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Summer Camp (4) ——— combo of the six rounds (poj1067)

horrible goblin staring at you.You: "..."Devil: "As long as you and I game three innings, you win, then I will meet your one wish, otherwise, you just lose a sentence." Hum. ”You didn't have time to spit this ESU bridge section, then agreed to the Devil's request. In the first inning, the devil turned out two piles of stones, and he gave the number of stones, and you chose to have the hand to seeWho is the last one who can no longer take the stone?Problem Analysis: Witzov game problem, as long

2016HUAS_ACM Summer Camp 4K-Basic DP

++) - { theCin>>N[i]; +Sum+=i*n[i];//figure out the sum of values A } the if(! Sum)//all 0 + Break; - if(sum%2)//The total value is odd when not established, pruning $ { $cout"Collection #"": \ncan ' t be divided.\n\n"; -t++; - Continue; the } - Wuyiflag=false; the -Dfs0,6); Wu - if(flag) About { $cout"Collection #"": \ncan be divided.\n\n"; -t++; - Continue; - } A Else +

2016HUAS_ACM Summer Camp 4M-Basic DP

Simple 0-1 knapsack problem, everyone will do. Test instructions don't want to explain too much.Briefly describe the case of the topic and take several keySample Input1//Number of test groups T5 10//Total number of bones N, total backpack volume V1 2 3 4 5//n block Bone individual values5 4 3 2 1//n block bone Individual volumeSample output//Outputs maximum value14Note: Each bone has only one piece, otherwise the output of the case can not be understood as 14.The value and volume of the bone mus

2016HUAS_ACM Summer Camp 4F-Number theory

to) a hole to catch the rabbit, ask the rabbit finally can escape a robbery. For example, there are n=6 a hole, the number is 0, 1, 2, 3, 4, 5, the wolf every m-1=1 a hole to catch the rabbit, then the wolf into the cave is 0, 2, 4, 0, 2, 4 ... (infinite loop). If rabbits hide in holes 1, 3 and 5th, they are safe.Sample Input2//Number of test cases1 2//m and N2 2Sample OutputNOYES#include using namespacestd;intT,m,n;intgcdintAintb//This greatest common divisor function is best remembered, very

HDU ACM 1292 "Xiasha Camel" ACM Summer Camp->DP

Analysis: A team of the situation, if the team has n people, there are n cases are a group, two groups, ... ;There are two ways to divide a person into groups of J:1, i-1 individuals into the J-1 group, the first person is divided into a group of independent; Dp[i][j]=dp[i-1][j-1].2, i-1 individuals into J Group, the first person to join any group of J Group; Dp[i][j]=dp[i-1][j]*j.3, so the state transfer equation is dp[i][j]=dp[i-1][j-1]+dp[i-1][j]*j.#include HDU ACM 1292 "Xiasha Camel" ACM Sum

Uestc_suibian Summer Camp Summary

Alas, finally team up, finally can only BB, I will BB, I will not on!Team up with Xiper and chenxh.Here is a summary:Day1The first day to eat and drink enough, and then on the road, I saw a C problem in the beginning, but I dare not imagine this problem incredibly water ... And the teammate BB a bit, then jumped, look at other questions, or a blood is mine and then teammates found a problem, the theoretical complexity of the estimate, is 10e8, feeling more Xuan, and then did not do, after the fa

Summer Camp-Basic graph theory

original is divided into two layers, if a to B has a weight of the side of C, then A to B ' has a C/2 side, so that the shortest time to do is the answer. Note that the edge is an integer, but the answer may be a decimal, preferably the edge.BBare minimum spanning tree.CKnights of the Round Table, classic questions, not yet done.DThe miner at the bottom.EEquivalence proof, to a given graph, ask at least how many edges of the programming strong connected graph.The strongly connected components a

2015 Peking University summer Camp Day1 B:an idea of Mr. A

Test instructions: Given a range l,r calculation i,j (iIdea: The application of the number of horses, so I was stunned that there were 123 people will do, I do not TM hair.In fact, any of the two coprime, that's all.1#include 2#include 3#include 4#include 5#include 6 #definell Long Long7 ll A, B;8 intMain () {9 while(~SCANF ("%lld%lld",a,b)) {Tenprintf"%lld\n", (A-B) * (a-b-1)/2); One } A}2015 Peking University summer Camp Day1 B:an idea of M

! HDU 1243 Counter-terrorism training camp--dp--(longest common sub-sequence)

Test instructions: give you a bullet sequence and a terrorist sequence, only the bullets hit the corresponding serial number of terrorists to score, each terrorist has a corresponding score, to seek the maximum scoreAnalysis: The abstract model is the longest common sub-sequence, the direct set of formula: Dp[i][j] for the first time to hit J terrorist with the maximum score, note that this refers to the process from the starting state to the optimal solution, rather than the optimal solution of

The first stage of the summer camp "two" acquaintance of our friend

Wandering for a long time, will be eager to hometown, where is not prosperous, but always warm as spring, only because, there are a group of sweet people.Never knowing each other, we need to resist together;Cut the ice, only to the unimpeded;Expand, develop, develop;Develop relationships and grow friendships.Cohabitation corner, peers can be;Bucket, join hands Fang Yun;The light of the grain of rice, appreciate to cherish;The heart has the system, the line has the dependent, diligently moves for

Codeforces Gym 100676G Training Camp-like pressure DP

The main idea is to tell you to fix n courses, each course has a weight of w[i], in the K-day course to get k*w[i] of the learning points, give the curriculum and the relationship between the first course, to take the course must be completed prior to the course. Ask how many points you can learn.A very simple pressure DP (I also misled my teammates to write a two-dimensional t^t);Dp[s]: s binary is the maximum number of points that can be obtained in the selected course, in that state.If you le

Summer camp-Two minutes, network flow, 2-sat

)); Flow+=DFS (S, INF); if(Flow > Need)returnflow; } returnflow; } BOOLCheckfull (ints) { for(inti =0; I ){ if(Edges[g[s][i]].flow! =Edges[g[s][i]].cap) { return false; } } return true; }};Mcmfstructedge{intU,v,c,cost,next;} Edge[e];inthead[v],cnt;voidinit () {CNT=0; memset (Head,-1,sizeof(head));}voidAddedge (intUintVintCintCost ) {edge[cnt].u=u;edge[cnt].v=v;edge[cnt].cost=Cost ; EDGE[CNT].C=c;edge[cnt].next=head[u];head[u]=cnt++; EDGE

Summer Camp-the third game of training

ID Origin Title 31/51 Problem A HDU 4175 Class Schedule 27/140 Problem B HDU 4193 Non-negative Partial Sums 5/17 Problem C HDU 4212 Shut the Box 3/9 Problem D HDU 4216 Computational Geometry? 2/3 Problem E HDU 4219 Randomization? Problem F HDU 4234 Moving Points

David Camp WeChat Public platform development official content Expansion version---PHP version qq WeChat public platform development WeChat public platform developer WeChat public platform development difficult

Public platform Development (i) Configuration interface Public platform Development (ii) Public Platform sample Code analysis Public platform Development (iii) subscription event (subscribe) processing Public platform Development (iv) Simple reply function development Development of Public Platform (v) forecast function development Development of public Platform (vi) Translation function development Public platform Development (vii) Chat robot function development Public platform Develop

Ecug Community promoter Xu Xiwei: The choice of programming language regardless of the camp, it's about taste

language tightly linked together, once upon a while, many people think that seven cows choose Go language is a very bold decision. How should programmers choose the right programming language? How to learn effectively in the face of a new language? There is no correct programming language, only the appropriate language. Choosing a language requires a decision based on your understanding of the problem domain to be solved. Of course, this matter is also related to taste, different languages actu

Fifth week of Camp D LCS

common substring, record the selected characters, the final output is good#include"Iostream"#include"CString"UsingNamespace Std;StringA[110];StringB[110];StringC[110];int DP[110][110];int D[110][110];IntMain(){int L1-ls;While(CIN>>a[1]){L1=2;While(A[L1-1]!="#") CIN>>a[L1++]; L1-=2; Cin>>b[1]; L2=2;While(b[L2-1]!="#") CIN>>b[L2++];Memset(DP,0,sizeof(DP));Memset(d,0,sizeof(d));For(int I=1; I; I++)For(Int J=1; j; j++){If(A[I]==b[j]){DP[I][j]=dp[I-1][j-1]+1; D[I][j]=3;}Else{If(DP[I-1][j]>dp[I][j-1]

The sixth week of the camp e question

E-Expectations (classic question)Time Limit:1000MSMemory Limit:32768KB64bit IO Format:%lld %llusubmit StatusDescriptionGiven a dice with n sides and you had to find the expected number of times you had to throw this dice to see all I TS faces at least once. Assume that's the dice is fair, that's means when you throw the dice, the probability of occurring any face is equal.For example, for a fair, and sided coin, the result is 3. Because When you first throw the coin and you'll definitely see a n

2015 Beijing University software Engineering excellent college students summer camp on the machine exam---A: the element maximum span value of an integer sequence

Describe Given a sequence of non-negative integers of length n, calculate the maximum span value of a series (maximum span value = maximum value minus minimum value). Input A total of 2 rows, the number of the first action sequence N (1 Output the output line that represents the maximum span value for the sequence. Sample input 63 0 8 7 5 9 Sample output 9 This is the first si

2016NOI Winter Camp Day0

I wrote a question in the morning.After noon packed things happily after the old driver drove the taxi came to the beautiful Nanshan High school!!! :)There were so many volunteers that we were a little embarrassed ... :)Came to the bedroom, saw the rumor of the Quilt Empty (Kong4) tune (Diao4), WOC This is not the summer cover??? :(Turn over the handout, 80% can not understand 90% do not test: (The boring waves over the afternoon, fortunately dinner good, self-help:)The opening ceremony was to

Summer Camp-Training 9th

ID Origin Title 8/22 Problem A HDU 4358 Boring counting 35/52 Problem B HDU 4359 Easy Tree DP? 31/79 Problem C HDU 4362 Dragon Ball 1/2 Problem D HDU 4363 Draw and Paint 18/56 Problem E HDU 4365 Palindrome graph 3/17 Problem F HDU 4367 The War of Virtual world

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