of attention, the dictionary ordering note the starting position of the same substring order, its order is the reverse of the enumeration order. In other words, we avoid falling into another hole when we are bypassing a pit.Finally, HBW mentions a method of optimizing the random string suffix array to O (n), and when the rank array has a maximum value of n, it simply break off, seemingly a simple and useful optimization#include #include#include#include#includeusing namespacestd;#defineMAXN

UVA-10298 suffix Array (viewing only)

'; Ch=getchar ();}returnX*f;}CharSTR[MAXN];intNstructsa{intRANK[MAXN],SA[MAXN],TSA[MAXN],A[MAXN],B[MAXN];intCNTA[MAXN],CNTB[MAXN];intheight[maxn],best[maxn][ A],n;voidGetintnn) {n=nn; Rep (I,0,666) cnta[i]=0; Rep (I,1, n) cnta[str[i]]++; Rep (I,1,666) cnta[i]+=cnta[i-1]; Rrep (I,n,1) Sa[cnta[str[i]]--]=i; rank[sa[1]]=1; Rep (I,2, N) {if(Str[sa[i]]==str[sa[i-1]]) {Rank[sa[i]]=rank[sa[i-1]]; }Else{rank[sa[i]]=1+rank[sa[i-1]]; } } for(intL=1; ran

Ural1517freedom of Choice (suffix array)

[MAXN],A[MAXN],B[MAXN]; intRANK[MAXN],SA[MAXN],TSA[MAXN],HT[MAXN]; voidsort () { for(inti =0; I -; i + +) cnta[i] =0; for(inti =1; I ; for(inti =1; I -; i + +) Cnta[i] + = cnta[i-1]; for(inti = L; I I--) sa[cnta[ch[i]]---] =i; rank[sa[1]] =1; for(inti =2; I ) {Rank[sa[i]]= Rank[sa[i-1]]; if(Ch[sa[i]]! = ch[sa[i-1]]) Rank[sa[i]] + +; } for(intL =1; Rank[sa[l]] 1){ for(inti =0; I 0; for(inti =0; I 0; for(inti =1; I ) {Cnta

HDU-1403 Suffix Array Preliminary

();} while(ch>=' 0 'ch' 9 ') {x=x*Ten+ch-' 0 '; Ch=getchar ();}returnX*f;}CharSTR[MAXN];structsa{intRANK[MAXN],SA[MAXN],TSA[MAXN],A[MAXN],B[MAXN];intCNTA[MAXN],CNTB[MAXN];intheight[maxn],best[maxn][ -],n;//height[i]: CP of Sa[i] and Sa[i-1] voidGet () {N=strlen (str+1); Rep (I,0, -) cnta[i]=0; Rep (I,1, n) cnta[str[i]]++; Rep (I,1, -) cnta[i]+=cnta[i-1]; Rrep (I,n,1) Sa[cnta[str[i]]--]=i; rank[sa[1]]=1; Rep (I,2, N) {if(Str[sa[i]]==str[sa[i-1]]) {

SPOJ705 Distinct substrings (suffix automaton & suffix array)

]=maxlen[p]+1; while(P!ch[p][x]) ch[p][x]=np,p=Fa[p]; if(!p) fa[np]=1; Else { intq=Ch[p][x]; if(maxlen[p]+1==MAXLEN[Q]) fa[np]=Q; Else { intnq=++sz; memcpy (Ch[nq],ch[q],sizeof(Ch[q])); MAXLEN[NQ]=maxlen[p]+1; FA[NQ]=Fa[q]; FA[Q]=fa[np]=NQ; while(pch[p][x]==q) ch[p][x]=nq,p=Fa[p]; } } }}; Sam Sam;intMain () {CharCHR[MAXN]; intt,ans,i,l; scanf ("%d",T); while(t--) {sam.init (); Ans=0; scanf ("%s", CHR); L=strlen (CHR); for(i=0; i'A'); for(i=1; iSam.maxlen[

hdu4080stammering Aliens (suffix array + dichotomy)

appears in a string that exceeds m (can be crossed), without output none, with the output length, and the last occurrence.Ideas:Find the suffix array, binary length, get the length, as for the last position, need to enumerate each position, that is greater than mid ht[i], corresponding to the sa[i], and sa[i-1].#include #include#include#include#include#includestring>#includeusing namespacestd;Const intmaxn=40010;CharCH[MAXN];intm;intMaxintXintY) {if(x>y)returnXreturny;}structsa{intRANK[MAXN],SA

bzoj3238 [Ahoi2013] difference suffix array + monotonic stack

"bzoj3238" [Ahoi2013] Difference descriptionInputOne line, a string sOutputA row, an integer that represents the value evaluatedSample InputCacaoSample Output WuExercisesWhat is the LCP of any two strings, just asA, b so if A==b is Len (a)Otherwise set sa[a]1#include 2#include 3#include 4#include 5#include 6 7 #defineN 5000078 #definell Long Long9 using namespacestd;TenInlineintRead () One { A intx=0, f=1;CharCh=GetChar (); - while(ch'0'|| Ch>'9'){if(ch=='-') f=-1; ch=GetChar ();} -

Method for installing the R language package, r Language

Method for installing the R language package, r Language How to install the R package: 1. Online Installation On the R console, enter install. packages ("TSA") # install TSA Install. packages ("TSA", contriburl = "url", dependencies = TRUE) # install TSA 2. Manual installation (offline installation) In Wi

Tools for turning HTML to PDF--wkhtmltopdf

Zhangzhenhua on 2016/11/1. */public class Pdfsigner {//tsa private signerkeystore signerkeystore; Private Tsaclient tsaclient; Private Pdfsigner () {}/** * * @param tsa_url TSA server address * @param tsa_accnt TSA Account number * @param TSA_PASSW ts A password * @param cert_path certificate path * @param CERT_PASSW Certificate Password */public Pdfsigner

Conversion between C # objects, files, and binary strings (byte arrays)

1. About this article When transmitting information using the TCP (class TcpClient), UDP (class UdpClient) protocol under C #, you need to convert the information to an array of type byte to send. This article implements two conversions of object and byte arrays and a way to convert a file to a byte array. Data of the underlying type, which can be converted using functions in the Bitconverter class. 2.object and byte[] conversion: Serialization and deserialization using IFormatter serialize and

The practice of URAL-1297 suffix Arrays LCP application

EREP (i,u) for (register int i=head[u];~i;i=nxt[i])#define IIN (a) scanf ("%d", a)#define Lin (a) scanf ("%lld", a)#define DIN (a) scanf ("%lf", a)#define S0 (a) scanf ("%s", a)#define S1 (a) scanf ("%s", a+1)#define PRINT (a) printf ("%lld", (ll) a)#define ENTER Putchar ('\n ')#define Blank Putchar (")#define PRINTLN (a) printf ("%lld\n ", (ll) a)#define IOS ios::sync_with_stdio (0)using namespaceStdConst intMAXN =1e5+11;Const intOO =0x3f3f3f3f;Const DoubleEPS =1e-7;typedef Long LongLl;ll Read

POJ-1743 suffix Array Height group

#include #include #include #include #include #include #include #include #include #include #include #define REP (i,j,k) for (register int i=j;i#define RREP (i,j,k) for (register int i=j;i>=k;i--)#define EREP (i,u) for (register int i=head[u];~i;i=nxt[i])#define IIN (a) scanf ("%d", a)#define Lin (a) scanf ("%lld", a)#define DIN (a) scanf ("%lf", a)#define S0 (a) scanf ("%s", a)#define S1 (a) scanf ("%s", a+1)#define PRINT (a) printf ("%lld", (ll) a)#define ENTER Putchar ('\n ')#define Blank Putc

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