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Description The switch statement is required. If only the if statement is submitted successfully, the score is zero. Amen……> LCL liked Harry Potter very much. Google camp held a 3D modeling competition at the end of last semester. At the end of the award, some titles were needed for evaluation, therefore, LCL wants to know what the corresponding rules in HP are, so she handed this question to you ~~~ (Why does she always give you these

Our company is eager to recruit two interns. Great opportunity: Take the test outsourcing from Microsoft and practice at Peking Union Medical College Hospital, the top hospital in China. Have the opportunity to access Microsoft's latest medical technology (amalga UIS) in China ). At the same time, we have the opportunity to work in a dynamic entrepreneurial team and get hands-on advice from senior industry experts. Required in Beijing (no accommodation). This year's undergraduate students, sof

Summer camp for "Shenzhen Cup" Mathematical Modeling in 2015-Question B: k-mer index of DNA sequence,-bk-mer This is a question given to me by a student from Shandong University of Science and Technology. I don't know much about mathematical modeling, so I can only use computer programs to solve it. This is a specific problem: This problem comes from the k-mer index problem of the DNA sequence. Given a DNA sequence, this series contains only four let

Php tutorial magic function concentration camp 1. _ Construct () Called when instantiating an object, When _ construct and a function with the class name both exist, __construct will be called and the other will not be called. 2. _ Destruct () It is called when an object or object operation is terminated. 3. _ Call () Object calls a method, If a method exists, it is called directly; If not, the _ call function is called. 4. _ Get () When reading the a

. Don't misunderstand me-there are still a lot of excellent PHP developers, even at the time. However, as I said, the shoddy Cainiao works are everywhere. When a cowboy PHP programmer has no guiding principles to develop a program together, like PHPbb, PHPNuke, and many rough. php3 packages. But can you simply blame PHP developers? No! Other Web language giants, ASP and Perl, are equally notorious. they also promote a method of development in the form of stew. That's why PHP gets such a nickname

DescriptionReads a non-negative integer that contains only a +,-, *,/, evaluates the expression, and computes the value of the expression.InputThe test input contains several test cases, one row per test case, and no more than 200 characters per line, separated by a space between integers and operators. There is no illegal expression. When only 0 o'clock input is completed in a row, the corresponding result is not output.OutputOutput 1 rows For each test case, that is, the value of the expressio

Take the right and check the set of silly questionsUse the split method to grass over.Split code:# include 　　2016 Summer Camp Training 2 C problem food chain

test, indicates the minimum HP loss.Sample Input110 22100 11 100Sample Output20201 problem Analysis: DotA ah, long time no play, really ... Well, first count all the enemy damage, and then use DPS/HP (each point of health damage) as the basis for sorting, from large to small to kill the light, each kill a will let the total DP minus the killed person's DP can.1#include"iostream"2#include"algorithm"3 4 using namespacestd;5 structEnemy6 {7 intHP;8 intDP;9 };TenEnemy n[ +]; OneEnemy t[ +];

1 2Sample Output2 Problem Analysis: Obviously this is a question of reverse order number, can be solved by merging sort.1#include"Cstdio"2 3 intnum[1000005];4 intt[1000005];5 __int64 sum;6 voidMsetintN)7 {8 for(intI=1; i)9scanf ("%d",num[i]);Ten } One voidpxintXinty) A { - if(Y-x >1) - { the intm = x + (y-x)/2; - intp = x,q = M,i =x; - px (x,m); - px (m,y); + while(P y) - { + if(q >= y | | (P Num[q])) At[i++] = num[p++]; at Else -

instance is one row.Sample Input121 33 40 73 815 1915 2010 158 186 125 104 142 90Sample Output5problem analysis: Greedy algorithm bar, first the program relationship according to the program start time sorting, and then from the first, if there is another program in its program time interval, then replace the program with it, until there are no other programs in the program, repeat until the maximum time,get the answer. 1#include"Cstdio"2 3 structTV4 {5 intBeg;6 intend;7 };8TV v[ -];9 v

= r2; The circle equation can be transformed into x=rcosα,y=rsinα;and x12+y1 2= r2 = x02+y0 2, (a*b)/| a|*| B| = cos120.Easy to get acosα+ bsinα= -0.5r(acosα) 2 = (0.5r + bsinα) 2r2sinα2 + rbsinα+ 0.25r2-a2 = 0X1 = -0.5*b + a*√3 * 0.5 or x1 = -0.5*b-a*√3 *0.5 (shed)and y = -0.5*b-a*√3 * 0.5 or y= 0.5*b + a*√3 * 0.5 (Shed)The same can be done by x2, y2;It can also be solved directly using the cos (α + β) = cosαcosβ-Sinαsinβ,sin (α + β) = sinαcosβ+ cosαsinβ1#include 2#include 3 intMain ()4 {5 D

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Minimum spanning tree, simple topic. Set of prim templates, other topics are more meaningful.Sample Input3//Number of villages1 2 1/connectivity status and weights1 3 22 3 441 2 11 3 41 4 12 3 32 4 23 4 50Sample Output//The right to export the minimum spanning tree351#include 2#include string.h>3 #defineSize 1004 #defineINF 0x3f3f3f3f5 6 intVellage[size][size],flag[size];7 intN,T,A,B,C,I,J,K,ANS,MAXN;8 9 voidInit ()Ten { Onet=n* (n1) >>1; Amemset (Flag,0,sizeof(flag)); -memset (Vellage,0,sizeof(

voidDijkstra () at { -dis[1]=0; - for(i=1; i//Traverse - { - intm=inf,x; - for(j=1; j) in { - if(!flag[j]dis[j]M) to { +m=Dis[j]; -x=J; the } * } $flag[x]=1;//MarkPanax Notoginseng for(k=1; k//Maintenance -Dis[k]=min (dis[k],dis[x]+land[x][k]); the } +coutEndl; A } the + intMain () - { $ while(cin>>t>>N) $ { - init (); - while(t--) the { -Cin>>a>>b>>C;Wuyi if(LAND[A]

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') - { -FIR.I =i; -FIR.J =J; inFIR.K =K; - } to } + } - voidBFS () the { *Queue p; $ escaper sec;Panax NotoginsengFir.time=0; - P.push (FIR); the while(!p.empty ()) + { ASEC =P.front (); the P.pop (); + for(intI=0;i6; i++) - { $FIR.I = sec.i+v[i][0]; $FIR.J = sec.j+v[i][1]; -FIR.K = sec.k+v[i][2]; - if(MAZE[FIR.I][FIR.J][FIR.K]! ='#') the { -Fir.time = sec.time+1;Wuyi if(MAZE[FIR.I][FIR.J][FIR.K] = ='E') the

--) One { AMemset (A,0,sizeof(a));//initialize two arrays to be used -memset (b,0,sizeof(b)); -CIN >>N; the for(i=1; i) -A[i]=i;//number of N recruits - while(n>3)//execution of statements within a loop when the number is greater than 3 - { + for(i=1, j=1; i) - { + if(i%2!=0)//1 2 1 2 ... a count of 2 of the full report, which is marked as even in the array of a, should be removed A { atB[j]=a[i];//Place the n

; -Then.time=0; -Maze[then.i][then.j].z ='#'; - P.push (then); A while(!p.empty ()) + { theNext =P.front (); - P.pop (); $ for(intk=0;k4; k++) the { theTHEN.I = next.i+v[k][0]; theTHEN.J = next.j+v[k][1]; the if(Maze[then.i][then.j].z! ='#') - { inThen.time = next.time+ One; the if(Maze[then.i][then.j].z = ='@') theMaze[then.i][then.j].sum + =Then.time; AboutMaze[then.i][then.j].z ='#'; the P.push (then); the } the } + } - } the in

(int i= (x); i#defineGongzi (i,x,y) for (int j= (x); j>=y;j++)#defineMAXN 1000005#defineRandom (x) (rand ()% (x))using namespacestd;intn,a[maxn],k;int Select(intLintR) { if(L==R) {returna[l];} intMid=random (r-l+1)+l; intKey=a[mid];//mid for the final subscript, constantly retrieving, until the left side is smaller than key, the right is bigger than key intFirst=l,last =R; while(firstLast ) { while(last>mida[last]>=key) { Last--; } swap (A[mid],a[last]); Mid=last;//at this point

A basic application of a wrong-line formula.Approximate test instructions: To find the wrong arrangement of N number. (Each one is wrong)Here first put the wrong line formula: D (1) =0;d (2) =1;d (n) = (n-1) * (d (n-1) +d (n-2))Its derivation is also very interesting, it should be the idea of recursion (personal guess).Sample Input23Sample Output12Note this question two points:1. Long Integer type __int642. It is better to hit the table to prevent timeoutsThen, then, it's over.#include #includeu