a12 9800

, and there must be a area code 2. If it is a mobile phone, You Can prefix it with "+ 86", "86", "86-", and "+ 86 -". 3. The phone number can only match those in mainland China. There are three places at the beginning of 02, and only the numbers of 010 Beijing are allowed at the beginning of 01 4. The extension number is 020-89571800-1,020-89571800-125. 5,400 hotline support '/^ (\ +? 86 -?)? (18 | 15 | 13) [0-9] {9} $ /', 'tel '=>'/^ (010 | 02 \ d {1} | 0 [3-9] \ d {2 }) -\ d {7, 9} (-\ d + )

Just now, we heard the message "BlackBerry App World is accessible" from many netizens and opened Torch 9800 on our own... Access successful, Beijing, Torch 9800. It is accessible at least for the time being. It is undoubtedly a big positive news that BlackBerry PlayBook was about to be commercially available around the world 20 days ago. BlackBerry App World is a platform for BlackBerry mobile phones and

= Teacher ("harry", "26", "female", "02", "9000 ") # instantiate two lecturers, teachers_dict ["leo"] = t1 teachers_dict ["harry"] = t2 teacher_dict = {"TeacherName": "leo", "TeacherAge": "28 ", "TeacherSex": "male", "CourseNo": "01", "Salary": "10000"} teacher_dict = {"TeacherName": "harry", "TeacherAge ": "26", "TeacherSex": "female", "CourseNo": "02", "Salary": "9000"} course1 = Course ("01 ", "Linux cloud automated O M", "12800") # instantiate two courses course2 = Course ("02", "c/c ++ De

option takes parameters, such as-P 192.168.0.1:9800, Optarg points to its arguments, which is "192.168.0.1:9800" then ProxyHost is 192.168.0.1 and ProxyPort is 98. XX */TMP=STRRCHR (Optarg, ':‘); Proxyhost=optarg; if (tmp==null) {break; } if (Tmp==optarg) {fprintf (stderr, "Error in option--proxy%s:missing hostname.\n", Optarg); return 2; } if (Tmp==optarg+st

Gecko) version/5.0.2 mobile/8j2 safari/6533.18.5 ', ' user-agent:mozilla/5.0 (IPod; U CPU iPhone os 4_3_3 like Mac os X; En-US) applewebkit/533.17.9 (khtml, like Gecko) version/5.0.2 mobile/8j2 safari/6533.18.5 ', ' mozilla/5.0 (IPAD; U CPU os 4_3_3 like Mac os X; En-US) applewebkit/533.17.9 (khtml, like Gecko) version/5.0.2 mobile/8j2 safari/6533.18.5 ', ' mozilla/5.0 (Linux; U Android 2.3.7; En-us; Nexus one build/frf91) applewebkit/533.1 (khtml, like Gecko) version/4.0 Mobile safari/533.1 '

' : "Dec"}]}, "DataSet": [ {"Seriesname": "2006", "Data": [ {' Value ': ' 27400 '}, {' Value ': ' 2 9800 "}, {" Value ":" 25800 "}, {' Value ': ' 26800 '}, {' Value ': ' 29600 "}, {' Value ': ' 32600 '}, {' Value ': ' 31800 '}, {' Value ':

(Complex SQL authoring scheme)11-2 Chaining calls11-3 Complete the latest gift (four ways to write a business)11-4 My gift One (query with db.session and filter)11-5 my present two (group_by with Funct.count statistics combined)11-6 My gift three (do not return tuples in a function, but should return a dictionary)11-7 my present Four11-8 User Logoff11-9 my wish is one11-10 My Wish II (talk about the solution of the Loop import again)11-11 my wish three (talk about packaging tips for repeating c

inside, but the order after grouping must also be m1,m2,m3 ... The middle can be missing, but not disorderly.The following are legal m1,m3 or m2,m3 but not m3,m2If the order of the following code list is id=2 before id=1, the access after grouping must be id=2 before theHowever, if you call the default grouping, you will find that the id=1 is in front ( in the back will be in front; before it will be behind)Output is always1[A12,A11]2[A2,a21]But the

This problem is my topological sort of the beginning of the collection of the coffin, card me for several days, during the time of the separate committed timeout, memory overflow, Understanding WA, Details WA, Format wa ...The title is probably in a three-dimensional coordinate system with a large stack of rectangles, each of which is parallel to the axis.There are 4 cases of these rectangles--1. A coincident part (I a B) indicates that A is coincident with B;2. A's x-coordinate is greater than

"(? =[a-z])" match succeeds in position 0, so[a-z0-9]+ Also starting at position 0 to try to match, "[a-z0-9]+" first tries to match "a", matches successfully, continues to try to match, can successfully match the next "1" and "2", At this point has been matched to position 3, position 3 on the right side has no characters, then the control will be given to "$"; The meta character "$" tries to match from position 3, which matches the end position, which is " position 3", and the match is succe

calculation. The main reason is that this method does not reduce the number of multiplication of matrices. Matrix multiplication consumes much more time than matrix addition. So the breakthrough of the optimization algorithm is to reduce the multiplication operation . ~~~ According to the thought of the divide-and-conquer method, it can be seen that if we want to reduce the number of multiplication, the key is to calculate the product of 2 2-order matrices and use less than 8 times. Strassen pr

2011-01-21 11:05:19| Category: Default Category | Font size subscription Static U32 writepage (U32 addr, U8 *buf){U32 I, MECC, SECC;U8 Stat, tmp[6], value;Addr = ~0x3f;INITECC (); Reset ECCMeccunlock (); Unlock Main area ECCNfchipen (); Open the Nandflash film selectionWaitnfbusy (); Waiting for a busy signalWrnfcmd (0x80); Page Write command Cycle 1WRNFADDR (0x00); Column Address A0~a7WRNFADDR (0x00); Column Address A8~a11Wrnfaddr ((addr>>0) 0xFF); Line Address

and in is that the in-boot clause can only return a single field, such as:Select name from student where sex = ' m ' and mark in (select-from-grade where ...), the IN clause returns three fields, which is incorrect, theexists clause is allowed, but in only one field is allowed to return, and two fields can be randomly removed in the three-way.Not exists and not are the opposite of exists and in.exists (SQL returns the result set as true) notexists (SQL does not return a result set to true)The

exists (SQL returns result set, true)Not EXISTS (SQL does not return result set, true)As follows:Table AID NAME1 A12 A23 A3Table BID AID NAME1 1 B12 2 B23 2 B3Table A and table B are 1-to-many relationships a.id = B.aidSelect Id,name from A where EXIST (SELECT * from B where a.id=b.aid)Execution results are1 A12 A2The reasons can be analyzed as followsSelect Id,name from A where EXISTS (SELECT * from B wher

EXISTS (SQL returns the result set as true)Not EXISTS (SQL does not return result set is true)As follows:Table AID NAME1 A12 A23 A3Table BID AID NAME1 1 B12 2 B23 2 B3Table A and table B are 1-to-many relationships a.id = B.aidSelect Id,name from A where EXIST (SELECT * from B where a.id=b.aid)Execution results are1 A12 A2The reasons can be analyzed as followsSelect Id,name from A where EXISTS (SELECT * fro

returns the result set as true)Not EXISTS (SQL does not return result set is true) The following is a detailed description of the process of NOT exists: As follows:Table AID NAME1 A12 A23 A3Table BID AID NAME1 1 B12 2 B23 2 B3Table A and table B are 1-to-many relationships a.id = B.aidSelect Id,name from A where EXISTS (SELECT * from B where a.id=b.aid)Execution results are1 A12 A2The reasons can be analyz

= ' Wang ' or name= ' Zhao 'The result is the same.The example is as follows (that is, exists returns the same value in the WHERE clause after 2 comparisons, and not exists returns the different values in the WHERE clause):EXISTS (SQL returns the result set as true)Not EXISTS (SQL does not return result set is true)As follows:Table AID NAME1 A12 A23 A3Table BID AID NAME1 1 B12 2 B23 2 B3Table A and table B are one-to-many relationships a.id-b.aidSelec

. 2. CDMA 1X Network Structure is-95a Evolution to CDMA 1X Network, the circuit domain part of its core network is consistent with the IS-95, but in order to satisfy the packet data service, only the new PCF (Group control function), PDSN (Packet Data Service node), AAA (authentication, authorization and billing) and HA (attribution agent) and other grouped domain network elements are needed. To add A8, A9, A10, A11 interface processing between BSC-PCF and PCF-PDSN business and signaling messa

detailed description of the process of NOT exists:As follows:Table AID NAME1 A12 A23 A3Table BID AID NAME1 1 B12 2 B23 2 B3Table A and table B are 1-to-many relationships a.id = B.aidSelect Id,name from A where EXISTS (SELECT * from B where a.id=b.aid)Execution results are1 A12 A2The reasons can be analyzed as followsSelect Id,name from A where EXISTS (SELECT * from B where b.aid=1)--->select * from B WHER

Product_list = [(' Iphone ', 8000),(' Mac Pro ', 9800),(' Bike ', 800),(' Watch ', 10600),(' Coffee ', 30),]Shopping_list = []Salary = input ("Input your Salary:")If Salary.isdigit ():salary = Int (salary)While True:For Index,item in Enumerate (product_list):Print (Index,item)User_choice = input ("Choose to buy? >>>:")If User_choice.isdigit ():user_choice = Int (user_choice)If User_choice P_item = Product_list[user_choice]If P_ITEM[1] Shopping_list.ap