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(A36)) Print ('------------- -------') a = Np.random.random ((3,4)) *10 print ( a) print (' Decimal rounding: ', Np.floor (a)) print (' Decimal rounding up : ', Np.ceil (a)) Matrix Subtraction Import NumPy as np A12 = Np.arange () print (A12) A34 = A12.reshape (3,4) print (A34) # # structure can be directly used + * -/symbol for Operation Print (A34 + A34) pri

Reprinted from: http://blog.csdn.net/shanghaiqianlun/article/details/6976804Shanghaiqianlun's Column1. Structural block Diagram:2. Pin function Description Pin symbol Type Describe A0-a9,a10/ap,a11,a12/bc#,a13 Input Address input. Provide a line address for the Activate command, and a column address for the Read/write command and an automatic pre-charge bit (A10) to select a location from a bank's memory

Number: Name the original (current) path name start and end point through the main node A1 Yingbin Avenue A20 Pudong-Pudong Airport South 6 Road, A30 A2 huilu expressway A20 Pudong-Donghai Bridge Zhouzhu Road, Huinan Road, Dayu Road, A30, Nanlu Road A3 planned line 5 * A20 Pudong-A30 Pudong Zhouzhu Road, Dayu Road, A30 A4 fengjin expressway xinzhuang interchange-jinshanwei fengpu bridge, Dayu highway, A30, A5, A6 A5 jiajin expressway * city boundaries-A4

Create procedure patongjixx@ Datetimes datetime,@ Datetimee datetimeAsDeclare @ tbtiqu table (Aid int identity (1, 1 ),Anbie varchar (40 ),Xiaqu varchar (24 ),Isxingshi bit) Declare @ tbxiaqu table (Xid int identity (1, 1 ),Xxiaqu varchar (24 )) Declare @ tbresult table (Rid int identity (1, 1 ),Rxiaqu varchar (24 ),Xingheji int,Sharen int,Qiangjie int,Daoqie int,Daoqiej int,Qiangjian int,Baozha int,Toudu int,Fandu int,Xingqita int,Zhian int,Zaihai int,Huojing int,Shigu int,Jqita int,Qiuzhu int,

) Master method calculates the Master method calculation (first case) t (n) = (n^2)Optimization:(A-B) * (c-d) = ac+bd-(Bc+ad) so the xy equation (a*d+b*c) can be replaced with ac+bd+ (B-A) (c-d).That is, the original calculation AC,BD,AD,BC four sub-problems, converted to AC, BD, CD three sub-problems.T (n) =3t (N/2) +θ (n) calculated t (n) =o (n^ (log2^3)) ≈o (n^ (1.59))Classic Question 3: matrix multiplicationInput: Two matrices A, B output: a*bDivide and Conquer:General thinking is divided in

atm.youku.com\r\n"}; Char a3[] = {"127.0.0.1 fvid.atm.youku.com\r\n"}; Char a4[] = {"127.0.0.1 html.atm.youku.com\r\n"}; Char a5[] = {"127.0.0.1 valb.atm.youku.com\r\n"}; Char a6[] = {"127.0.0.1 valf. atm.youku.com\r\n "}; Char a7[] = {"127.0.0.1 valo.atm.youku.com\r\n"}; Char a8[] = {"127.0.0.1 valp.atm.youku.com\r\n"}; Char a9[] = {"127.0.0.1 lstat.youku.com\r\n"}; Char a10[] = {"127.0.0.1 speed.lstat.youku.com\r\n"}; Char a11[] = {"127.0.0.1 urchin.lst

% 10 First byte b1 = m1 + 0x90 Second byte b2 = m2 + 0x30 Third byte B3 = m3 + 0x81 Fourth byte B4 = N3 + 0x30 PressAccording to the above method, we can calculate that 0x10ffff is mapped to 0xe3329a35. In the secondary plane, the bitwise after 0xe3329a35 is reserved. The algorithm mentioned above can beIt is easy to write C/C ++ code. For non-programmers, you can also use the Excel formula for calculation. Assume that Unicode encoding is placed in cell

using formulas. Let's see how to calculate it. The Unicode ing method from unicode encoding to gb18030 encoding is as follows: U = Unicode-0x10000 M1 = u/12600 N1 = u % 12600 M2. = N1/1260 N2 = N1 %1260 M3 = n2/10 N3 = n2 % 10 First byte b1 = m1 + 0x90 Second byte b2 = m2 + 0x30 Third byte B3 = m3 + 0x81 Fourth byte B4 = N3 + 0x30 According to the above method, we can calculate that 0x10ffff is mapped to 0xe3329a35. In the secondary plane, the bitwise aft

convert the string to jsonVar JsonL = eval ("(" + str + ")"); // or var JsonL = new Function ("return" + str )(); // After conversion, it should be: JsonL = [{"name": "Wang Qiang", "age": 20 },{ "name": "Wang haiyun", "age ": 18}]; // It is not difficult to see that this structure is very similar to array, so we can use the idea of operating the array to operate the jsonNext we can control the output of elements in json.Alert (JsonL [1]. name );For (var I = 0; I For (var key in JsonL [I]) {Aler

complicated and often brings disastrous consequences to software integration. For example, if you want to install software A, B, and C in your release, and the running of a depends on packages A1, A2, A3, and B, c depends on C1. to install software A, B, C, you must install A1, A2, A3, B1, B2, C1, it is found that the A1 runtime must use the database A11 and A12, And the C1 runtime must use the database C11. After you have spent a lot of effort to fi

. When the matching is not successful, the system selects mismatch first. Only when this type of choice makes the entire expression fail to match. Here, the quantizer "?" Is used to modify the character "B", so "B ??" Is a whole. Matching Process: First, the character "A" gets control, starts from the position 0, and matches "A". The match succeeds. The control is handed over to the character "B ??"; Ignore the match, that is, "B ??" If no matching is performed, an alternative state is recorded,

on each channel. Supports two voltages: standard DIMM 1.5V voltage, supports speeds up to 1600, low voltage (1.35V), and supports speeds up to 1333 MHz. Supports single-row (SR), dual-column (DR), and four-column (QR) DIMMs. Up to two QR DIMMs and three Dr or SR DIMMs can be installed per channel. The system consists of 24 memory slots, divided into two groups (12 per group), one per processor group. Each of the 12-socket components into four channels. In each channel, the release lever of the

connected together, are a0-a12, a total of 13 address lines, and the data line is connected to 2440 LDATA0---LDATA15, One is ldata16-ldata31, and then look at the 2440 pin:As can be seen, 2440 of the data line is DATA0-DATA31, can receive the data width is 32 bits, and its address line is addr0--addr26, altogether is 27, then 2^27 is 128M, exactly is the memory controller a bank size. Then contact SDRAM and 2440 of the wiring, found that the data lin

A12..................A2 A1 A3 A1 A2 A4 A1 A2 A3A4 A3 A6 A4 A5 A5 A6 A7A6 A5 A9 A7 A8 A12 A9 A10 A11.................. N2 F2 layout: A1 A1 A2 A1 A1 A2 A2 A3A3 A3 A4 A3 A4 A4 A4 A5 A5A5 A5 A6 A6 A6 A6 A7 A7 A8A7 A7 A8 A8 A9 A9 A10 A10..................A2 A2 A1 A1 A2 A3 A1 A2A4 A4 A3 A5 A5 A3 A4 A4A6 A6 A5 A7 A8 A6 A6 A7A8 A8 A7 A7 A10 A10 A8 A9 A9.................. O2 layout: 2 drives 3 drives 4

2015 Blue Bridge Cup: 7. Number of card types21 points 3598180 small white or violence, this is after the test after the classmate told me .... 21 minutes, that's it.Xiao Ming was hijacked to X Vegas and was forced to play cards with 3 other people.A deck of poker (minus the size of ace, a total of 52), evenly distributed to 4 people, each 13 Zhang.At this time, Xiao Ming's brain suddenly emerged a problem:If you do not consider the suit, only consider the points, also do not consider the order

observed value O2 probability is B1 (O2), from the state 2 to emit the observed value O2 the probability of B2 (O2), from the state 3 to emit the observed value O2 probability of B3 (O2).If the observation value from the State 1 O2, may be from the first moment of the 1, 2 or 3 of the state loaded, if the transition from the state 1, the probability is α1 (1)*a11*b1 (O2), if the transition from the state 2, the probability is α1 (2)*a21*b1 ( O2), if converted from State 3, the probability is α1

, there is an interesting phenomenon here, we obviously follow the translation of the Py, rotation XZ and the order of scaling SF as the input of the row matrix multiplication, but in the later process text description, I follow the inverse to explain. What is this for? Because the matrix is stored in a two-dimensional array, WebGL passes through the shader in the process of passing the matrix to the shader , that is, the shader is processed by the data for each column .In general, two matrices

with a12:2. $a means searching for content ending in a13:3.^$ represents a blank line, not a space14:4.[Email protected]_back ~]# grep-v n "^$" Test.loggrep: ^$: No file or directoryTest.log: In a nutshell, a regular expression is a set of rules and methods that are defined to handle a large number of strings, such as assuming @ represents 123456,! for ABCDE. By defining the paving of these special symbols, the system administrator can quickly filter

#!/usr/local/bin/python3#-*-coding:utf-8-*-#key-value#dict unordered, no subscript, no subscript required, because there is keystu={' stu001 ': "Zhang Yu", ' stu002 ' : "Ma Hong Yan", ' stu003 ': "Zhang Guo Bin", ' stu004 ': "Sha Chun Hua"} "------------------------------Operation--------------- -------------------------take----------print (stu["stu001") #根据key值取对应的value值--------------------stu[' stu001 ']= ' Tommy Cheung '--------------------stu[' stu005 ']= ' Zhang Zhong Jian '----------delete

Suppose, a column of data, save is male or female such sex, below, how can calculate the number of men and women? Suppose the data range for saving men and women information is: A1:A12 then: ① Calculate male other numbers =countif (A1:a12, "male") Use the general formula above to calculate the number of men. ② calculate the number of women in other =countif (A1:a1