afa cyberpatriot

1#include 2#include 3 #defineM 20000004 intcnt,fa[m],n,m,ans[m],k,f[m],a[m],head[m],next[2*m],u[2*M];5 intZhaointA1)6 {7 if(a1==FA[A1])8 returnA1;9fa[a1]=Zhao (fa[a1]);Ten returnFA[A1]; One } A voidJiaintA1,intA2) - { -cnt++; thenext[cnt]=HEAD[A1]; -u[cnt]=A2; -head[a1]=CNT; - return; + } - intMain () + { Ascanf"%d%d",n,m); at for(intI=1; i) - { - inta1,a2; -scanf"%d%d",a1,A2); -a1++; -a2++; in Jia (A1,A2); - Jia (a2,a1); to } +scanf"%d",k); - fo

(A +1, a+m+1, CMP); - for(intI=1; ii; Wu intk=1, t=0; Memset (d,0,sizeof(d)); memset (s),0,sizeof(s)); - for(intI=1; i) About { $ intFX=FINDFA (a[i].x), fy=Findfa (A[I].Y); - if(a[i].c!=a[i-1].C) s[k]=i-1, k++;//record the last position of the K-type edge - if(fx!=fy) - { Afa[fx]=fy; +t++;d [k]++; the } - } $s[k]=m; the if(t!=n-1) {printf ("0\n");return 0;} the for(intI=1; ii; the

the same connected block).Analysis: Offline, delete as insert, each use and check set maintenance connected block number.Code:1#include 2#include string.h>3#include 4 using namespacestd;5 #defineN 4000506 intn,fa[n],m,q[n],ans[n],cnt;7 inthead[n],to[n1],nxt[n1],vis[n],k;8InlinevoidAddintUintv)9 {Tento[++cnt]=v;nxt[cnt]=head[u];head[u]=CNT; One } A intFindintx) - { - intp=Fa[x]; the while(P!=fa[p]) p=Fa[p]; - while(x!=2) { - inttmp=Fa[x]; -fa[x]=p; +x=tmp; - } + r

]; - - //0 - voidInit () + { - for(intI=0; i) + { Afa[i]=i; atcnt[i]=1; - } - } - - intFindset (intx) - { in returnFa[x]!=x? fa[x]=Findset (fa[x]): x; - } to + voidUnion_set (intXinty) - { the intxx=Findset (x); * intyy=Findset (y); $ if(XX==YY)return;//description Two elements are originally part of the same collection returnedPanax Notoginseng Else if(XX//if the root node of x is smaller than the root node of y -

Freshman:Before turning to professional in the NetEase cloud Open class to see MIT's line generation revenue is quite a lot,Sophomore last semester:NetEase Cloud on the AFA of C, repeatedly looked at five or six times, feel not difficult and always feel less what, later looked good bin (excellent specialist teacher) enlightened, saw two times. Good bin data structure is also good, because no such training institutionsBehind in the group of good Friend

of the currency1.txt AED Emirati dirham 1998-06-01 00:00:00.000 AFA Afghani 1998-06-01 00:00:00.000 ... ... ... ... ... ... ZWD Zimbabwe Dollar 1998-06-01 00:00:00.000 When you log in using a password, you need to enclose the-u username and the post-p password with double quotes. Note: In addition to being able to execute in the console, BCP can also run bcp in SQL statements by calling a system stored procedure of SQL Server xp_cmdshell. If the firs

; Mignoreblanklines = Ignoreblanklines; Mcurrent = null; } Public Linereader GetEnumerator () { return this; } public void Reset () { throw new NotSupportedException ("Linereaderö»äü¶áè¡ò»´î"); } String mcurrent; public string Current { Get { return mcurrent; } } public bool MoveNext () { Todo { Mcurrent = Mreader.readline (); }while (mignoreblanklines mcurrent!= null mcurrent.length = 0); return mcurrent!= null; } public void Dispose () { Mreader.close (); } } } Test code: Using System; Using

System_user ();SELECT Current_User ();SELECT Current_User;Returns the character set of the string strSELECT CHARSET (' AFA ');SELECT last_insert_id (); Last entry insert record ID number5. Cryptographic functionsMD5 ()PASSWORD ();SELECT MD5 (' ROOT ');SELECT PASSWORD (' ROOT ');Password encryption for user passwordsSELECT * from user WHERE user= ' root ' \g;Add password password to add permissions6. Process functionsIFSELECT IF (3>1, ' A ', ' B ');SE

character set of the string strSELECT CHARSET (' AFA ');SELECT last_insert_id (); Last entry insert record ID number5. Cryptographic functionsMD5 ()PASSWORD ();SELECT MD5 (' ROOT ');SELECT PASSWORD (' ROOT ');Password encryption for user passwordsSELECT * from user WHERE user= ' root ' \g;Add password password to add permissions6. Process functionsIFSELECT IF (3>1, ' A ', ' B ');SELECT id,username,if (age>18, ' adult ', ' underage ') from employee;SE

264px #d9d9d9, 691px-11px #ebebeb, -622px 402p X #c2c2c2, 219px 396px #f0f0f0, -149px-423px White, -716px-78px #d9d9d9, -590px 341px #e6e6e6, -208px 79px #d6d6 D6, -227px-24px #f7f7f7, 239px 262px #d1d1d1, 740px 443px #f7f7f7, 509px 134px #d6d6d6, -555px 232px #e8e8e8, -67px-427p X #cfcfcf, -368px 250px #f7f7f7, 715px-415px #fafafa, 411px-301px #f0f0f0, -322px 287px #d9d9d9, -429px-90px # F2F2F2, -327px-387px #f0f0f0, -491px 183px #c2c2c2, -133px 250px #d4d4d4, 538px 139px #e3e3e3, -417px-125px

4. system functions Select version (); current database VERSION SELECT CONNECTION_ID (); number of connections to the current server Current database: Select database (); Select schema (); Current user Select user (); SELECT SYSTEM_USER (); SELECT CURRENT_USER (); SELECT CURRENT_USER; Returns the STR character set. Select charset ('Afa '); SELECT LAST_INSERT_ID (); id of the last insert record 5. encryption functions MD5 () PASSWORD (); SELECT MD

SYSTEM_USER (); SELECT CURRENT_USER (); SELECT CURRENT_USER; Returns the STR character set. Select charset ('afa '); SELECT LAST_INSERT_ID (); ID of the last insert record 5. encryption functions MD5 () PASSWORD (); SELECT MD5 ('root '); Select password ('root '); PASSWORD encryption for user passwords SELECT * FROM user WHERE User = 'root' \ G; Add a PASSWORD when adding Permissions 6. Process Functions IF Select if (3> 1, 'A', 'B '); SELECT id,

* from tableName" // db2 imports table data to a file Db2 "import from fileName. del of del insert into tableName" // import the data in the file to the table in db2 4. Check whether the table exists in DB2 select*from"SYSIBM"."SYSTABLES"wherelower(name)='afa_maintransdtl' 5. Solve the db2 lock table problem: Db2 "connect to afa" Db2 "get snapshot for locks on Instance name" Db2 "terminate" View the related information, find the locked table,

(0 OutputThe output should is printed on the standard output. For each given input data set, print one, integer number in a, gives the result (the minimum number of sold Iers). An example are given in the following:Sample Input40: (1) 11: (2) 2 32: (0) 3: (0) 53: (3) 1 4 21: (1) 02: (0) 0: (0) 4: (0)Sample Output12SourceSoutheastern Europe 2000a simple tree DP, state transition equation: Basically the same as the last question .　　DP[NODE][0]+=DP[TREE[NODE][I]][1]; 　Dp[node][1]+=min (dp[tree[nod

]=np,p=Fa[p]; - if(!p) fa[np]=1; + Else{ - intq=Ch[p][c]; + if(len[q]==len[p]+1) Afa[np]=Q; at Else{ - intnq=++cnt;len[nq]=len[p]+1; -memcpy (Ch[nq],ch[q],sizeof(Ch[p])); -fa[nq]=fa[q];fa[q]=fa[np]=NQ; - while(ch[p][c]==q) -ch[p][c]=nq,p=Fa[p]; in } - } to } + }sam; - CharSTR1[MAXN],STR2[MAXN]; the intMain () * { $ intlen1=0, len2=

DescriptionOnly one output, is the minimum length of fiber connected to each farm and.Sample input to sample40 4 9 214 0 8 179 8 0 1621 17 16 0Sample outputSample Output28Data range and TipsData Size HintTest instructions: Minimum spanning tree: kruscal template topic Note WA Point1#include 2#include 3#include 4#include 5#include 6#include 7 using namespacestd;8 structnode9 {Ten intl; One intR; A intv; -}n[11000]; - intfa[101]; the intN; - intJishu; - intEXM; - BOOLcmpstructNode

Else { - intq=Ch[p][c]; - if(l[p]+1==L[Q]) fa[np]=Q; - Else { + intNq=++sz; l[nq]=l[p]+1; -memcpy (Ch[nq],ch[q],sizeof(Ch[q])); +fa[nq]=Fa[q]; Afa[np]=fa[q]=NQ; at for(;p q==ch[p][c];p =fa[p]) ch[p][c]=NQ; - } - } - } - - intN,t,b[n],cnt[n]; in - voidget_sum () { to for(intI=1; i; + for(intI=1; i1]; - for(inti=sz;i>=1; i--) b[cnt[l[i]]--]=i; the for(inti=sz;i;i--)

][ the][1010], fa[ One][ the][1010];7 intN, K0, M, N2, N3, sum, ans;8 intP1, Q1, R1, p2, Q2, R2;9 intFINDF (intXintYintz)Ten { One if(Fa[x][y][z]! =z) AFA[X][Y][Z] =findf (x, Y, fa[x][y][z]); - returnFa[x][y][z]; - } the intMain () - { - while(SCANF ("%d%d%d", n, k0, m)! =EOF) - { +N2 = n *K0; -n3= N2 *K0; + for(inti =1; I i) A for(intj =1; J j) at { - for(intK =1; K k) -

Made a simple music player. With open files inside the computer, select songs to playThe main purpose is to master, open the folder, select the file's　　1 Private voidFrm_load (Objectsender, EventArgs e)2 {3Skinengine1.skinfile ="Diamondblue.ssk";4 5MediaPlayer1.settings.autoStart =false;//disable playback on load6Mediaplayer1.url ="f:\\qqpcmgr\\desktop\\ player \\MUSIC\\1.mp3";7 }8 //generic collection, which is used to load the full path of a music fil

Algorithm Essentials: the most difficult point of the Kruskal algorithm is how to determine whether to join the edge (x, Y) after the formation of a ring.The problem can be as follows: judging the two vertices x, y of the Edge (x, Y) is the most connected in the graph (actually forest) Mst. If it is already connected, the joining Edge will form a ring;In the Kruskal algorithm, the merging and finding of the set is Used.and check the Set:1 intGETFA (intK//find the most ancestors2 {3 if(fa[k]=