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Configure the FTP server in MySQL + Proftpd

script under the/etc/rc. d/init. d/directory. The specific content is as follows: M #! /Bin/bashqm # Red sweetheart Forum-red sweetheart Forum * v6 # Startup script for the proftpd FTP server | mf ./Etc/rc. d/init. d/functionsq % Proftpd =/usr/local/sbin/proftpdF 3 Prog = proftpdLD) 7G RETVAL = 0C Start () {| Echo-n $ "Starting $ prog:" 8 aaPtp Daemon $ proftpdwz) RETVAL =$? G * x Echo red sweetheart Forum-red sweetheart Forum ^ re [$ RETVAL-eq 0] touch/var/lock/subsys/proftpdtA6zij Return $

HDU 5095 linearization of the kernel functions in SVM (simulation)

Linearization of the kernel functions in SVM Time Limit: 2000/1000 MS (Java/others) memory limit: 65536/65536 K (Java/Others)Total submission (s): 206 accepted submission (s): 109 Problem descriptionsvm (Support Vector Machine) is an important classification tool, which has a wide range of applications in cluster analysis, community division and so on. SVM the kernel functions used in SVM have functions forms. here we only discuss the function of the Form F (x, y, z) = AX ^ 2 + by ^ 2 + cy ^ 2

Use qemu for System Simulation

. Supported peripheral devices Using qemu as a PC system simulator provides various peripheral devices. The required standard peripherals include hardware video graphics array (VGA) simulators, PS/2 mouse and keyboard, integrated development environment (IDE) hard drives and CD-ROM interfaces, and floppy disk simulation. In addition, qemu includes the ne2000 Peripheral Controller Interconnect (PCI) network adapter, serial port, a large number of sound cards and PCI universal Host Controller Int

Analysis and Comparison of TCO in virtualization solutions

department. CFO may be more concerned about this issue (there are too many things to be concerned about, so gradually improve it ). I think virtualization will help to reduce the number of machines in the IDC room. A 32core server and a 4core server both occupy 4u space. The data center is also very expensive. If the original data center is full, you need to create a new data center. The construction cost is normal for tens of millions, not includin

Tips for checking whether the service starts and kill the process, and then start the process

Tips for checking whether the service starts and kill the process, and then start the process First Check whether the service is started through the process View port [root@mode etc]# netstat -lntActive Internet connections (only servers)Proto Recv-Q Send-Q Local Address Foreign Address State tcp 0 0 0.0.0.0:2049 0.0.0.0:* LISTEN tcp 0 0 0.0.0.0:5666 0.0.0.0:* LISTEN tcp 0 0 0.0.0.0:747 0.0.0.0:* LISTEN tcp 0 0 0.0.0.0:715 0.0.0.0:* LISTEN tcp 0 0 0.0.0.0:111 0.0.0.0:* LISTEN tcp 0 0 0.0.0.0:784

Data center Integrated Wiring is widely used in the court Industry

-Core Optical Fiber in a 4U height, it also provides user-friendly drawer tray management and comprehensive bare fiber fixation and protection functions. The plug-and-play function can be used with the optical fiber pre-Connection System to save on-site construction time. 3) pre-Connection System The pre-connection system adopts the high-density connection mode of factory end-to-end connection and testing. The pre-connection system includes the distri

Linuxlsof command details and use examples (more detailed summary)

@ localhost soft] # Note: When + D is used, all subdirectories and files in the corresponding directory will be listed. Example 4: without the + D option, traverse all the file information in a directory Command: lsof | grep 'test/test3' Output: Copy codeThe code is as follows:[Root @ localhost soft] # lsof | grep 'test/test3'Bash 24941 root cwd DIR 4096 2258872/opt/soft/test/test3Vi 24976 root cwd DIR 4096 2258872/opt/soft/test/test3Vi 24976 root 4u

IBM tower Xeon 12000 yuan preferred for CRM and databases

ServerRAID-7e to provide higher flexibility, the new easy-to-plug-and-Remove SATA model supports a storage system that can be easily maintained without the need to open the server chassis. 2-way tower system, converted to 4U rack server by optional cabinet installation kits Up to two Intel Xeon processors, up to 3.20 GHz ;? Too many ?? Om. c. What is the growth margin? What are the details of the BM file? Why? Why is it a low performance? /P> 2-way

Codeforces 586B Laurenty and Shop

F-laurenty and ShopTime limit:1000MS Memory Limit:262144KB 64bit IO Format:%i64d %i6 4u SubmitStatusPracticecodeforces 586BDescriptionA little boy Laurenty had been playing his favourite game Nota for quite a while and was now very hungry. The boy wants to make sausage and cheese sandwiches, but first, he needs to buy a sausage and some cheese.The town where Laurenty lives in are not large. The houses in it is located in and rows, n houses in each

5M Hong Kong International Bandwidth hosting Server How much is the price of a year? which computer room hosting the most professional

Server hosting important one maintenance, to know the cost of the server hosting a year, we need to understand what the hosting server maintenance and which factors are related, these factors are important factors that affect server hosting costs:Server specification Size: Generally have 1u,2u,4u such, the larger the specification, the higher the cost of hosting.Server power consumption: CPU several hard disks several pieces of memory how many models

Training first day Content brief

Rookie Learning MemoriesLinux Day 1Linux tenet:1. All Documents2. Small, single-use programs3. Connect the program and complete complex tasks together4. Avoid confusing user interfaces5. Configuration data stored in textSmall Knowledge Points:Rack-Mount Servers:Width 19 inches, in U, 1U 2U 3U 4U 5U 7UTypically, the cabinet is a 42U cabinet (height approx. 2 m)Server Hardware--CPUfrequency = FSB x octaveThe higher the frequency the faster the CPUCache:

Codeforces 176B Word Cut (Count DP)

Word CutTime limit:2000MS Memory Limit:262144KB 64bit IO Format:%i64d %i6 4u SubmitStatusPracticecodeforces 176BDescriptionLet ' s consider one interesting word game. In this game you should transform one word into another through special operations. Let's say we have Word W , let's split this word into a non-empty Parts x and y so, that w = xy . Asplitoperation is transforming Word W = xy into word u = yx . For exa

Codeforces 300C--Number theory

A-aTime limit:2000MS Memory Limit:262144KB 64bit IO Format:%i64d %i6 4u SubmitStatusPracticecodeforces 300CDescription Vitaly is a very weird man. He's got and favorite Digits a and b . Vitaly calls a positive integergood, if the decimal representation of this integer o Nly contains Digits a and b . Vitaly calls a good Numberexcellent if the sum of its digits is a good NUMBER. For example, let's say that Vitaly ' s favourite digits is 1

Poj 2096 Collecting Bugs (probability DP for expectation)

C-collecting BugsTime limit:10000MS Memory Limit:64000KB 64bit IO Format:%i64d %i6 4u SubmitStatusDescriptionIvan is fond of collecting. Unlike other people who collect post stamps, coins or other material stuff, he collects software bugs. When Ivan gets a new program, he classifies all possible bugs into n categories. Each day he discovers exactly one bug in the program and adds information about it and its category into a spreadsheet. When he fin

HDU 4268 Alice and Bob greedy STL O (NLOGN)

B-alice and BobTime limit:5000MS Memory Limit:32768KB 64bit IO Format:%i64d %i6 4u DescriptionAlice and Bob ' s game never ends. Today, they introduce a new game.     In this game, both of them has N different rectangular cards respectively. Alice wants to use he cards to cover Bob ' s. The card A can cover the card B if the height of a is not smaller than B and the width of A are not smaller than B. As the best programmer, you is asked to compute

HDU 4435 charge-station () BFS graph theory problem

e-charge-stationTime limit:1000MS Memory Limit:32768KB 64bit IO Format:%i64d %i6 4u Submit Status Practice HDU 4435Appoint Description:DescriptionThere is n cities in M^3 ' s empire. M^3 owns a palace and a car and the palace resides in City 1. One day, she wants-to-travel around all the cities from her palace and finally back to her home. However, her car had limited energy and can only travel by no more than D meters. Before it is run out of the

Vanya and Brackets

Vanya and BracketsTime limit:1000MS Memory Limit:262144KB 64bit IO Format:%i64d %i6 4u SubmitStatusPracticecodeforces 552EDescriptionVanya is doing he maths homework. He has a expression of form, where x1, x2, ..., xn is digits from C8>1to 9, ampersand represents either a plus '+ ' or the multiplication sign ' * '. Vanya needs to add one pair of brackets in this expression so that is maximize the value of the resulting expression. InputThe first l

HDU 1372.Knight Moves

Knight Moves Time limit:1000MS Memory Limit:32768KB 64bit IO Format:%i64d %i6 4u Submit Status Practice HDU 1372 DescriptionA Friend of you doing in the the Traveling Knight problem (TKP) where you were to find the shortest closed tour of Knight moves that visits each square of a given set of n squares on a chessboard exactly once. He thinks the most difficult part of the problem is determining the smallest number of knight moves betwe

Codeforces #319 B-modulo Sum (drawer principle, DP)

B-modulo SumTime limit:2000MS Memory Limit:262144KB 64bit IO Format:%i64d %i6 4u SubmitStatusDescriptionYou are given a sequence of numbers a1, a2, ..., an, and a Number m. Check if it is possible to choose a non-empty subsequence aiJ such that sum of Numbers in this subsequence are divisible by M. InputThe first line contains numbers, n and m (1≤ n ≤106, 2≤ m ≤10 3)-the size of the original sequence and the numb

Miller-rabin Prime number Test

)Pseudo code:miller-Rabin (N): If (n2) then If (n==2) then return True End If return False End If if (n mod2==0) Then//N is an even number that is not 2 and returns directly to compositeReturn False End If//we first find the smallest a^u, and then gradually expand to a^ (n-1)u= N-1;//U represents exponential while(U%2==0) U= u/2End while//Extraction factor 2For i=1.. S//S is the number of tests setA = Rand_number (2N1)//Random acquisition of a 2~n-1 number ax = a^u%n while (UN)//check each a

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