Configuration successful. If debugging is successful!
Hongyi # show run
Building configuration...
Current configuration: 4655 bytes!! Last configuration change at 04:47:29 UTC Sun Apr 25 2004 by tonyxue! NVRAM config last updated at 04:47:50 UTC Sun Apr 25 2004 by tonyxue!Version 12.3:Service timestamps debug datetime msecService timestamps log datetime msecService password-encryption!Hostname hongyi!Boot-start-markerBoot-end-marker!No logging consoleEnable secret 5 $1 $ nyjl $3Q7avJNhGMGg9h8S3
/* For the sum of the first 5 items of sn = a + AA + AAA + AAAA + AAAAA, where A is a number, for example: 2 + 22 + 222 + 2222 + 22222*/#include int main (){int i = 0;int a = 0;int sum = 0;int num=0;scanf ("%d", num);for (i = 0; i {A = a * ten + num;sum = sum + A;}printf ("%d", sum);return 0;}Output Result:224690Press any key to continueThis article is from the "51cto" blog, be sure to keep this source http://51cccto.blog.51cto.com/10251929/1709000Fin
In the configuration of the V5 H3C MSR router, including the V7 H3C switch, the AAA local user right can be modified by Authentication-mode level 1/2/3 To modify the user's configuration permissions. In the new MSR Router V7 version, the level option is not available and only the local user rights are configured through user-role 650) this.width=650; "src=" Http://s5.51cto.com/wyfs02/M00/78/43/wKioL1Z5DK6yW17_AAAqEyG8A8s229.png "title=" ori@_ 2js[je9
Program:The sum of the first 5 items of sn = a + AA + AAA + AAAA + AAAAA, where A is a number, for example: 2 + 22 + 222 + 2222 + 22222#include int main (){int i = 0;int a = 0;int sum = 0;int num=0;scanf ("%d", num);for (i = 0; i {A = a * ten + num;sum = sum + A;}printf ("%d", sum);return 0;}Results:224690Press any key to continueThis article is from the "Rock Owl" blog, please be sure to keep this source http://10742111.blog.51cto.com/10732111/171199
Example of RADIUS authentication, authorization, and billing configuration for 18.6.3 802.1x users
In 802.1x authentication, the use of remote RADIUS servers is the most commonly used AAA access control, and the RADIUS server can not only realize the required authentication of 802.1x users, but also authorize and charge them. This example topology, as shown in Figure 18-6, uses a RADIUS server that is widely used by the H3C company to develop the IMC
Package COM. hanqi; import Java. util. *; public class yonghukongzhi {public static void main (string [] ARGs) {// todo automatically generated method stub system. out. println ("enter a number:"); required jishu = new partition (system. in); int A = jishu. nextint (); system. out. println ("Enter the number:"); export Geshu = new partition (system. in); int B = Geshu. nextint (); int sum = 0; string c = ""; for (Int J = 0; j
S = a + AA + AAA + AA
Just use a For loop to achieve the purpose #includeFind the sum of the first 5 items of SN=A+AA+AAA+AAAA+AAAAA, where a is a number, for example: 2+22+222+2222+22222
$items [' items '] = Array ( l (' Configure ', ' admin/config '), L (' Structure ', ' admin/structure '),); $theme = Theme (' Item_list ', $items);1, judging if all the modules are loaded,if (!module_load_all (NULL) ! defined (' Maintenance_mode ')) { thrownewException(t (' theme () May is called until all modules is loaded. ') )); }2, get all the themeregistry information, this information is the Hook_theme array of all module definitions, and merge many default information, such as
JS two number A, B, to find the value of S=A+AA+AAA+AAAA+AA...A, where a is a number. Add a total of B numbers, such as user input 2,5 s=2+22+222+2222+22222
has no user attribute. On the contrary, I indicated # {user. the user in username} is the parameter I passed in, indicating@ Param ("user "). This solution can be promoted to the case where the parameter is not a bean object.
According to the analysis just now, if # {user. Username} is used, add@ Param ("user ")To mark the USER parameter. In other words, if the parameter is not added, the user in # {user. Username} is treated as an attribute in the parameter (note that there is an underline in
of the Rocchio algorithm is that it is easy to implement, the calculation (training and classification) is very simple, it is usually used to measure the performance of the classification system of the benchmark system, and the practical classification system rarely use this algorithm to solve the specific classification problem.9 Comparison of various classification algorithmsAccording to the conclusions of this paper,Calibrated boosted trees has the best performance, random forest second, unc
See the full set of "C language problem sets"
Topic:
Find the value of S=A+AA+AAA+AAAA+AA...A, where a is a number. For example 2+22+222+2222+22222 (there are 5 numbers added at this time), several numbers are added with keyboard control.
1. Procedure analysis: The key is to calculate the value of each item.
2. Program Source code:
#include "stdio.h"#include "conio.h"Main (){ int a,n,count=1; long int sn=0,tn=0; printf ("Please input A and n\
relational database table; is a recognition property that is typically used to retrieve2. Start the construction process:sudo apt-get install ldap-utils SLADPDError occurred:Solve the problem:sudo apt-get install SLAPD ldap-utils migrationtools(2) Reconfiguration:sudo dpkg-reconfigure slapd, Modify the DIT suffix to dc=example,dc=com, and DNS domain name to fill in the example.com, that is, the client to fill in the benchmark DN(3) Create a new add_content.ldif file to add the corresponding us
For correction, $ aaabbb is changed to aaabbb 1. for example:
$ Table = Channel
Change
$ Table = Channel
2 for example
$ Row = 10
Change
$ Row = 10
3 for example
$ Table = Channel
Change
Proud browser is deeply loved by netizens web browser software, a lot of friends are accustomed to use this software in the network of the Sea. But most of the time, some users realize that when they use a browser to surf the internet, they
Today into the use of orcle, found in the system, systems account login prompted account is locked, and later looked up data, problem resolution, the method is as follows:Microsoft Windows [version 5.2.3790](C) Copyright 1985-2003 Microsoft
Re-locking is a similar scenario for deadlocks and nested monitoring programs. The re-entry lock is also mentioned in the read and write lock.
Reentrant locking may occur if a thread is reentrant in a lock, readwritelock or some other Synchronizer
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