2048 cheat

It took me two hours to write in the stupidest way ... The most humble version ...I'm not sure if this logic is right ...#include 　　C Language Character Edition easy 2048

This article mainly introduces the relevant information about the 2048 games written using Javascript. If you need it, you can refer to the recent whim. The project is over. use javascript to write a game and practice it, if the writing is not good, please give your criticism and suggestions. The HTML code is as follows:

Refer to the http://blog.csdn.net/keshuai19940722/article/details/24723417 he started a little small analysis, of course there are questions, it is rare to see the CF question a little long, read for a long time to add YY to get out of the question, But I still haven't introduced the state transition equation, because the question says to move to the beginning, I pushed it backwards, so I was trying a memory-based search, and all the way to the search came across only 0, 2, 4. Check whether the

the addition principle, F (n-2) + f (n-1) methods are used to complete the second step. According to the multiplication principle, the number of wrong sorting of n different elements F (n) = (n-1) [F (n-2) + f (n-1)] (n> 2 ). Supplement: Someone wrote n letters and N envelopes, if all the letters were wrong. Ask how many different situations are there when the wrong envelope is installed for all the messages. When n = 1 and 2, it is easy to get the solution ~, Assuming that F (N-1) and F (N-2)

)); Int N; bool mark; scanf ("% d % * C", N ); Fillbox (n); print (N ); While (true) {char ch; scanf ("% C % * C", Ch); If (CH = 'A') {mark = left (n );} else if (CH = 'D') {mark = right (n);} else if (CH = 'W') {mark = up (n );} else if (CH ='s ') {mark = down (n);} else {continue;} system ("CLS"); printf ("Move: \ n "); print (n); If (! Mark) {continue;} fillbox (n); printf ("fill: \ n"); print (N ); If (isover (N) {printf ("\ n \ Ngame over! \ N "); break;} return 0 ;} /* Method Descriptio

Javascript 2048 games, javascript2048 There is no technical content, but it is used to practice code logic. To ensure the code structure is clear, I write the logic control part in the global variables. The user interface operations are encapsulated in the UI object. This is probably the case. For reference only. Some of my coding styles are too messy at work, so I want to write something that is not so messy .. Copy codeThe Code is as follows:708616

2048 waiting to write Java version

#include int main (){int i,j,n,m;__int64 a[22]={0,0,1,2},s;float b[22];b[2]=0.5;b[3]= (float) 1/3;for (i=4;i{a[i]= (i-1) * (A[i-1]+a[i-2]);S=1;for (j=1;jS*=j;b[i]= (float) a[i]/s;//There is no parentheses here at a[i]/s because it causes errors in the first calculation.}scanf ("%d", n);while (n--){scanf ("%d", m);printf ("%.2f%%\n", b[m]*100);}return 0;}Copyright notice: This article Bo Master original articles, blogs, without consent may not be reproduced. Hangzhou Electric

Tecardsprite (int flag); Random generation of the regular generation of numbers to move upward is generated in the following Private:int Firstx,firsty,endx,endy; Touch point coordinates cardsprite *CARDNUM[4][4]; Create an array object with digital energy 4*4}; Class Cardsprite:public Cocos2d::ccsprite{public: virtual bool init (); static cardsprite* createcardsprite (int numbers,int width,int height,float cardspritex,float CardSpriteY); Create_func (cardsprite); int GetNumber ()

cell is followed by a line-break - if(0= = (I 3)) { thePutchar ('\ n');Bayi } the } the - //read input from keyboard - if(! W2)) { theRead (0, k,3); theS (1, k[(K >> X)%4]); the T (); the } - } the the int theMain (void)94 { the //Uses Stty to clear the screens in preparation for the game theSystem ("Stty Cbreak"); the 98 /*intializes random number generator*/ About Srand ((unsigned) time (NULL)); - 101 T ();102 103 //Game have finished by this point104 //If win, displ

the number of test instances, followed by the C row of data, each line containing an integer n (1Output for each test instance, export the percentage that this occurs, the output of each instance is a row, and the result retains two decimal places (rounded), in the exact format, refer to sample output.Sample Input1 2Sample Output50.00%AUTHORLCY////According to the test instructions, the total number of n=, c= the result of the wrong formula, d=n the whole arrangement; results =c/d; The problem

, representing the number of test instances, followed by the C row of data, each line containing an integer n (1Output for each test instance, export the percentage that this occurs, the output of each instance is a row, and the result retains two decimal places (rounded), in the exact format, refer to sample output.Sample Input12Sample Output50%AuthorlcyThe source recursive Solution topic exercise (for beginner) describes itself. n individual n votes, ask everyone to take the wrong vote method

map,Now we have to add a vector (set) to hold all the blocks.GameScene.h:vectorAnd then. In Init. We created the lattice, and then, with a number block,It's going to produce a random block.Add a method--newnumbertiledThis function is to create a new block:void gamescene::newnumbertiled () {//Create an instance of a number block auto tiled = Numbertiled::create ();//Find a location with several spare int freecount = 16-m_allt Iled.size (); int num = rand ()% freecount;int row = 0,col = 0,count =

This isWritten in C + +, in fact, using the input and output of C + +, the rest is all C contentThe code is detailed, very simple, welcome to learn from and exchange#include 2048 Console Edition

Simple DP. DP [I] [J]: in the position I, the status of decline is J, and the maximum profit is obtained. Enumeration status. If the number X to be added is greater than the minimum number X, the status changes to X. If X is smaller than the smallest, the status is J + X. If X is equal to the smallest value, it is incremented sequentially until the smallest value is greater than X. # Include Zoj-3802-Easy 2048 again

Scroe:HTML+CSS+JS implementation 2048

= Event.gety ( ); Break;case MotionEvent.ACTION_UP:offsetX = Event.getx()-startx;offsety = Event.gety ()-starty;if (Math.Abs (OffsetX) >math.abs (OffsetY)) {if (offsetxImport Android.content.context;import Android.view.gravity;import Android.widget.framelayout;import Android.widget.textview;public class Card extends Framelayout {public Card (context context) {super (context); label = new T Extview (GetContext ()); Label.settextsize (+); Label.setbackgroundcolor (0X33FFFFFF); Label.setgravity (

The code is as follows: If you need source code packaging resources I have uploaded to the resources, you can downloadDownload finished if you feel good please give your praise Yo ProTo change the probability of a 4 occurrence, you can change the value of 0.35. function PRD () {var otable = document.getElementById ("Mytab");var myrows= otable.rows;var Rowno=math.floor (Math.random ());var cellno= math.floor (Math.random ());var itemnum=math.round (Math.random ()-0.35);

Write a more hurried, more simple function, the interface is ugly, the operation of the number of steps should also be optimized.Ultimately, it is to write AI, but it seems not so simple, write a few about the pattern evaluation function, you have to continue to learn ...Left and RIGHT ARROW key operation.Source:Import Java.awt.borderlayout;import java.awt.color;import Java.awt.font;import Java.awt.gridlayout;import Java.awt.event.*;import Java.util.random;import Javax.swing.jframe;import Javax.

1. Capturing keyboard events"2048" The operation of the game mainly depends on the keyboard on the top, bottom, left and right to complete, first we need to capture the keyboard response in the Game.js file event.$ (document). KeyDown (function (event) {switch (event.keycode) {case 37://leftbreak;case 38://upbreak;case 39:// Rightbreak;case 40://downbreak;default:break; }});After the keyboard event is captured, we need to complete the specific game