wave 2 4 4 mu mimo

$arr= [1, 2,-4, 4, 10,-23, 4,-5, 1]; $max _sum= 0; $sum=0; $new= []; $i= 1; Echo' ; foreach($arr as $key=$value ){ if($sum){ unset($new[$i]); $i++; $sum=$value; }Else{ $sum+=$value; } $new[$i][] =$value; if($max _sum$sum){ $max _arr=$new; $max _sum=$sum; } } Print_r($max _sum

even-numbered and5 6 intnum = 2;//represents an even number between 1-507 8 Do {9 //Implementing Cumulative SummationTen One Anum = num + 2;//the value is added 2 for each execution once to determine the next cyclic condition - -} while( );//repeat loop when value is met betwe

valueSecond, complete the main methodTips: 1, call the custom method, save the method return value in the variable maxscore 2, output variable result1 Public classHelloWorld {2 3 //complete the Main method4 Public Static voidMain (string[] args) {5 6 //Create object, object named Hello7HelloWorld Hello =NewHelloWorld ();8 9 //calling a method and saving the ret

Source: http://www.imooc.com/code/1432The function of continue is to skip the remaining statements in the loop body to perform the next loop.For example, to print all the even numbers between 1--10, use the continue statement to implement the code:Operation Result:TaskImplementation function: Ask for all even numbers between 1 and 10.Implementation of the idea: Define a variable sum to save the cumulative value, define a variable I save 1 to 10 integer, iterate and judge, if I cannot be divisibl

60 years old, then the "middle age", if the ages between 18 to 40 years old, then the "juvenile", 18 years of age, the reminder "childhood"Operation Result:1 Public classHelloWorld {2 Public Static voidMain (string[] args) {3 intAge=25;4 5 if(Age >= 60) {6System.out.println ("Old age");7}Else if(Age >= Age ) { 8System.out.println ("Middle-aged");9}Else if(Age >= Age ) {TenSystem.out.println ("juvenile"); One}Else { ASyst

function for the entire hit-wave effect. 123456789101112131415161718192021222324252627282930313233343536 function rippleAnimation(event, timing) {var tl = new TimelineMax();x = event.offsetX,y = event.offsetY,w = event.target.offsetWidth,h = event.target.offsetHeight,offsetX = Math.abs( (w / 2) - x ),offsetY = Math.abs( (h / 2) - y ),deltaX = (w

Turn: From the graphic TCP/IP P204The three-time handshake and four-wave status transition diagram are as follows:, because the second handshake receiver sends the syn+ack signal so the handshake only used three times, waving because the receiver ACK and fin two times, so wave needs four times .Finally, the receiving end needs a time_wait state, and if the last ACK sent by the TCP client is lost, it will be

=" Http://s5.51cto.com/wyfs02/M00/8C/0B/wKiom1hf9eSQPEgEAAFHAE3MyJs193.png-wh_500x0-wm_3 -wmp_4-s_1975253060.png "style=" Float:none; "title=" TCP four times Wave png.png "alt=" wkiom1hf9esqpegeaafhae3myjs193.png-wh_50 "/>(1) Client A sends a fin to turn off customer A to Server B data Transfer (message segment 4).(2) Server B receives this fin, which sends back

error "Scenario 2"Three, 4 wave process1, the establishment of a connection requires three handshake, and terminate a connection to go through four handshake, which is caused by the semi-shutdown of TCP (Half-close). The exact process is shown. [1]Termination of TCP connections(1) An application process first calls close, which is said to perform "active close"

TCP Connection Client state transition processClosed-->syn_sent-->established--> fin_wait1-->fin_wait2-->time_wait-->closedTCP connection Service side state transition processClosed-->listen-->syn_recvd-->established-->close_wait-->lask_ack-->closedWhy is the TCP connection 3 handshake, disconnect to 4 times wave?Because when the TCP disconnects, the client sends Fin=1 's disconnect request to the server (t

= ' #tablelist '; } if(!$ ('. Shade '). Get (0) {$ (DOM). Append (div); }}//Unmute MaskfunctionRemoveshade () {$ ('. Shade '). Remove ();View Code444//Get current Timefunctiongetnowformatdate () {varDate =NewDate (); varSeperator1 = "-"; varSeperator2 = ":"; varmonth = Date.getmonth () + 1; varStrdate =date.getdate (); if(Month >= 1 month ) {Month= "0" +month; } if(strdate >= 0 strdate ) {strdate= "0" +strdate; } varcurrentdate = date.getfullyear () + seperator1 + month + Seperator1 +

Three-time handshake for TCP connectionsFirst handshake: The client sends a SYN packet (SYN=J) to the server and enters the Syn_send state, waiting for the server to confirm;( The client asks the server: Do you love me? )Second handshake: The server receives the SYN packet, it must confirm the customer's SYN (ACK=J+1), and also send itself a SYN packet (syn=k), that is, the Syn+ack packet, when the server enters the SYN_RECV state;( Server Answer: I love you, you love me too? )Third handshake:

Opencv experiences (1) The second chapter of learning opencv mainly introduces some common and interesting functions and data types, so that students at the beginning are more interested in image processing, although I do not understand the internal experiment of the function and the meaning of some defined constants, I am still very happy after learning Chapter 2. At least I know some basics of image processing, such as contour processing; Knowledge

#!/usr/bin/env python# Coding:utf-8Import Redef Dealwith (Express): Express.replace ('+-','-') Express.replace ('--','+') returnexpressdef Col_suanshu (exp):if '/' inchexp:a,b= Exp.split ('/') returnStrfloat(a)/float(b))if '*' inchexp:a,b= Exp.split ('*') returnStrfloat(a) *float(b) def get_no_barcate (Express): Express=express.strip ('()') Print ('>>>', Express) whileTrue:ret= Re.search ("-?\d+\.? \d*[*/]-?\d+\.? \d*", Express)ifRet:res=Col_suanshu (Ret.group ()) Express= Ex

public static void Main (string[] args){int m = 19;int n = 2;m = Recursionmult (M, n);Recursiondivision (M, n);Testm = 35;n = 4;Console.WriteLine ("\nm=" + M + ", n=" + N);m = Recursionmult (M, n);Recursiondivision (M, n);m = 40;n = 5;Console.WriteLine ("\nm=" + M + ", n=" + N);m = Recursionmult (M, n);Recursiondivision (M, n);m = 21;n = 1;Console.WriteLine ("\nm=" + M + ", n=" + N);m = Recursionmult (M, n)

Summary:Ordinary BST does not guarantee a good performance after multiple operations. So we need a BST, yes. The cost of each insertion and search is a logarithmic function of the large size of the tree. The 2-3-4 tree is a kind of BST that maintains balance.2-3-4 Tree IntroductionTo ensure that BST is balanced, we nee

Can I upgrade ios8.2 to iPad 2/3/4?The ios8.2 system supports the upgrade of ios8.2 for ipad 2 for iPad 3 for iPad miniiPad 4. The details are as follows:IPad 4IPad 4 (generation model A1458) WIFI (iPad3, 4)IPad

47. Innovation workshop (algorithm ):Returns the longest descending subsequence of an array, for example, {9, 4, 3, 2, 5, 3, 2,4,3, 2} Idea: Dynamic Planning Calculates the longest descending subsequence of the sequence of the current number. Each time you look for the longest child sequence, scan the child sequence obtained before it, and the first number is sm

Package com; public class test {public static void main (string [] ARGs) {system. out. println (getsteps1 (); system. out. println (">>>>>>>>>>>>>>>>>>>>>>>>>>>>"); system. out. println (test. getsteps (); system. out. println (">>>>>>>>>>>>>>>>>>>>>>>>>>>> ");} public static int getsteps () {// use the minimum public multiple to reduce the number of traversal times. Int I = 1; int step = 2; Boolean maxstep = false; while (true) {system. Out. Print ("

Using formula (n-1) 3=N3-3n2+ 3n-1 Set S3 =13+ 23+ 33+ 43+... + N3 And S2 =12+ 22+ 32+ 42+... + N2 And S1 = 1 + 2 + 3 + 4 +... + n D: S3-3S2 + 3s1-n = (1-1) 3+(2-1) 3 +(3-1) 3+ (4-1) 3+... +(N-1) 3= S3-N3 Therefore, 3S2 = 3s1 + N3-N Bring S1 = n (n + 1)/2 to the u