an8mal jam

Test Instructions:LinkMethod:Rotating Jamparsing:It's like the POJ2079 triangle. So the idea is actually a train of thought. But notice that the subject is to look for the four-sided shape, if you find three moving points, it seems unrealistic. So we enumerate diagonal words, there must be a point diagonally up and down, and found the point below the counter-clockwise rotation, the above point is actually counterclockwise. So according to the idea of rotating

1. Pull out the paper disk 1.2. Gently pull out the paper jam and make sure all the paper in tray 1 is aligned.If the paper is not moved when pulling, or there is no paper in this area, click here to query the video operation of the machine's internal paper jam.3. Load the paper disk 1 back to the printer and directly card it in place. The printing work will be automatically restored.1. Remove the stuck

Gently pull the paper from the tray.If you do not see the paper jam or are struggling to pull it, stop the operation and go to step 2. Step 2. Remove the back cover paper jam1. Open the back cover.2. Press the pressure bar on both sides.3. After seeing the paper jam, gently pull it out.4. Push the pressure lever back to the initial position.5. Close the back cover and the printing will be automatically rest

Convex hull rotating jam to find the maximum triangular areaMaximum triangleTime limit:5000/2000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 3316 Accepted Submission (s): 1119Problem description Teacher in the computational geometry of this class to decorate a topic for Eddy, the title is this: given a two-dimensional plane on the n different points, required to find three points in these points, so that they const

Although I didn't think about the prize or the t-shirt from the very beginning when I participated in Goole code jam The ending is too speechless. I can skip the qualifying round. I think I still have a few hopes to enter rund 2. In three rounds of rund 1, the first one was not done because the invitation to participate in the BGI Invitational competition. The game started ............ First of all, I miss the first game. Of course I want to finis

Example:It cannot be printed. The machine screen displays "machine internal paper jam ".Original cause:Paper gets stuck inside the printer.The solution is as follows:1. Click the release button, open the front cover, and pull the toner cartridge.2. Gently pull out the stuck paper.3. Reinstall the cartridge and close the front cover. The print will be restored automatically.You can also click here to refer to the "machine internal paper

new "point to heel Point-edge" pair (or when two lines are coincident with the edge, "Edge-edge" pair) is generated at this time. Calculates the new distance, and compares it with the current minimum value, which is less than the current minimum. 5. Repeat step 3 and step 4 (jam) until the original parallel edge is reached again. 6. The pair of the minimum value to be obtained as the pair output to determine the width. The more intuitive algorithm is

http://blog.csdn.net/ACMaker/archive/2008/10/29/3176910.aspx http://cgm.cs.mcgill.ca/~orm/rotcal.frame.html History: In 1978, the paper "Computational Geometry", M.i Shamos's Ph.D, marked the birth of this field of computer science. What he was doing was a very simple algorithm for finding the diameter of a convex polygon, which is determined by the maximum value of a pair of points of a polygon.Later, the diameter evolved to be determined by a pair of pairs of heel points. Shamos presents a

N, the rest of the newline is still in the input buffer, to use the nextline () function to remove it for(inti=0;i) {Pool[i]=reader.nextline ();//read all the strings in the dictionary} printwriter writer=NewPrintWriter (out); intMatchcount=0; Pattern Pleft=pattern.compile ("\ \ ("); Pattern Pright=pattern.compile ("\ \)"); for(inti=1;i) {String patstr=reader.nextline ();//read a ciphertext, the following processing will process it into patternMatcher mleft=Pleft.matcher (PATSTR); Stri

http://lx.lanqiao.cn/problem.page?gpid=T94Test instructions: Gives the s,t,wThe maximum character is T, which generates the next arrangement, simulating the T-binary +1, because the permutation is to be strictly incremented by the minimum increment dictionary order of the first J characters, which is the maximum of ' a ' +t-(W-j) J-character +1, and increments from that bit to the last letter, with a tolerance of 1　　Algorithm training Jam counting met

#include #include using namespace Std;int s,t,w,a[30],time=5;Char c[30];BOOL Ok;//ok Indicates whether the specified set is found;void data_in ()//Use bit vector method;{scanf ("%d%d%d", s,t,w);scanf ("%s", c);for (int i=0;iA[c[i]-96]=1;}void DFS (int x,int len){if (x>t){if (len==w){if (!ok) {Ok=1;return;}if (time>0){time--;for (int i=s;iprintf ("\ n");}}Return}for (int i=1;i>=0;i--) if (len{if (OK){A[x]=i;DFS (X+1,len+i);}if (!ok) if (a[x]==i) DFS (x+1,len+i);if (time==0) return;}}int main (){F

, we only guarantee the less than or equal to N in the a=1 plane.But don't worry, because the rest of the B-direction is legal, because our method of construction is equivalent to translating the plane of A=1 into a B-direction as a grows.In this way, the construction is completed, and the coordinates of the selected cube are found so that the output can be achieved.#include #includeusing namespacestd;intA, B, C, n;voidWork () {if(c N) {printf ("%d\n", A * b *c); for(inti =1; I ) fo

Test instructions: give you a sequence from 0-n initial position of 0, only from I walk to i+1 you need to have the number >= i+1, each location has a[i] individual, ask you how many people you need to go to N.Problem-Solving ideas: violenceProblem Solving Code:1 //File name:a.cpp2 //Author:darkdream3 //Created time:2015 April 11 Saturday 23:06 57 seconds4 5#include 6#include 7#include 8#include Set>9#include Ten#include One#include A#include -#include -#include the#include -#include -#in

problem Is the enumeration, I think so ...At that time the feeling may time out, also thought the composite decomposition .... I didn't do it at the end. It's a lot of thought.PS: If you know the following, then this problem is much easier ...For a polynomial like ax²+bx+c, the Δ=B²-4AC can be used to determine whether it can use the cross decomposition method to decompose the form. When Δ is a full-squared number, the polynomial can be multiplied by a cross-range of integers.C. Enumera

Topic Link: UVA 12307-smallest enclosing RectangleThe two pairs of heel-to-point circumference are rectangular, and the minimum values of all feasible rectangles are enumerated.#include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. UVA 12307-smallest enclosing Rectangle (rotating jam)

Topic Link: Click to open the linkTest instructions: give you a n*n matrix. The number of palindrome from (n,n) to be made.Idea: At first, the state was written as a d[x][y][s],s of a string, with a map, and later found extremely infeasible, because this state is simply too big, including the s string of all cases. Just a pruning in DFS.Later thought, in fact, the string is not necessary to record, we just count the number, so it may be in the DP process to judge the case of palindrome, then you

Topic Link: Click to open the linkTest instructions: There is a balance without a cursor, and n steelyard weight scales, m ask, each time a k, ask can weigh the weight of k. Steelyard weight scales can be placed on both sides.Idea: Because n is maximum 20, a subset of violent enumerations. Because you can put both sides, so each time run again, minus each weight, save the answer.The game forgot to limit the boundaries, although the final test data, but by the people with Big Data hack (RE), or t

Problem DescriptionJam has a math problem. He just learned factorization. He is trying to factorizeAx^2+bx+cAX?2??+BX+C into the form ofpqx^2+ (QK+MP) x+km= (px+k) (qx+m)PQX?2?? +(qk+mp)x+km=(px+k) (qx+m). He could only solve the problem in which p,q,m,k is positive numbers. Please help him determine whether the expression could is factorized with P,q,m,k being postive. InputThe first line was a number tT, means there is t (1 \leq t \leq)T(1≤t≤

Topic: Given a set of points, any choice of four points constitute a convex polygon, to find the largest area of convex polygonEnumerates the diagonal of a quadrilateral, one point at a time, and another point on the diagonalEach time you find the point that is farthest from the diagonal on both sides of the diagonal, the movement of the points on both sides is monotonous and can therefore be maintained with a rotating jamIn addition, the area of the quadrilateral is calculated by dividing the a

LK's Travel time limit: -Ms | Memory Limit:65535KB Difficulty:5 Describe LK recently traveled to some places, she planned a few points on the map, and with a pen point out, ready to travel to these cities during the 51 holidays. Now I want you to find out what the distance between all the points in her point is the farthest from the two points. The various attractions can be thought of as being on a flat surface. Input The