Objective
I believe you all know it,. amr format for mobile device audio, compression compared to larger, more for the voice, call, the effect is OK! So, the mobile device uses AMR format to record and save more! A more common example: Call recording, micro-letter voice and recording, etc.!
But this ghost, in two words to describe, is "egg pain", because HTML5 does not support it (
Test instructionsn number, each time you can choose a number to make it *=2 or/=2Ask at least how many times the operation makes all the numbers equal.Ideas:For each number, calculate the number that the number can be converted to, and the smallest number of steps to change to, save with two arraysCnt[i] indicates that the number of CNT in a sequence can be changed to IStep[i] The number of those that can become I is the cost of I and how much.Which, when encountered odd times to special treatme
how many times 2. Of course, the direct calculation can also be divided by 2 until the base value equals Base[j]. But the outer layer has already used the N*log (n) complexity, so here we divide the number of times divided by 2 by 2 points. A maximum of 10W can be divided by 16 times 2. So the complexity of the dichotomy is log2 (16) = 4 is almost equal to O (1). This can be done because, if I divide by 2^k and the base value is smaller than base[j], then dividing by a value greater than 2^k wi
Topic linksTest instructionsGiven n-long sequencesEach time you can choose a number to make it *=2 or/=2Ask at least how many times the operation makes all the numbers equal.Ideas:For each number, calculate the number that the number can become, and the minimum number of steps to change to that number.Cnt[i] indicates that the number of CNT in a sequence can be changed to IStep[i] The number of those that can become I is the cost of I and how much.Notice:if A[i] = = 7, A[i] also can reach 6. by/
This b is not difficult ... It's mostly test instructions and details.Test instructions is to find the most occurrences of the number of the left and right end of the value,, as many words to find the smallest interval,,, the same length of the left to find ...Change a little bit messy,,,, slowly change well,,,,,#include #include #include #include using namespace Std;struct node{int c,b;}A[100001];int cmp (const void *a,const void *b){struct node *q= (node*) A;struct node *w= (node*) b;if (q->c!
CONTENT:
* AMR Introduction
* AMR Voice quality Assessment
* AMR File Structure analysis
* AMR Frame structure Analysis
* AMR frame reading algorithm
* AMR decoding principle and process
* AMR
Tags: nbsp release jsb solve problem pil bit name SSO tryReprint: http://blog.csdn.net/sanshipianyezi/article/details/78742621Reprint: http://blog.csdn.net/szfhy/article/details/50441162Under Linux for the conversion of WAV and AMR, if it is AMR to wav only need ffmpeg can but if WAV to AMR will need to rely on ffmpeg and Opencore_amrnb library.Complete: http://d
Recently to do a project, to the mobile phone app on the file upload to the server, including pictures, sounds, video files. At first only the Android version, as you know, Android's recording format Amr, can not play out on the computer, must be transcoding. Because previously only the Android version, so the use of Jave to facilitate the solution. But then the iphone version was added and the recording format was CAF. Jave supports dozens of audio a
PHP Windows environment can convert AMR format to MP3 format ask the great God for advice
Reply content:
PHP Windows environment can convert AMR format to MP3 format ask the great God for advice
PHP is not good at this thing, even if it can be written, but also slow to dieThis kind of thing or a C or something to fix it, you can first a class library through PHP calls, but also better to use Gearman
in ms. The minimum unit of the voice frame is 20 m. The data size for every 20 ms is 320 bytes. Of course, this is 16 bit, 8 kHz.
How to calculate it.
Okay. Let's talk about the encoding and deepen your understanding of this aspect:
After the 320-byte PCM-16 speech is encoded, the programming length is 13 bytes, that is, the voice format of AMR Nb. If we want to play it through audiotrack, we have to use amrdecoder to decode and restore these 13 b
Recording AMR files less than 1 minutes, dozens of K, using your own server conversion is more convenient than uploading to Ali or seven kn processing.1, installation ffmpeg apt-get install FFmpeg2, ffmpeg only MP3 decoding no coding tool, Apt-get install Libmp3lame-dev installed this MP3 encoded open-source third-party library It doesn't seem to work.Ffmpeg-codecs viewing existing encoding and decoding formatsUnloading:First sudo apt-get remove ffmpe
Codeforces Amr and Chemistry (Mathematics + chaos)
Question: give n numbers. Each number can be multiplied by two or divided by two (the downward integer is equivalent to the left or right shift). Ask how many operations can make the n numbers disguised.
Idea: first consider the possible values of each number, and express a number in the form of s * 2 ^ k. s is an odd number.
Then all values of this number may be s '* 2 ^ x, (s' = s/2, (s/2)/2 ,.....)
Codeforces 558C Amr and Chemistry rules
Question Link
Question:
Given n-long sequence
You can select a number to make it * = 2 or/= 2.
Ask how many operations are performed to make all numbers equal.
Ideas:
For each number, calculate the number that can be changed to and the minimum number of steps.
Cnt [I] indicates that the number of cnt in the sequence can be changed to I
Step [I] indicates the cost and the amount of I that can be changed to I.
Not
Title Link: Http://codeforces.com/problemset/problem/558/BTitle meaning: Give a sequence, and then find the most occurrences, but the interval occupies the shortest interval around the value.Because it is a side-read-in-edge comparison, the most critical issue is to record where each number first appears, that is, the left value. Because you want to ensure that the number of occurrences is the most, you need a cnt[] array to record the number of occurrences. Then, when the maximum number of occu
Test instructions: The number of n, each can be multiplied by two or divided by two (rounding down equivalent to left or right), ask at least how many operations can make this n number disguised.Idea: First of all consider the possible value of each number, a number is represented as s*2^k form, S is odd.Then all possible values for this number are S ' *2^x, (S ' =s/2, (S/2)/2,.....) and S ' *2^xBecause the data range is small, and each value may not be a maximum of hundreds of, so record 1 to 1
CodeForces 558C Amr and Chemistry (bitwise operation, number theory, rule, enumeration), codeforces558c
Codeforces 558C
Question: give n numbers. You can perform two operations on each number: num * 2 and num/2 (rounded down: the minimum number of operations required to make n equal.
Analysis:
Calculates the binary common prefix of each number.
The enumeration method is also supported.
/**Author : Flint_x *Created Time : 2015-07-22 12:33:11 *File nam
This is a simple script I wrote in Perl to convert between AMR AND DIFERENT audio formats (WAV, Midi MP3 ). my script has this input/output digoal :. -----------. --> | mid/mod | '----- + -----' | timidity | V v. ---------.. -------------.. -------.. -----------.. -------. | + -- mp123-> | + -- encode-> | + -- ifs2amr-> | MP3 | WAV |
http://xa.bi/mms/
Http://blog.csdn.net/dinggo/archive/2007/12/29/2002298.aspx
AMR Audio Codec
Table of Contents 1. Overview 2. AMR Code 3. AMR decoding 4. AMR frame reading algorithm 5. Resources
1. Overview
Many smartphones now support multimedia features, especially audio and video playback, and the
First, what is AMR file?
AMR (Audio/modem Riser, Voice/modem card) is an open industry standard that defines an expansion card that can support both sound and modem functions. This kind of design can effectively reduce the cost and simultaneously solve some limitations on the function of voice and modem subsystem.
AMR (full name is Adaptibve multi-rate), in add
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