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2015-11-13 14:44:44,681 ERROR [main]: Datanucleus.datastore (Log4JLogger.java:error ())-an exception is thrown while Adding/validating Class (es): Specified key was too long; Max key length is bytesCom.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException:Specified key was too long; Max key length is bytesAt Sun.reflect.GeneratedConstructorAccessor21.newInstance (Unknown Source)At Sun.reflect.DelegatingCons

larger than the value of this definition, then replace this position and then continue traversing the end of the loop to output this value is the maximum value or the smallest value such asDouble max = score[0]; for (i = 0; i This code is to ask for an extremum and the largest one.Find The function is to query the current array for the value you need, as if you were going to a place to find someone.The lookup uses the Boolean variable becaus

Cache-control max-age=0 Cache-control no-cache-forces each request to be sent directly to the source server, without the checksum of the locally cached version. This is useful for verifying the authentication application (which can be used in conjunction with public) or for applications that use the latest data (all the benefits of using the cache at the expense of)Pragma when "No-cache" appears in the request message, the application should push the

valid for the current shell, in order to take effect anywhere, in addition to executing the ULIMIT command is to change the configuration file, that is, change the maximum number of File open global settings, by editing/etc/security/ limits.conf file, add the following two lines to restart the system to take effect . ：* Hard nofile 65535* soft nofile 65535where "*" means that all users are in effect, after rebooting, executing ulimit-n anywhere will show 65535.Some commands related to opening n

This tutorial is to introduce the use of PS 3D Max production of three-dimensional triple-Ty stereo word effect, tutorial production of the effect is very good, like friends can follow the tutorial together to see! Text version, load selection-build path then file-Export-path to illustrator OK Save As text path Continue text generation path, select-Modify-Extend-20 pixel get new

don't know. "IIS Max concurrent worker threads" there is no place to set, know friends can give me a message, thank youSo now the problem is, the maximum number of concurrent connections affects the number of queues, so is there any progress affecting the number of queued settings? Yes: Queue LengthQueue Length Assuming that the maximum number of connections is set to 100,1000 a concurrent connection request comes up, first 900 is returned dire

First, prefaceSecond, the question 485 Max consecutive Ones Given a binary array, find the maximum number of consecutive 1s in this array. Example 1: Input: [1,1,0,1,1,1] output:3 explanation:the First and digits or the last three digits is consecutive 1s. The maximum number of consecutive 1s is 3. Note: The input array would be only contain and 0 1 . The length of input array is a positive integer and would not

Label:Error executing nova-manage DB sync: 2012-03-24 14:07:01 CRITICAL Nova [-] (Operationalerror) (1071, ' Specified key was too long; Max key length is $ bytes ' ) ' \ncreate TABLE user_project_association (\n\tcreated_at datetime, \n\tupdated_at datetime, \n\tdeleted_at datetime, \ n\tdeleted BOOL, \n\tuser_id varchar (255) NOT NULL, \n\tproject_id varchar (255) is not NULL, \n\tprimary KEY (user_id, Projec t_id), \n\tcheck (deleted in (0, 1)), \n

A recent use of statspack on a customer's 8i production library found an error in alert:Mon June 16 13:17:52 2014Errors in FILE/ORACLE/8.1.7/ADMIN/PROD/BDUMP/SNP0_96626_PROD.TRC:Ora-12012:error on Auto execute of Job 304Ora-01631:max # Extents (505) reached in table Perfstat. Stats$sql_summaryOra-06512:at "Perfstat. Statspack ", line 978Ora-06512:at "Perfstat. Statspack ", line 1612Ora-06512:at "Perfstat. Statspack ", line 71Ora-06512:at Line 1Mon Jun

Tags: union tin max no article Department net Ora logSELECT * FROM(select T.*, Row_number () over (partition by Group field order by sort field desc) rnFrom TableName t)where rn=1 Row_number () over (PARTITION by COL1 ORDER by COL2) indicates that, according to COL1 grouping, sorting is based on COL2 within the grouping, and the value computed by this function represents the sequential number of each set of internally ordered (contiguous unique withi

Tags: created nbsp number of meanings Group benefits URL Student TranslationWrite in frontYesterday went to Tsing Lung Gorge to play a day, tired and dog-like. But fortunately, finally counted on the top of the mountain, but also count to Beijing after the conquest of the third mountain. Here also nagging, do the development of this line, nothing or more sports, on their own or very good, nonsense less, or toss toss the SQL statement it.Series ArticlesMySQL CREATE database, create data tableMySQ

Tags: design img Create scale var max null arch characterToday design table structure, add a few fields, the results of the errorThe situation was that there would have been 50 fields in the table, and this time the need to add 18 fields, I set all 18 fields to Vachar 255. The result was an error. I don't understand why.This mistake with Baidu translated out is "the line is too big." The largest line in the scale. Except blobs,65535. ”What the hell is

Issue create Table:specified Key was too long;Max key length is 767 bytes reason database table is UTF8 encoded, where varchar (255) column has a unique key index and MySQL by default the index of a single column cannot exceed 767 bits (different versions may differ)So UTF8 character encoding, 255*3 byte exceeds the limit resolution 1 using INNODB engine, 2 enable Innodb_large_prefix option, extend constraint to 3072byte;3 re-create database; MY.CNF c

Common functionsAVG (average) COUNT (count) MAX (maximum value) MIN (minimum value) SUM SumThe syntax for applying a function is:Select from "table name";For example, if we were to find the sum of the Sales fields from our demo table,SELECT SUM from Store_information;Results:27502750 represents the sum of all Sales fields: 1500 + 250 + 300 + 700.In addition to the use of functions, SQL can also do simple mathematical operations, such as add (+) and m

Tag:codeinuxnumberlinu Connection Options ota system newline du [-ABCDHHKLMSSX] [-l du -h --max-depth=1 /pathLinux View each folder size command du-h--max-depth=1

Categories: Unity, C #, VS2015Date Created: 2016-04-05 first, three-dimensional software introductionDue to the relatively weak modeling function of the game engine itself, both professional and freedom can not be compared with the professional three-dimensional software, so most of the game model, animation and other resources are through the professional three-dimensional software to make, after the completion of the production and then import it into unity use on the line.Unity supports almos

1, summary system limitations are:/proc/sys/kernel/pid_max #查系统支持的最大线程数, usually very large, equivalent to the theoretical value/proc/sys/kernel/thread-maxmax_user_process (ulimit-u) #系统限制某用户下最多可以运行多少进程或线程/proc/sys/vm/max_map_countHardware Memory Size2. The Java Virtual machine itself limits:-xms #intial java heap Size-xmx #maximum java heap Size-XSS #the stack size for each thread3. Query the current number of threads or processes of a programpstree-p ' ps-e | grep java | awk ' {print $} ' | Wc

because we use 0 as the end sign for all numbers, and of course we can change to something else. The statement "incl%edi" means adding 1 to the value in the%edi register so that the next instruction ("movl data_items (,%edi,4),%eax" ) can get the address of the next number, the statement "cmpl%EBX,%eax" to compare the size of two numbers, the next statement "jle Start_loop" Indicates that if the previous comparison result is a value in%eax less than or equal to the value in%EBX, the program jum

Test instructions: There are M machines, there are n tasks. Each task must be done in SI or later, completed before EI or, the completion task must process the PI time unit. where each task can work on any (idle) machine, each machine can only work one task at a time, and each task can only be worked by one machine at a time, and the task is half-interrupted and taken to other machines. Can you finish the task within the stipulated time?The map is simply classic. Just beginning to see is also a

, the number of times to restart the machine can be minimized.The task is to calculate the minimum number of times. Initially, both machines are running in mode No. 0.Ideas:Turn each task into a line, assuming that task I processes a a[x] point on a machine, on a B machine for b[y] points, connect a[x] and B[y],Cover all edges with the fewest points in a machine and B machine (all tasks are done in a minimal mode).This is the minimum point coverage problem, according to the K?nig theorem (the ma