adendorff cipher

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[bzoj1031] [JSOI2007] Character encryption cipher

string.Sample InputJSOI07Sample OutputI0o7sjHINTThe length of the data string for 100% does not exceed 100000.Idea: a template title for the suffix array.We just need to copy this string to the back, and then handle the SA, which in turn outputs the starting point in the ranking.#include #include #include #include using namespace STD;#define N n*2-1Const intm=200100;CharCH[M];intn,m=0, Sa[m],t1[m],t2[m],c[m];voidBuild_sa () {intI,p,k,*x=t1,*y=t2; for(i=0; i0; for(i=0; i for(i=1; i1]; for(i=n-1;

BZOJ1031: [JSOI2007] character encryption cipher

]]--]=i; intln=1, p=0; while(pN) {intk=0; for(inti=n-ln+1; ii; for(intI=1; iif(sa1[i]-ln>0) sa2[++k]=sa1[i]-Ln; memset (Rsort,0,sizeof(Rsort)); for(intI=1; i; for(intI=1; i1]; for(inti=n;i>=1; i--) sa1[rsort[rank[sa2[i]]]--]=Sa2[i]; for(intI=1; iRank[i]; rank[sa1[1]]=1;p =1; for(intI=2; i) { if(tt[sa1[i]]!=tt[sa1[i-1]]|| tt[sa1[i]+ln]!=tt[sa1[i-1]+LN]) p++; Rank[sa1[i]]=p; } LN*=2; m=p; }}intMain () {scanf ("%s", A +1); intN=strlen (A +1); for(inti=n+1; i1; i++) a[i]=a

bzoj1031 [JSOI2007] character encryption cipher

\ (S[sa[i] + n-1] (s=input+input,sa[i]#include #include #include #include #include #include #include using namespaceStd#define N 200001#define REP (I, A, b) for (int i = A; I #define DRP (i, A, b) for (int i = A; I >= b; i--)#define LL Long Longinline intRead () {intx =0, flag =1;Charch = getchar (); while(!isdigit (CH)) {if(! (ch ^'-')) flag =-1; ch = getchar (); } while(IsDigit (ch)) x = (x 1) + (x 3) + CH-' 0 ', ch = getchar ();returnx * FLAG;}intNCharIn[n];intS[n];intSa[n], T1[n], t2[n], c[

[Cipher] [ArchLinux] [Disk Encryption] [Btrfs] Disk partition encryption + Btrfs

]~/MNT # Touch Txt[email protected]~/mnt # VIM txt [email protected]~/mnt # cat txt123456[email protected]~/mnt # ls123Txt[email protected]~/MNT # lltotal4-rw-r--r--1Root root0June2 on: $ 123-rw-r--r--1Root root7June2 on: $Txt[email protected]~/MNT # CD.5. Uninstall shutdown[Email protected] ~~ ~ # ll/dev/0crw1236 June 1:Third, encrypt the whole systemHttps://wiki.archlinux.org/index.php/Dm-crypt/Encrypting_an_entire_systemThere are various ways to include boot partition encryption and so on.

Solution to the failure of "Linux" non-cipher SCP in crontab

First, Reason:Before because the server can only login, and limit the root account login, so ssh through all the server, to achieve the public key forward SCP free password, etc., greatly facilitate the management of the server.Recently there is a need to do offsite backup of data. The simplest use of SCP script, but script manual execution is OK, put crontab does not work properly.Second, the solution:Script execution failed, immediately thought to print verbose log debug, that scp-v then read

"Bzoj" 1031: [JSOI2007] character encryption cipher (suffix array)

http://www.lydsy.com/JudgeOnline/problem.php?id=1031It is easy to think of this as copying the string to its end and then the suffix array out of the SA and output by the interval.Then change the template and put the cardinal sort outside#include Suffix array of the original: #include    DescriptionLike to delve into the problem of JS classmate, and recently fascinated by the encryption method of thinking. One day, he suddenly came up with what he thought was the ultimate encryption: to

bzoj1031: [JSOI2007] character encryption cipher suffix array

Because it is a ring, it can be reproduced in the back again.#include   bzoj1031: [JSOI2007] character encryption cipher suffix array

Ucenter cipher algorithm rules and Generation methods

other system's user name and password calculation, import ucenter uc_members table, to achieve user migration. For example, if the original system uses an algorithm such as MD5 (password) to save the password, then the program randomly generated salt, and then calculate the cumulative MD5, so it is easy to calculate the user in the Ucenter user password hash value, so as to achieve seamless user migration. However, if the original system is using MD5 (Password+salt) to save the password, it wil

Des cipher algorithm

The code puts this aside for backup.#include Des cipher algorithm

Large field of view 1031-character encryption cipher (suffix array)

given:07jsoi-->07+......+i7jsoi0-->7+......+0I07jso-->i07+......+ojsoi07-->jsoi07+ (7)Oi07js-->oi07+......+sSoi07j-->soi07+jyou can see that 07,7,i07,jsoi07,oi07,soi07 is all the suffixes of the original string, so we only need to sort these suffixes when sorting. This will use the suffix array. Note: Because it is annular, it is necessary to first copy the multiplication string, get the new string, and giveNew StringThe first half of the sequence, and then output each in the multiplication aft

UVa 306/poj 1026 Cipher (permutation group)

306-cipher Time limit:3.000 seconds Http://uva.onlinejudge.org/index.php?option=com_onlinejudgeItemid=8category=115page=show_ problemproblem=242 http://poj.org/problem?id=1026 Bob and Alice started to use a brand-new encoding scheme. Surprisingly it is isn't a public Key cryptosystem, but their encoding and decoding are based on the secret keys. They chose the secret key at their's last meeting into Philadelphia on February 16th, 1996. They chose

Laravel No supported Encrypter found. The cipher and/or key length is invalid

Error Laravel Access No supported Encrypter found. The cipher and/or key length is invalid Go to project directory, enter commandBuild configuration file PHP Artisan Key:generate Tips [Errorexception] File_get_contents (/USERS/WXX/PHPSTORMPROJECTS/XXLARAVEL/.ENV): Failed to op en stream:no such file or directory Tip No. env fileGo

Uva1339-Cipher ent Cipher

Question:Given two strings with the length of N, determine whether the 26 letters can match one by one. That is, after a one-to-one ing, the two strings are the same. Input two strings and output yes or no. Ideas:You only need to determine

POJ 1026 Cipher (permutation group) _ Combinatorial Mathematics

Description Bob and Alice started to use a brand-new encoding scheme. Surprisingly it is isn't a public Key cryptosystem, but their encoding and decoding are based on the secret keys. They chose the secret key at their's last meeting into

The technique of displaying text hint function code _javascript based on JS implementation cipher box (password)

In fact, actually implementation can not let password display text hint, but we have such a demand in the work, when there is no input, the box is prompted to enter the password, but when the input of things and shows the * number, then how to

PHP generates random cipher functions (four sections)

Method One The code is as follows Copy Code function Generate_password ($length = 8) {    //password character set, you can add any character you need     $chars = ' Abcdefghij

Apple iphone5 set Complex cipher graphic method

The iphone's simple password is usually made up of 4 digits, and complex passwords can contain special symbols and letters, and passwords are not limited in length and have a high level of security. The input of the password is to unlock the screen

Jing Dong Net Silver wallet method of setting gesture cipher

1, in the mobile phone into the east and then find the screen under the screen silver wallet and then open into the account to find-security after the entry, details below. 2. After entering, you will see a gesture password. Here we re-enter the

Caesar cipher, decrypted by Caesar encryption.

Using System; Using System.Collections.Generic; Using System.ComponentModel; Using System.Data; Using System.Drawing; Using System.Linq; Using System.Text; Using System.Windows.Forms; namespace Caesararithmetic {public partial class Frm_main:form

A brief talk on the way of Discuz cipher encryption _php Example

When Discuz registers, the password is encrypted according to a rule. Like my code is 123456. Copy Code code as follows: echo MD5 ("123456"); Will output: Copy Code code as follows: e10adc3949ba59abbe56e057

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