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This bug occurs especially when fastreport preview is used and may occur when you exit the program. The error message returned when the app exits: access violation at address 00000000. Read of address 00000000. Vclskin version: 4.93.11.13 if you have any questions, please contact me coolslob@163.com solution: Comment the 26th line of the following code in the winskinform. Pas unit. Procedure twinskinform. getIcon (var bmp: tbitmap ); VaR Smallicon: hicon;

first jump found in the correct information) NOP is used to erase the jump and make the jump invalid, lost, so that the program smoothly comes to the correct information behind it Xxxxxxxxxxxx correct information, such as: Registration successful, thank you for your support, etc (we hope it will not be skipped, let it appear, the program must come here smoothly)......Xxxxxxxxxxxx error messages (we do not want to jump here to prevent it from appearing) are transmitted between the memory and reg

You can use the setwindowpos function to set the position and status of a window. In this example, you can use this function to place a form on all forms so that it is always at the beginning. Let's take a look at the definition and parameters of the setwindowpos function: Before using the API function, you must declare the following in the program: Private declare function setwindowpos lib/"USER32/" (byval hwnd as long, byval hwndinsertafter as long, byval X as long, byval y as long, byval

Sketchup has a ruby interface that allows you to easily develop plug-ins you need. First, we will try to draw a ball. However, there is a small problem, that is, when we draw the same ball continuously (with the same radius and ball Center), we will not only see the new ball, but even delete the original one. We need to study it again. The Code is as follows: Require 'sketchup. rb' @ Cx = 0@ Cy = 0@ Cz = 0 Def drawshpere (center, radius)# Access the e

Basic concepts1 bytes = = 8 bits = = 11111111 (2 binary)255 (10 binary) = 11111111 (2 binary) ==ff (16 binary) ==8 bit register65535 (10 binary) = 11111111 11111111 (2-in) ==ffff (16-binary) ==16-bit register16-bit General purpose register: AX BX CX DX, maximum storage is number is FFFFAh Al represents high 8-bit and low eight-bit registers for AXFor example execution: mov ax f4a3hAX=F4A3H (62627)In memory 11110100 10100011F4 A3Ah alBH Bl,ch CL,CH CL

Program 0: Convert the string "Adcdef" to uppercase, and change the string "FGHJK" to lowercaseData segmentDB ' Adcdef 'DB ' xcvbnm 'Data endsCode segmentStartMOV Ax,dataMOV Ds,axMOV bx,0MOV cx,6MOV di,0S:mov AL,DS:[BX]and al,1011111bMOV Ds:[bx],alMOV al,ds:[bx+6]or al,0100000bMOV Ds:[bx+6],alAdd bx,1Loop sMOV ax,4c00hint 21hCode endsEnd StartProgram 1: Use stack reverse to store DW 0111h,0222h,0333h,0444h,0555h,0666h,0777h,0888hAssume Cs:code, Ds:dat

This article to share is the use of VC + + according to the size of the dialog box to adjust the size of the control method and sample code, the need for small partners can refer to. One. Change in size and position 1. First add the CRect m_rect for the form class, which is used to record the current size of the form. 2. In the Class Wizard (Ctrl+w), add the message wm_size response function OnSize () to the form; Note if (ntype==1) return; This sentence must be added, otherwise the minimum

; ; ; ; Rotate around Y-axis; ; XT = X * COS (Yang)-Z * SIN (yang)/256; ; ZT = X * SIN (yang) + Z * COS (yang)/256; ; X = XT; ; Z = ZT; ; ; ; Rotate around Z-axis; ; XT = X * COS (Zang)-Y * SIN (Zang)/256; ; YT = X * SIN (Zang) + Y * COS (Zang)/256; ; X = XT; ; Y = YT; ; ; ;　　　　　 Divide by 256 coz we have multiplyd our sin values with 256 too. ; ;　　　　　　This example isn ' t too fast right now but it ' ll work just. ; ; ; ; Current date:6-9-95 Vulture; ; ; ;========================================

Cmpl $SMAP,%eax # Check the return is ' SMAP 'Jne bail820 # Fall to e801 if it fails # Cmpl $%di # is this usable memory?# jne again820 # If this are usable memory, we save it by simply advancing%di by# sizeof (E820REC).#good820:Movb (E820NR),%al # up to entriesCMPB $E 820MAX,%alJnl bail820 INCB (E820NR)MOVW%di,%axADDW $,%axMOVW%ax,%diagain820:Cmpl $%EBX # Check to IfJne jmpe820 #%EBX is set to EOFbail820: Using the assembly instructions above, the entry description block order of the av

5.1 [BX] and [0] Similar [0] Indicates the offset address length, the segment address is default in BS, However [0] in debug is not the same as in ASM, [0] in ASM after ML will become the value of 0 To solve MOV ax,[1] after AXM compiled into MOV ax,1; can be written mov ax,ds:[1] Four kinds: mov Al,[0];mov al,ds:[0];mov Al,[bx];mov DS:[BX] Loop: Related to Loops (ax) =0010h; use () to indicate that the content in Ax is 2000:1000 of the content is 0010: (21000H) =0010h MOV ax,[2] is described

-2 means there is no control inside, so you should be aware that there is no macro definition ID-2 in your control, this is an imperfect point. Then add the variable in the member variable of the class CRect m_rect;//get the initial window sizeControl m_control[10];//up to 10 controls, where code portability is less powerful, but the author is less capable, directly represented by numbers, and not defined by macros Then you can add a method to the OnSize. Controls the size of the control, making