2 5 x2 5 prints

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Docker Learning Notes (5-2) configuration and operation of the Docker daemon

Learning Goals:To view the running status of the Docker daemonStart, stop, restart the Docker daemonStartup options for the Docker daemonModify and view the startup options for the Docker daemon1. # View Docker running statusMethod One: Ps-ef | grep javaMethod Two: sudo status dockerBack to: Docker start/running, Process 18479Returns the process number that is currently started and is running while returning2.# Start, stop, restart the Docker daemonsudo service docker startsudo service docker st

Compiler error message: CS1617: Option "6" is not valid for/langversion; must be ISO-1, ISO-2, 3, 4, 5, or Default

When you upgrade the. NET Framework from version 4.5.0 to 4.5.2 with VS2015, the following error follows: Description: An error occurred during the compilation of resources required to provide services to the request. Please check the following specific error details and modify the source code appropriately.Compiler error message: CS1617: Option "6" is not valid for/langversion; must be ISO-1, ISO-2, 3, 4, 5

2016/5/8 Database 2

Database integrity: Reliable + accurate = integrityDatabase integrity: Entities: Ensure that each row has a data field: A column of data references: Guaranteed numbering customization: ensure your own rulesPrimary key: Ensures that each row of Entity data can be differentiated without identical dataConstraint: Name format primary key set Primary keyUNIQUE constraint: Column values can only be unique nullable can be multiple unique names format unique NOT NULLNon-empty constraint: NOT null (canno

C ++ shortcut tutorial-Chapter 5-array and string (Part 2)

// -- C ++ shortcut tutorial -- Chapter 5 -- array and string (Part 2)// -- Chapter 5 -- array and string// -- 11/11/2005 Friday// -- Computer lab// -- Liwei // -- Program #17 two-dimensional array# Include Using namespace STD;Void F1 (); Int main (){F1 ();F1 ();Cout // Getchar ();Return 0;} Void F1 (){Char s [80] = "this is a test./N ";Cout Strcpy (S, "changed.

Huawei Machine Test-Choose 2 people from 5 persons as etiquette

To choose 2 people from 5 persons as a courtesy, each of whom has a height range of 160-190, requiring a minimum height difference of 2 persons(If the difference is the same, select the highest of the two) to output the height of two people in ascending order.Sample input:161 189 167 172 188Sample output:188 189#include The test data is: 161 189 167 172 188The re

Recently looking at ASP. NET 5, about the official implementation of the OAuth 2 package

with the the official implementation of the OAuth 2 package, extended to the domestic more convenient (lazy to find a third party). Official implementation of the authorization and verification package:https://github.com/aspnet/Security Based on this, I've expanded several domestic OAuth 2 authorizations:moreauthentication PS: Because of its own official package is still in development, so a lot of things

MYSQL Basic Learning Note Overview with basic data type: integer: 1) TINYINT 2) SMALLINT 3) Mediumint 4) INT 5) BIGINT Main is the size of the difference chart floating point: command

One, the CMD frequently uses the MySQL related commandmysql-d,--database=name//Open Database--delimiter=name//Specify delimiter-H,--host=name//server name-P,--password[=name]//password-P,--Port[=name]//Port number--prompt==name//Setup prompt-U,--user=name//username-V,--version//output versionAble to use combination, such as input-uusernam-ppassword login username for usrname password for password accountII. Basic data typesIntegral type:1) TINYINT 2)

How does php arrange and solve the problem in the order of 1, 2, 3, or 4, 5?

Php is arranged in the order of 1, 2, 3, or 4, 5. if there is a string of numbers 1, 2, 3, 7, 8, how can we divide 123 into a group, let's divide 7, 8 into another group, namely, separating 1, 2, 3 and 7.8 ------ solution ---------------------- $ s nbsp; 1, 2, 3, 7, 8; $ ar

Introduction to algorithms-5. Chapter 6 (2) priority queue

heapincreasekey (int * a, int I, int key) { If (Key Cout A [I] = key; While (I> 1 a [I/2] { Int temp = a [I]; A [I] = a [I/2]; A [I/2] = temp; I/= 2; } } // Insert an element with the key keyword Void MaxHeapInsert (int * a, int key, int heapsize) { ++ Heapsize; A [heapsize] =-INF; HeapIncreaseKey (a, heapsize, key

[Asp.net 5] Options-configuration file (2), asp. netoptions-

[Asp.net 5] Options-configuration file (2), asp. netoptions- I wrote an article about Options a long time ago. I opened it again in 2016 and found many changes. Added new classes and OptionMonitor-related classes. Today we will introduce the so-called new version. The old version of the portal ([Asp.net 5] Options-configuration after the configuration file ). Fir

Introduction to Programming--c Language 4th week programming exercises 2 read integers (5 points)

Topic content:Your program is going to read an integer in the range [ -100000,100000]. Then, use Hanyu Pinyin to output each bit of this integer.If you enter 1234, the output:Yi er san siNote that there is a space between the pinyin for each word, but there is no space behind the last word. When a negative number is encountered, add "fu" at the beginning of the output, such as the 2341 output as:Fu er san si yiInput format:An integer that ranges from [ -100000,100000].Output format:The pinyin th

Huawei interview questions: 1 cent, 2 cent, and 5 cent coins, which constitute a single angle. How many combinations are there. Java source code

Public class jiaofen {Public static void main (string ARGs []){Int I, J, K;Int n = 0;For (I = 0; I {For (j = 0; j {For (k = 0; k {N ++;If (10 = 5 * I + 2 * j + k) // note that "="System. Out. println ("1 cent number of coins:" + K + ";" +"2 cent coin count:" + J +"; The number of 5 cent coins is:" + I );}}}System. Out.

Sdut 5-2 constructor of the derived class

5-2 constructor of the derived class Time Limit: 1000 ms memory limit: 65536 k any questions? Click Here ^_^ Description Through this exercise, you can understand the definition and usage of the derived class constructor. Define a base class person with three protected data members: Name (char * type), gender sex (char type), age (INT type ); A constructor is used to initialize data members. A member fu

Week five "project-triangular prototypes 2, 3, 4, 5"

2) on the basis of the above program, redefine the Triangle class, where the logic is particularly simple set and get member functions, to be processed as inline member functions, defined directly within the class.3) Design The constructor of the Triangle class with parameters, namely triangle (double x, double y, double z), and the three-side length is given directly by the argument at invocation, so that the object can be initialized at the time of

Find the sum of the first 5 items of SN=A+AA+AAA+AAAA+AAAAA, where a is a number, for example: 2+22+222+2222+22222

/* For the sum of the first 5 items of sn = a + AA + AAA + AAAA + AAAAA, where A is a number, for example: 2 + 22 + 222 + 2222 + 22222*/#include int main (){int i = 0;int a = 0;int sum = 0;int num=0;scanf ("%d", num);for (i = 0; i {A = a * ten + num;sum = sum + A;}printf ("%d", sum);return 0;}Output Result:224690Press any key to continueThis article is from the "51cto" blog, be sure to keep this source http

WCF Series 5-day crash-the second day of binding use (2)

Original: WCF Series 5-day crash-the second day of binding use (2)To undertake the previous chapter, today, the application of MSMQ in actual combat projects. As we all know, to prevent the loss of orders, we are using order over MSMQ.The benefits of MSMQ are personally considered: innate asynchronous message sending and natural automatic load balancing.Well, look at the application of MSMQ in combat.The fi

[ASP. 5] options-configuration Files (2)

A long time ago, I wrote an article about options, and 2016 opened up a lot of changes. Added new classes, adding optionmonitor related classes. Today is the introduction of this so-called new version.The old version of the portal ([ASP. NET 5] options-configuration file after the configuration).First the previous diagram:* The Green Line is an inheritance relationship, and the Blue Line is an association relationship.We cut the top into

c language; The sum of the first 5 items of sn=a+aa+aaa+aaaa+aaaaa where A is a number for example: 2+22+222+2222+22222

Program:The sum of the first 5 items of sn = a + AA + AAA + AAAA + AAAAA, where A is a number, for example: 2 + 22 + 222 + 2222 + 22222#include int main (){int i = 0;int a = 0;int sum = 0;int num=0;scanf ("%d", num);for (i = 0; i {A = a * ten + num;sum = sum + A;}printf ("%d", sum);return 0;}Results:224690Press any key to continueThis article is from the "Rock Owl" blog, please be sure to keep this source h

Linux boot levels: init 0, 1, 2, 3, 4, 5, 6

Document directory 0: stopped 0: downtime 1: single-user mode, only root for Maintenance 2: multi-user, cannot use net file system3: full multi-user 5: Graphical 4: security mode 6: restart actually, you can view/etc/rc. rc * in d *. d .. Init 0, the corresponding system will run, the program specified in/etc/rc. d/rc0.d. Let's take a look at the name. [Root @ localhost ~] # Ls/etc/rc. d/rc0.d rj1_k35nmb

C language input a 2-5-digit number, remove the number left after the first!

#include int main () {int i;do{printf ("Please enter a 2-5-bit number:");scanf ("%d", i);if (i>9iprintf ("The remainder after the first removal is:%d\n", i%10);else if (i>99iprintf ("The remainder after the first removal is:%d\n", i%100);else if (i>999iprintf ("The remainder after the first removal is:%d\n", i%1000);else if (i>9999iprintf ("The remainder after the first removal is:%d\n", i%10000);else{print

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