834 edi

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Inline hook api (hot-patching)

I remember writing a HOOK API article (C/C ++ HOOK API (in-depth analysis of the principle-loadlibrarya). The main principle of this article is to construct a code byte, modify the first 16 bytes of the loadlibrarya function, and then jump to the custom function. When you call a normal function, unhook it again. In this way, when you call a function again, the unhook and hook operations appear too frequent. Moreover, the hook and unhook were designed as thiscall at the time. Therefore, maintaini

Memcpy function optimized by sse2

// Http://stackoverflow.com/questions/1715224/very-fast-memcpy-for-image-processing CourtesyWilliam Chan and Google. 30-70% faster than memcpy in Microsoft Visual Studio 2005. void X_aligned_memcpy_sse2(void* dest, const void* src, const unsigned long size_t){ __asm { mov esi, src; //src pointer mov edi, dest; //dest pointer mov ebx, size_t; //ebx is our counter shr ebx, 7; //divide by 128 (8 * 128bit registers) loop_copy:

How to count the number of times that the same string appears in multi-line text files in Delphi

{2002.8.5 kingron} {Source: Source string} {Sub: Sub string} {Return: Count} {Ex: strsubcount ('abccdcd', 'bc') = 2} Function strsubcount (const source, Sub: string): integer; VaR Buf: string; I: integer; Len: integer; Begin Result: = 0; Buf: = source; I: = pos (sub, Buf ); Len: = length (sub ); While I Begin INC (result ); Delete (BUF, 1, I + len-1 ); I: = pos (sub, Buf ); End; End; {strsubcount} {The following function returns the position after the specified position of substr in S}{Example:

ReactOS interrupt handling refers to the actual interrupt handling of the connection ..

KiInterruptTemplate .. That's it... The KiInterruptTemplate code is in ntoskrnl/ke/i386/Traps. s .... . Func KiInterruptTemplate_ KiInterruptTemplate: /* Enter interrupt trap */INT_PROLOG kit_a, kit_t, DoPushFakeErrorCode _ KiInterruptTemplate2ndDispatch:/* Dummy code, will be replaced by the address of the KINTERRUPT */Mov edi, 0 _ KiInterruptTemplateObject:/* The jump instruction address will be replaced with the actual address of the function to b

Example analysis of memory structure of C program runtime

corresponding to the main function is as follows 123456789101112131415161718192021222324252627282930313233343536 7: int main()8: {00401020 push ebp // ebp初始为0018FF84h压栈,压栈后esp = 0018FF48h - 4 = 0018FF44h00401021 mov ebp,esp // ebp保存栈顶0,ebp=esp=0018FF44h00401023 sub esp,48h // esp -= 48h开辟了一段栈空间,留待后面保存局部变量,此时esp=0018FF44h-48h=0018FEFCh00401026 push ebx 00401027 push esi00401028 push edi // ebx、esi和

64-bit Linux system: Stack overflow +ret2libc ROP attack

program, and no other auxiliary components. To control the register of passed parameters, you can extract the generic gadgets in the program initialization function.Enter Objdump–d./vul to observe the _libc_csu_init () function.There are two accessories available:Accessories 14005f0: 4c 89 ea mov %R13,%RDX 4005f3: 4c 89 f6 mov %R14,%RSI 4005f6: 44 89 ff mov %R15d,%EDI 4005f9: 41 ff 14 dc

Adobe Reader & amp; #39; CoolType. dll & amp; #39; TTF font Overflow

: 0803DD09 xor eax, ebp. Text: 0803DD0B mov [ebp + 108 h + var_4], eax. Text: 0803DD11 push 4Ch. Text: 0803DD13 mov eax, offset loc_8184A54. Text: 0803DD18 call _ EH_prolog3_catch // set up an SE handler. Text: 0803DD1D mov eax, [ebp + 108 h + arg_C]. Text: 0803DD23 mov edi, [ebp + 108 h + arg_0]. Text: 0803DD29 mov ebx, [ebp + 108 h + arg_4]. Text: 0803DD2F mov [ebp + 108 h + var_130], edi. Text: 0803DD32

Xitami If-Modified-Since command vulnerability analysis and exploitation

: 00412AC6 test cl, cl. Text: 00412AC8 jz short loc_412B06. Text: 00412AC8. Text: 00412ACA lea ecx, [esp + 8 + var_4]. Text: 00412ACE lea edx, [esp + 8 + arg_0]. Text: 00412AD2 push ecx. Text: 00412AD3 push edx. Text: 00412AD4 push eax. Text: 00412AD5 call sub_4444C0.. Text: 004444C0 sub esp, 5Ch. Text: 004444C3 push ebx. Text: 004444C4 push ebp. Text: 004444C5 push esi. Text: 004444C6 push edi. Text: 004444C7 mov

_stdcall function debug/release Assembly code differences

Debug versionESP stack top pointerEBP holds stack pointer Empty program: Int main () { 00411360 push ebp, press into EBP 00411361 mov ebp,esp; EBP = ESP, keep esp, wait for function call to resume, ESP is definitely used in a function call. 00411363 Sub esp,0c0h; esp-=0c0h (192); Leave temporary storage for the function ; put the values in other pointers or registers into the stack to use them in the function. 00411369 push ebx; Press into EBX 0041136A push esi, press into ESI 0041136B pu

Message process of the mfc Program

, ESI73D311B9 FF50 60 call dword ptr ds: [EAX + 60]; PreTranslateMessage (Message preprocessing)73D311BC 85C0 test eax, EAX73D311BE 75 0E jnz short MFC42.73D311CE73D311C0 57 push edi; message preprocessing returns FALSE73D311C1 FF15 ACB6DC73 call dword ptr ds: [73D311C7 57 PUSH EDI73D311C8 FF15 30B6DC73 call dword ptr ds: [;73D311CE 6A 01 PUSH 1; return TRUE73D311D0 58 POP EAX73D311D1 5F POP EDI73D311D2 5E POP ESI73D311D3 C3 RETN Tip:A. OD after the p

(3) Compilation of hello world with lwj Q & A H

From [wenjuliu25]: HelloWorld disassembly Analysis Lab environment:Visual c ++ 6.0 Objective: To analyze the memory allocation of a simple c program during program execution using assembly language /******* Mymain. cpp *********/ 1: # include 2: int main () 3 :{ 4: int x = 1; 5: printf ("Hello Canney \ n "); 6: return0; 7 :} /******* Mymain. asm *********/ 1: # include 2: int main () 3 :{ 00410950 push ebp 00410951 mov ebp, esp 00410953 sub ESP, 44 h // ESP = esp-0x40, allocate stack space t

--- Prototype implementation of overflow implanted Trojan Horse (backdoor) Author: flashsky (original)

stack occupied by the pressed ParameterPush ESI // protect the peripheral memoryPush EDIPush ECxPush edXMoV eax, [esp + 11bch]Push eaxMoV ESI, [esp + 11bch]Push 11a9h // Replace the value with an overflow ValueLea ECx, [esp + 24 h]PushecxMoveax, [esp + 11bch]PusheaxCall Recv // Recv forwardingTest eax, eaxJle loc_2CMP eax, ESI // determine whether the packet is receivedJle loc_1Movedx, [esp + 11ach]Xoreax, eaxDec eaxCmpedx, 0x90909090 // compare the specified overflow address valueJneloc_2Movea

Notes 1 for Assembly Language Learning

CPU switches from user mode to privileged mode, then jump to the kernel code to execute the exception handling program.In the "B INT" command, the value 0x80 is a parameter. In exception handling, the parameter determines how to handle the problem. In the Linux kernel, an int 0x80 exception is called a system call.The values of C eax and EBX registers are two parameters passed to the system call. The value of eax is the system call number, 1 indicates _ exit call, and EBX indicates the paramete

[Code] without DLL Remote thread injection, get the asterisk password of the Target Program

;//////////////////////////////; First get the relocation difference Call rebaseRebase:Pop EBP;Sub EBP, offset rebase;; Get the kernel32.dll's base address; By peb direct access; Place in here not routine; Because we need it afterAssume FS: nothing; MoV eax, FS: [30 h]; PTR _ TebMoV eax, [eax + 0ch]; PTR _ peb_ldr_dataMoV eax, [eax + 1ch]; list_entry ininitializationordermodulelist. flinkMoV eax, [eax]; flink's flinkMoV eax, [eax + 08 h]; The Kernel32's base addressMoV [EBP + dwbase], eax;MoV EC

C ++ from the perspective of assembly (opening part)

about some personal opinions. Next, we will conduct some small tests and explain them in assembly language. You can do it together. (1) Char name [] and char * Name 1:2: void process()3: {00401020 push ebp00401021 mov ebp,esp00401023 sub esp,4Ch00401026 push ebx00401027 push esi00401028 push edi00401029 lea edi,[ebp-4Ch]0040102C mov ecx,13h00401031 mov eax,0C

Example analysis of the underlying difference between C + + copy initialization and direct initialization

the arguments of the constructor, and is initialized with 1, which omits a step, speeds up the operation, and achieves the same effect. Note: In the above assembly, Visual Studio compiler optimizations have been turned off, indicating that this approach has been used as a general method of Visual Studio, rather than as a vs-perceived optimization tool.Initialize 3:classtest ct3 = Ct1Classtest ct3 = ct1;//Copy Initialization00b09538 Lea Eax,[ct1]00b0953e push EAX00b0953f Lea ECX,[CT3]00b09545 ca

About the invocation of a compiled language function (i)

asCall before eip=0x00401363 (next eip=0x00401368)After call EIP=0X0040100A,ESP=0X0012FEF4Then the call ends, and the last RET instruction of the __CDECL convention function pops the top of the stack to the EIP pointereip=0x00401368 Esp=0x0012fef8Then add esp,0xc, here 0xc=12 that is 3 DWORD is the number of front push (pop to pop to a register, add directly modify the top position of the stack, reduce the stack size)To this, the stack and EIP revert to the state before the call.Then we go insi

ring0-Change Dbgport address offset over dbgport clear 0

: 8063A8B2 7573 jne nt! Dbgkpsetprocessdebugobject+0xd1 (8063a927) The first function: Dbgkpsetprocessdebugobject (note that EDI+0BCH is the location of the debugport, which says the position is 0XBC), and is set when the debugger attaches the process DebugPort[CPP]View Plaincopy Kd> # BCH Nt! Dbgkpsetprocessdebugobject Nt! DBGKPSETPROCESSDEBUGOBJECT+0X56: 8063A8AC 399fbc000000 cmp DWORD ptr [

[Reprinted] HOOK API

this function: Exported FN (): Send-ord: 0013 HAssembly Code of address machine code: 71a21af4 55 push EBP // machine code to be hooked (1st methods): 71a21af5 8bec mov EBP, esp // machine code to be hooked (2nd methods): 71a21af7 83ec10 sub ESP, 00000010: 71a21afa 56 push ESI: 71a21afb 57 push EDI: 71a21afc 33ff xor edi, EDI: 71a21afe 813d1c20a371931ca271 cmp d

0.033 seconds of art-traps in xNa Math Library

Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/-->Public Static Vector3 Foo (vector3 V, Float Radius){Matrix;Matrix. createtranslation ( Ref V, Out A ); Matrix B=Matrix. createtranslation (v ); Matrix. Multiply (RefA,RefB,OutA ); Vector3 F1=B. forward; Vector3 F2;F2.x=B. m31;F2.y=B. M32;F2.z=B. M33; Vector3 F3;Vector3.add (RefF1,RefF2,OutF3 );Vector3.transform (RefF3,RefA,OutF1 );ReturnF1;} Test 2 is the focus of this Article. To facilitate the discussion, we div

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