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and all 11.2, the offending SQL statements from involved sessions will be written in the trace. for earlier version or if there is no SQL statements in the trace, apply patch 6343023 or use step 6 to gather system state dump.Here are some common deadlock types:1. TX deadlock in exclusive (x) modetrace shows: Global wait-for-graph (WFG) at DDTs [0.170]: Blocked 0x8aafb0ec 5WQ 2 cvtops X1 TX0x320001. 0x121c97 [99000-0001-00000002] 0 Blocker 0x8aafafec 5WQ 1 cvtops

In C ++, the usage of New is very flexible in C ++. Here is a simple summary: "') X5 T # D/S # V) v9 n w! J 1. New () allocates a memory space of this type and initializes this variable with the value in parentheses;. u * t, V #~ % U 2. New [] allocates n Memory Spaces of this type and uses the default constructor to initialize these variables. 8 A6 r I) '6g % m L # Include . | 1 U "Q6 Z (y '? /V3 R A1 ~ # Include ) W $ t/m, X8 N6 V9 qusing namespace

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= segment Selector (16-bit) + offset (32-bit)So addressing the 80386CPU is based on the previous 8086 addressing approach, as described in the Linux kernel source scenario analysis:Can be simply recorded as: Segment Register (segment selector) → address segment description structure (segment descriptor) → address from base address → instruction + base address = Physical locationThe address segment describes where the structure (segment descriptor) comes from: Add two registers to the CPU, one i

Here's may find useful information:=====================x8---------------------------------8x=============================http://yysfire.github.io/linux/%E4%BB%8E%E6%BA%90%E4%BB%A3%E7%A0%81%E5%88%B6%E4%BD%9Cdeb%E5%8C%85%E7%9A%84%E4% B8%a4%e7%a7%8d%e6%96%b9%e6%b3%95%e4%bb%a5%e5%8f%8a%e4%bf%ae%e6%94%b9%e5%b7%b2%e6%9c%89deb%e5%8c%85.html=====================x8---------------------------------8x================

This.charat (k)-anotherstring.charat (k) If there are no different index positions for characters, the dictionary order of shorter strings is preceded by a longer string. In this case, COMPARETO returns the difference between the lengths of the two strings, which is the value: This.length ()-anotherstring.length () specified by: compareTo parameter in interface comparable: anotherstring-String to compare. returns a value of 0 if the argument string is equal to this string, and returns a value

sampling 864 sample points, for NTSC system is 858 sample points. Since each line in the TV signal includes a certain synchronous signal and a back sweep signal, the effective sample point of the image signal is not so much, CCIR 601 provides for all the standard, the effective sample point of each line is 720 points. Because different formats have different valid rows per frame (PAL and SECAM are 576 lines, NTSC is 484 rows), CCIR defines 720x484 as the basic standard for HDTV HDTV (High Defin

MySQL mysql 1304 Apr 23:47 MySQL-RW-RW----1 mysql mysql 203 Apr 03:47mysql-bin.000001-RW-RW----1 mysqlmysql 107 Apr 03:47 mysql-bin.000002 #时间和操作前的是一样的, confirm that no Binlog log is written-RW-RW----1 MySQL mysql Apr 03:47mysql-bin.indexsrwxrwxrwx1 mysql MySQL 0 Apr 03:47mysql.sock-rw-r-----1 mysql root 23291 Apr 03:47mysql_oldboy3307.err-RW-RW----1 MySQL mysql 5 Apr 03:47mysqld.pid-RW-RW----1 MySQL mysql 03:47relay-bin.000005-RW-RW----1 mysqlmysql 494 APR 04:02 relay-bin.000006 #证明从库已经写rela

graphics driver and disable Windows automatic GPU driver installation [in Windows].Create a manual restore point, just in case there is a startup problem [in Windows]. (I did not do this step)Select view by connection in Device Manager, and then locate the PCIe controller x8-1905 to disable it in [Windows].Close and then connect the EGPU (with an external display) to one of the Thunderbolt 3/usb-c ports on the right. (I can only connect to the right,

mode will find the Linux root partition on the hard disk and mount it to the "/mnt/sysimage/" folder in the disc directory structure.After entering the "sh-3.1" shell environment, execute the "chroot/mnt/sysimage" command to switch the directory structure to the Linux system to be repaired. Then re-establish the new grub.conf configuration file.grub.conf files in the normal host[Email protected] ~]# cat/boot/grub/grub.conf...default=0timeout=5splashimage= (hd0,0)/grub/ Splash.xpm.gzhiddenmenuti

/** * Fls-find last (most-significant) bit set * @x:the Word to search * * This is defined the same as a FFS. * Not E FLs (0) = 0, FLS (1) = 1, FLS (0x80000000) = 32. */Static__always_inlineintFLsintx) { intR = +; if(!x)return 0; if(! (X 0xffff0000u) ) {x -; R-= -; } if(! (X 0xff000000u) ) {x8; R-=8; } if(! (X 0xf0000000u) ) {x4; R-=4; } if(! (X 0xc0000000u) ) {x2; R-=2; } if(! (X 0x80000000u) ) {x1; R-=1; } returnR;}The function is

returns a small value, otherwise you can determine the existence of the edge.You can blur the edges after you find the edges.Blur EdgeThe Blur Edge is for super sampling, taking the surrounding pixels and then blendingPeople often see, for example, ssaax2,ssaax4,x8 .... The number that follows is the count of the sample points.Previously translated super-sampling on a wikiThere are many ways to blur the edges (sampling), and there are several more po

Example: There are 100 text money, to buy 100 chickens, Rooster 5 A, hen 3 article A, chick three only one article, ask the Rooster hen how many chickens each? Method One:1 #!/usr/bin/env python2 #-*-coding:utf-8-*-3 forAinchRange (100//5+1):4 forBinchRange (100//3+1):5 forCinchRange (0, 100*3+1, 3):6 ifA + B + C ==100 7 andA*5 + b*3 + (C//3) * = = 100:8 Print('gj:%3d mj:%3d xj:%3d'% (A, B, c))Execution Result:gj:0 mj:25 xj:75Gj:4 mj:18

rootRed 8x8led dot-matrix screen OneDuPont Line several3, 8x8 lattice screen introductionThere are two rows of pins behind the lattice, a row with 1, that is, 1-8 pins, a row with 9 (8 pins are the opposite of the pin), that is, 9-16 pins, the number within the circle is the corresponding serial number of the PIN. The corresponding PIN for ROW 1 is 9. When a row's pin is high, and a Col's pin is low, the LEDs of their intersection are lit. To facilitate the operation of rows and columns, we can

statement has been changed to the EXEC () functionFor example:2.x:print "The answer is", 2*23.x:print ("The answer is", 2*2)2.x:print X, # Stop line wrapping with a comma end3.x:print (X, end= "") # Use a space instead of a newline2.x:print # Output New Line3.x:print () # Output New Line2.x:print >>sys.stderr, "Fatal error"3.x:print ("Fatal error", File=sys.stderr)2.x:print (x, y) # output repr ((x, y))3.x:print ((x, y)) # is different from print (x y)!7) Change the behavior of the order operat

(constchar*name, mode_t mode, structdentry *parent, u16 *value);structdentry *debugfs_create_x32(constchar*name, mode_t mode, structdentry *parent, u32 *value);structdentry *debugfs_create_size_t(constchar*name, mode_t mode, struct dentry *parent, size_t*value);structdentry *debugfs_create_bool(constchar*name, mode_t mode, structdentry *parent, u32 *value); Where the three functions suffix x8, x16, and x32 refer to the data in Debugfs in hexad

The number of surveillance cameras that need to be recorded, such as 6 cameras needed to save video, is 6. Calculation method: Single-day Video size = main stream (M) ÷8x3600 (sec) x24 (hour) x channel number ÷1024 Video days = hard disk Capacity (G) x1024x coefficient x8÷3600 (seconds) ÷24 (time) main stream (M) Number of channels such as: 1 1080P camera, 4M main stream of the day video size: 4÷8X3600X24X1=43200M≈42GB Note: The following provi

that this 16-bit CRC polynomial is better than the previous Const unsigned long cncrc_32 = 0X04C10DB7; //CRC-32 = X32 + X26 + X23 + X22 + X16 + X11 + X10 + X8 + X7 + X5 + X4 + X2 + X1 + X0 unsigned long table_crc[256]; CRC Table //Constructed 16-bit CRC table void BuildTable16 (unsigned short apoly) { unsigned short i, J; unsigned short ndata; unsigned short naccum; for (i = 0; i { ndata = (unsigned short) (I naccum = 0; for (j = 0; J {

= Regex.Replace (M.value, @ "Sec-websocket-key: (. *?) RN "," $ "). Trim (); } byte[] encryptionstring = SHA1. Create (). ComputeHash (Encoding.ASCII.GetBytes (key + "258EAFA5-E914-47DA-95CA-C5AB0DC85B11")); return convert.tobase64string (encryptionstring); } If the handshake succeeds, the client's OnOpen event will be triggered.Resolve received client informationThe client data parsing rules are received as follows:1byteBit:frame-fin,x0 indicates that the message is followed by a

Mount the new hard disk after the input fdisk-l command to see the current disk information can be seen in addition to the current first hard disk and a second hard disk SDB, and then partition into the Fdisk command with FDISK/DEV/SDB, enter H can see the help of the command, to partition by N here the input e is divided into logical partition, according to P that is divided into the main partition, we want to divide this disk into primary partition is input p to enter the primary partition as