aline alignment

Research on css baselines: Implementation of vertical alignment-good, bad, and ugly, css baselines This may be because of the lack of understanding and appreciation of the baseline mesh, or because the baseline mesh is notoriously hard to implement. So far no one has taken the blueprint for its successful implementation. Some people even think that baselines are redundant on the network. As a Typographical term and network behavior, baselines follow d

(1) starting address of each member % alignment value of each member = 0. If the value is not equal to 0, the byte is null until the expression is true;(2) The overall length of a struct must be an integer multiple of its own alignment values. If it is not enough, the byte is left blank. # Pragma pack (8) Struct { Char; Long B; }; For struct a, its own alignment

In C Programming, sometimes in order to achieve the purpose of reducing the running time, there is a need to waste some space, and sometimes in order to save space, so that its running time to grow. The byte alignment is to gain access to efficiency and to use space in exchange for time. To master byte alignment, you first need to make a clear four concepts:1. Self-aligning values of the base data typeThe

variable4: alignment access of the structThe first thing to know is that we use. The way to access the struct is different considering the structure of the internal alignment problem, this part of the compiler will help us to deal with, but if we want to use pointers to access the structure of the elements inside the time we need to consider the memory alignment

http://blog.csdn.net/embeddedman/article/details/7429976First, a program introduces the topic:1//Environment: VC6 + Windows SP22//Procedure 13#includeiostream>45UsingNamespaceStd67structSt18{9CharA10 Intb;11ShortC12};1314structSt215{16ShortC17CharA18Intb;19};2021stIntMain ()22{23cout"sizeof (ST1) is"sizeof(ST1)Endlcout"sizeof (ST2) is "sizeof(st2)Endl; return 0 ;+ } - The output of the program is:sizeof (ST1) is 12sizeof (ST2) is 8The problem comes out, these two same structur

This memory alignment problem actually affects the result value of sizeof (struct). Suddenly think of a previously written API library, there is an API to the background service program to send a socket request. The socket packet is a struct. The length of the data is detected before the socket is sent, and the length is detected after the server receives the data. If the memory alignment problem affects th

Alignment rules in C ++ What is alignment?In C/C ++, the member variables of data structures or classes are not arranged one by one in a compact manner based on their sizes. They are arranged according to a specific method and may insert one or more bytes between two member variables, to ensure that the starting position of each member variable starts from a specific position. This is

Yesterday look at Q3 code, see there is a _intsaizeof macro, really dizzy a burst. Google, finally understand that the role of this macro is to find out the size of variables to occupy memory space, first look at the definition of _intsaizeof it:#define _intsizeof (n) ((sizeof (n) + sizeof (int)-1) ~ (sizeof (int)-1))(ANSI C standard, _intsaizeof macro definition in stdarg.h, Q3 defined in bg_lib.h; bg_lib.h--Standards C library replacement routines used by code)About the internal principle o

When using the sizeof operator to calculate the space occupied by a struct, it is not simple to add up the space of all the elements in the struct, which involves the problem of memory byte alignment. In theory, access to any variable can be accessed from any address, but in fact it is not, in fact, access to a specific type of variable can only be accessed at a specific address, which requires the individual variables to be arranged in space accordin

Byte alignment To enable the CPU to efficiently and quickly access variables, the starting address of the variable should have some features,That is, "alignment ". For example, for a 4-byte int type variable, its starting address should be on the 4-byte boundary,That is, the start address can be divisible by four. Variable alignment rules are as follows