zebra piggy bank

Problem description Before ACM can do anything, abudget must be prepared and the necessary financial support obtained. The mainincome for this action comes from irreversibly bound money (IBM). The ideabehind is simple. Whenever someACM member has any small money, he takes allthe coins and throws them into a piggy-bank. you know that this process isirreversible, the coins cannot be removed without breaking t

Piggy-bank Time limit:1000 ms Memory limit:32768kb 64bit Io format:% I64d % i64usubmit status DescriptionBefore ACM can do anything, a budget must be prepared and the necessary financial support obtained. the main income for this action comes from irreversibly bound money (IBM ). the idea behind is simple. whenever some ACM member has any small money, he takes all the coins and throws them into a

DescriptionBefore ACM can do anything, a budget must be prepared and the necessary financial support obtained. the main income for this action comes from irreversibly bound money (IBM ). the idea behind is simple. whenever some ACM member has any small money, he takes all the coins and throws them into a piggy-bank. you know that this process is irreversible, the coins cannot be removed without breaking the

Problem description Before ACM can do anything, a budget must be prepared and the necessary financial support obtained. the main income for this action comes from irreversibly bound money (IBM ). the idea behind is simple. whenever some ACM member has any small money, he takesAll the coins and throws them into a piggy-bank. you know that this process is irreversible, the coins cannot be removed without brea

Description Before ACM can do anything, a budget must be prepared and the necessary financialSupport obtained. the main income for this action comes from irreversibly bound money (IBM ). the idea behind is simple. whenever some ACM member has any small money, he takes all the coins and throws them into a piggy-bank. you know that this process is irreversible,The coins cannot be removed without breaking the

Problem Descriptionbefore ACM can do anything, a budget must is prepared and the necessary financial support obtained. The main income for this action comes from irreversibly Bound money (IBM). The idea behind are simple. Whenever some ACM member have any small money, he takes all the coins and throws them into a piggy-bank. You know it is irreversible and the coins cannot be removed without breaking the pi

http://acm.hdu.edu.cn/showproblem.php?pid=1114 Test instructions: The piggy bank can put some small money into it, but it doesn't know how much money is in it after a long time, unless you break it. Now given the weight of the empty jar and the maximum capacity, and then give the value and weight of each coin, we have to confirm the minimum amount of money in the jar without breaking it. Idea: very close t

Test instructions: To a piggy store, known empty piggy tank and the quality of the piggy store with coins. Then gives the quality and value of the n coins. Ask the minimum amount of money in the Piggy store. Solution: Complete backpack. Note to initialize the INF to exactly full, if the result is INF, the output is imp

Description: The weight of a heap of coins is m ( Analysis: It can be seen that this question is the deformation of the 01 backpack problem, that is 1. Each item has an unlimited number 2. The entire backpack must be filled. That is, the 01 backpack with two restrictions. The most common method I use does not affect the sorting of items. /*Zju2014 piggy-bank*/ # Include # Include # Define n 501# Define M 10

Poj 1384 piggy-Bank (full backpack) Http://poj.org/problem? Id = 1384 Question: There are now N types of coins, each of which has a specific weight cost [I] grams and its corresponding value Val [I]. each coin can be used infinitely. it is known that the total weight of all coins in a piggy bank is exactly M grams. How

Link: http://acm.hdu.edu.cn/showproblem.php? PID = 1, 1114====================================, Give you the weight of the empty piggy bank, the weight of the piggy bank, and the value and weight of the coin, let you estimate the minimum value of money in the piggy

Well.. Recently practicing the basic DPThis problem is quite simple (haha), but I just want to say that there is a detail here.First Test instructions:There is a T-set sample, and then give the start weight of the piggy bank e, end the weight f (that is, when it is full of change), and then give you a number n, which means that there are now n kinds of coins.Then the next n lines, each line has two numbers

Life is like a piggy bank, every effort we put into it will give back to us one day ...Exelis (ex. ITT) ENVI v5.3 IDL v8.5 LiDAR v5.3 x64 Complete Remote sensing image processing platformASPEN Aspenone V8.0 Chemical process simulation software send 8G learning materialsAutodesk Autocad Plant 3dPID 20,133-D factory Design full-featured in English and ChineseAVEVA PDMS 12.0 SP6 support Win7 3264 send 11G lear

Title: http://www.spoj.com/problems/PIGBANK/Simple knapsack problem.#include #include#defineINF 1000000005intew,fw,n,i,j,t,m;intv[505],w[505],f[10005];intMinintAintb) {returnAa:b;}intMain () {scanf ("%d",t); while(t--) {scanf ("%d%d",ew,FW); scanf ("%d",N); for(i=1; i) scanf ("%d%d",v[i],W[i]); for(i=1; i) F[i]=INF; f[0]=0; for(i=1; i) for(j=w[i];j) F[j]=min (f[j],f[j-w[i]]+V[i]); if(F[fw-ew]==inf) printf ("This is impossible.\n"); Elseprintf"The minimum amount of money in the

http://poj.org/problem?id=1384Test instructions: Give the empty and full weight of a savings tankand give the value and weight of the N-type coins.What is the minimum value of satisfying a jar when it is filled?Ideas:If(DP[J]>DP [J-w [i]]+v [i]) DP[j]=DP[J-W[i] ]+v[i]; #include #include#include#include#includeusing namespacestd;intMain () {inte,f; intn,t; inti,j,k; intinf=1000000000; intv[ +],w[ +]; intdp[10000+ -]; scanf ("%d",t); while(t--) {scanf ("%d%d",e,f); F=f-e; scanf ("%

In fact, this problem in the winter vacation self-study training game did, but feel the understanding now and then really not the same, a freshman half a year later, changed so much, we are in progress, a back then came out so far ...Okay, it's a simple question, a backpack, a sign on the line.#include #include#include#include#include#include#includeusing namespacestd;Long Longdp[10010];intmoney[10010], weight[10010];intMain () {intT; scanf ("%d",t); while(t--) { intw1,w2; scanf ("%d%

The first thought of the method is very complex, with a try to hold the mentality submitted, really tleThen search, is a complete backpack, a lot of do not remember, re-review a bit.The solution of the first annotation is tle, the second and the third are feasible, but the ideas are different.#include HDU 1114 Piggy-bank

Maximum value: The backpack must be filled accurately, when except dp[0] 0 other DP[1..V] are set to-∞Minimum value: Requires just full pack, then at initialization except Dp[0] 0 other DP[1..V] are set to ∞ Precautions : The topic requires "Exactly full" , so when initializing. Other than dp[0] assignment to zero dp[i] are assigned a value of +∞. Because the topic is to find the minimum value. If the maximum value is calculated, then Dp[i] is assigned a value of-∞ , and if there is no qualific

This question is about money-saving pig, empty quality W1, money quality W2, and then the value and weight of various types of money, asking how much money a piggy bank needs to store is a classic topic for getting started with a full backpack. Now I don't fully understand it. Let's talk about my understanding. The full backpack is to put every kind of data in it as much as possible, and every kind of data