aaa mpls

MPLS label distribution protocols include:1. LDP (Label Distribution Protocol)2. TDP (CISCO private)3. RSVP Resource Reservation Protocol4. CE-LDP5. MP-BGP (Multi-Protocol extensions for BGP-4)6. Labeled BGP (BGPV4 with label distribution capability)LDP (Label Distribution Protocol) Label Distribution ProtocolLDP operations mainly include the following four stages:(1) discovery stage(2) session establishment and maintenance(3) LSP establishment and ma

VPN instance changes, the changed PE device should take the initiative to send the BGP refresh packet to refresh the VPN route, and use the new RT attribute to filter the route. Different from RD, We can configure multiple RT attributes for a VPN instance, and the RT attributes are released in the extended group attributes of the bgp update message. The format is similar to that of common group attributes. When a route carries multiple extended group attributes and RT attributes at the same tim

Package COM. hanqi; import Java. util. *; public class yonghukongzhi {public static void main (string [] ARGs) {// todo automatically generated method stub system. out. println ("enter a number:"); required jishu = new partition (system. in); int A = jishu. nextint (); system. out. println ("Enter the number:"); export Geshu = new partition (system. in); int B = Geshu. nextint (); int sum = 0; string c = ""; for (Int J = 0; j S = a + AA + AAA + AA

Just use a For loop to achieve the purpose #includeFind the sum of the first 5 items of SN=A+AA+AAA+AAAA+AAAAA, where a is a number, for example: 2+22+222+2222+22222

= "Wkiol1r7wvbglewgaahxzdmybiq924.jpg"/>Select New650) this.width=650; "src=" http://s3.51cto.com/wyfs02/M02/54/2F/wKioL1R7wV_QOxU_AAHCskwvEec490.jpg "title=" 10.png "alt=" Wkiol1r7wv_qoxu_aahcskwveec490.jpg "/>Select NAC After this domain is submitted650) this.width=650; "src=" http://s3.51cto.com/wyfs02/M02/54/2F/wKioL1R7wXbSDb7yAAIT5gnlsuo341.jpg "title=" 11.png "alt=" Wkiol1r7wxbsdb7yaait5gnlsuo341.jpg "/>Select NAC configures this domain650) this.width=650; "src=" http://s3.51cto.com/wyfs02

PackageLianxi;ImportJava.util.*; Public classDiejia { Public Static voidMain (string[] args) {System.out.println ("Please enter a cardinality:"); Scanner Jishu=NewScanner (system.in); intA =Jishu.nextint (); System.out.println ("Please enter the number of added numbers:"); Scanner Geshu=NewScanner (system.in); intb =Geshu.nextint (); intsum = 0; String C= ""; for(intj = 0; J ) { //A to String typec = C +string.valueof (a); //Show cardinality increment changeSystem.out.println

$items [' items '] = Array ( l (' Configure ', ' admin/config '), L (' Structure ', ' admin/structure '),); $theme = Theme (' Item_list ', $items);1, judging if all the modules are loaded,if (!module_load_all (NULL) ! defined (' Maintenance_mode ')) { thrownewException(t (' theme () May is called until all modules is loaded. ') )); }2, get all the themeregistry information, this information is the Hook_theme array of all module definitions, and merge many default information, such as

JS two number A, B, to find the value of S=A+AA+AAA+AAAA+AA...A, where a is a number. Add a total of B numbers, such as user input 2,5 s=2+22+222+2222+22222

#include C language: The sum of the first 5 items of SN=A+AA+AAA+AAAA+AAAAA, where a is a number, for example: 2+22+222+2222+22222

has no user attribute. On the contrary, I indicated # {user. the user in username} is the parameter I passed in, indicating@ Param ("user "). This solution can be promoted to the case where the parameter is not a bean object. According to the analysis just now, if # {user. Username} is used, add@ Param ("user ")To mark the USER parameter. In other words, if the parameter is not added, the user in # {user. Username} is treated as an attribute in the parameter (note that there is an underline in

of the Rocchio algorithm is that it is easy to implement, the calculation (training and classification) is very simple, it is usually used to measure the performance of the classification system of the benchmark system, and the practical classification system rarely use this algorithm to solve the specific classification problem.9 Comparison of various classification algorithmsAccording to the conclusions of this paper,Calibrated boosted trees has the best performance, random forest second, unc

See the full set of "C language problem sets" Topic: Find the value of S=A+AA+AAA+AAAA+AA...A, where a is a number. For example 2+22+222+2222+22222 (there are 5 numbers added at this time), several numbers are added with keyboard control. 1. Procedure analysis: The key is to calculate the value of each item. 2. Program Source code: #include "stdio.h"#include "conio.h"Main (){ int a,n,count=1; long int sn=0,tn=0; printf ("Please input A and n\

relational database table; is a recognition property that is typically used to retrieve2. Start the construction process:sudo apt-get install ldap-utils SLADPDError occurred:Solve the problem:sudo apt-get install SLAPD ldap-utils migrationtools(2) Reconfiguration:sudo dpkg-reconfigure slapd, Modify the DIT suffix to dc=example,dc=com, and DNS domain name to fill in the example.com, that is, the client to fill in the benchmark DN(3) Create a new add_content.ldif file to add the corresponding us

broadband IP Telephone test network platform (VOIP-VPN) to achieve. Optical bridge users in the voice of the need to focus on the following areas: the scope of business to be broad, you can achieve voice mail, voicemail, address books and many other functions, can be integrated with the computer, data, voice simultaneous implementation. High bandwidth, easy to increase service items, low interference, stable voice quality, low cost, good performance/price ratio. These requirements through Netco

Release date:Updated on: Affected Systems:Cisco ios xe 3.9.xDescription:--------------------------------------------------------------------------------Bugtraq id: 63979CVE (CAN) ID: CVE-2013-6706 Cisco IOS is an interconnected network operating system used on most Cisco system routers and network switches. When Cisco ios xe processes an IP packet header in an MPLS packet, the CEF module may encounter an error. Attackers can exploit this vulnerabil

In the MPLS/vpn experiment, the configuration of OSPF/r12002 was developed from the basis of the first experiment, so some basic configurations are not mentioned here. The network topology is as follows: first complete the RIP configuration on CE1: Before you configure this, you must delete the previous configuration. If you do not delete the configuration, the problem may occur. CE1: router rip version 2 network 1.0.0.0 network 192.168.1.0 no auto-su

MPLS default MTU is 1500, do not make any changes, I ping full package does not fragment, why can pass! It adds MPLS information altogether is 1504 bytes, how can transmit? Here is my reply: It has been verified, what you need to do is to study your network topology again, if you have a ready-made environment, put your detailed topology map, as well as the configuration of each device sent to me, I can he

BGP/MPLSVPN Concept 1: VRF One of the security measures of BGP/MPLSVPN is routing isolation and information isolation. It is implemented through the VPN route Forwarding (VPNRouting Forwarding: VRF) Table and LSP in MPLS. On a PE router, there are multiple BGP/MPLSVPN concepts 1: VRF tables, which correspond to one or more sub-interfaces on the PE router, used to store the route information of the VPN to which these subinterfaces belong. Generally, t

Recently, I have been reading mpls vpn, but I have never understood the differences between the two RD and RT parameters in VRF. By searching materials on the Internet for repeated reading and thinking, I finally understood it. The following uses a more understandable metaphor for sharing. For example, if you receive an invitation letter, you need to go to a high-end office building to attend the meeting. Because of the strict security requirements,

For correction, $ aaabbb is changed to aaabbb 1. for example: $ Table = Channel Change $ Table = Channel 2 for example $ Row = 10 Change $ Row = 10 3 for example $ Table = Channel Change