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End Goole code jam journey in the form of sorrow ~~~~

Although I didn't think about the prize or the t-shirt from the very beginning when I participated in Goole code jam The ending is too speechless. I can skip the qualifying round. I think I still have a few hopes to enter rund 2. In three rounds of rund 1, the first one was not done because the invitation to participate in the BGI Invitational competition. The game started ............ First of all, I miss the first game. Of course I want to finis

Samsung laser black and white printer ML-3750ND machine screen shows "machine internal paper jam", how to solve

Example:It cannot be printed. The machine screen displays "machine internal paper jam ".Original cause:Paper gets stuck inside the printer.The solution is as follows:1. Click the release button, open the front cover, and pull the toner cartridge.2. Gently pull out the stuck paper.3. Reinstall the cartridge and close the front cover. The print will be restored automatically.You can also click here to refer to the "machine internal paper

Width of the---convex hull of a rotating jam

new "point to heel Point-edge" pair (or when two lines are coincident with the edge, "Edge-edge" pair) is generated at this time. Calculates the new distance, and compares it with the current minimum value, which is less than the current minimum. 5. Repeat step 3 and step 4 (jam) until the original parallel edge is reached again. 6. The pair of the minimum value to be obtained as the pair output to determine the width. The more intuitive algorithm is

Rotation Jam (calculates the two points farthest from the convex polygon)

http://blog.csdn.net/ACMaker/archive/2008/10/29/3176910.aspx http://cgm.cs.mcgill.ca/~orm/rotcal.frame.html History: In 1978, the paper "Computational Geometry", M.i Shamos's Ph.D, marked the birth of this field of computer science. What he was doing was a very simple algorithm for finding the diameter of a convex polygon, which is determined by the maximum value of a pair of points of a polygon.Later, the diameter evolved to be determined by a pair of pairs of heel points. Shamos presents a

On the marketing factors of soft text from the "jam" of soft-wen marketing

Soft Wen Marketing, a listen to understand, is writing with the nature of the article, and then let the potential customers see, and then achieve the purpose of marketing. But personally, I began to look for soft marketing tips, experienced a continuous period of time. Many of these areas have been caused by "jam." The so-called jam is not to say that write no article, when a person will write as a career,

Google code jam exercise -- Store Credit

I recently learned about Google Code Jam, a programming competition project. After logging on to the project, I can see the previous questions. I think they are all very interesting. So I 'd like to try it out. The first question I saw was Store Credit, which probably meant giving you a certain amount of money, then giving you an item price list, and choosing two items, just to spend all the money. Specific content can refer to the http://code.google.

Google Code jam -- Bad horse

; for ( int i=0; i { if (!n->adj[i]->visited) { n->adj[i]->groupId = 3 - n->groupId; q.push(n->adj[i]); } else { if (n->adj[i]->groupId == n->groupId) return false ; } } } return true ; } ~Graph() { for ( int i=0; i { delete nodes[i]; } } }; int main() { freopen ( "gcj_bad_horse_small-practice-2.in" , "r" , stdin); freopen ( "output.out" , "w" , stdout); int input_count; cin >> input_count; int counter = 1; while (input_count) { //do work int M; cin >

BZOJ3575[HNOI2014] Road Jam

].v,cost=edge[i].cost)if(!Ban[i])if(pos[v]>=Lim) {if(vis[v]!=ci) vis[v]=ci,sta[++top]=v,val[v]=dis[u]+cost+Suc[pos[v]]; Elseupmin (Val[v],dis[u]+cost+Suc[pos[v]]); } Else if(dis[u]+costDis[v]) {Dis[v]=dis[u]+Cost ; if(VIS[V]!=CI) Que.push (v), vis[v]=CI; }} re (I,1, top) S.insert (MP (Val[sta[i]],sta[i)); }intMain () {Freopen ("road.in","R", stdin); Freopen ("Road.out","W", stdout); inti; N=gint (); M=gint (), l=Gint (); Re (i,1, m) {intU=gint (), V=gint (), cost=gin

POJ3608 (rotating jam-finding the closest point-to-distance of two convex packets)

[i+1],p[i+2]);if (tmp>eps) return;else if (tmp{Reverse (p,p+n);Return}}}Calculates the shortest distance from point C to line ABDouble Getdist (Point a,point b,point C){if (Dist (A, b) if (multi (a,b,c) if (multi (b,a,c) Return Fabs (Cross (a,b,c)/dist (A, b));}Find the distance between the two ends of a line to another line, in turn, a total of 4 casesDouble Mindist (Point a,point b,point c,point D){return min (min (getdist (a,b,c), Getdist (a,b,d)), Min (Getdist (c,d,a), Getdist (c,d,b)));}Dou

Google Code Jam Contest-2016-April-09th

, -,4, -,6, -, and8, respectively. in case #4, Bleatrix would name One, A, -, -, -, the, the, the, About, theAnd then fall asleep. Case #5 isThe one describedinchThe problem statement. Note that it would only show upinchThe Large dataset, and notinchThe Small dataset.View CodeAnswer:ImportJava.util.*;ImportJava.io.*; Public classMain { Public Static voidMain (string[] args)throwsfilenotfoundexception {fileinputstream fis=NewFileInputStream ("A-large.in"); PrintStream out=NewPrintStream (NewFile

"Rotating Jam" POJ 2079 Triangle

], p[i], st[top-1]) 0) thetop--; +St[++top] =P[i]; - } $ } $ - DoubleA (point A, point B, point C) { - returnFabs (Cross (A, B, c))/2; the } - Wuyi Doublecal () { the covexhull (); - intp =0, q =1, r =2; Wu DoubleArea =A (St[p], st[q], st[r]); - while(true) { About intPP = p, qq = q, rr =R; $ while(Fabs (Cross (st[(R +1)% n], st[q], st[p])) >Fabs (Cross (St[r], st[q], st[p])) { -Area = max (area, A (st[(R +1) %N], St[q], st[p]); -R = (R +1) %N; - }

Google Code Jam Qualification Round B enumeration + greedy

Test instructions: give you an infinite number of columns and some values other than 0, you can do two things.1) All values greater than 1 in the sequence are reduced by 12) Remove any value from a[i] to any person.Ask you how many steps you can take at least to make the sequence all 0.Problem Solving: Enumerate the largest a[i]. The parts larger than a[i] are divided.Problem Solving Code:1 //File name:b.cpp2 //Author:darkdream3 //Created time:2015 April 11 Saturday 23:16 58 seconds4 5#include 6

Rotating Jam Templates

void cirandcut (point psn[],int. N,Point psm[],int m) {int nid=0, mid=0; for(int i=1; i if(Psn[i]. Y>psn[nid]. Y) {Nid=i;}for(int i=1; i if(Psm[i]. Y Y) {Mid=i;}//Find the top point in the point set n , and the bottom point in M. //l is a vector of horizontal right for(int ii=0; ii {//The first step is to determine who is going to roll. point nextn,nextm; Nextn = psn[(nid+1)%n]; Nextm = psm[(mid+1)%m]; if((Nextn-psn[nid)) * (PSM[MID]-NEXTM) >0 ) {//n, roll Fi

Bzoj 3575 Road Jam

[toit[i]] = dis[now]+len[i]+Suf[pos[toit[i]];Wuyi ElseVal[toit[i]] = min (val[toit[i]],dis[now]+len[i]+Suf[pos[toit[i]]); the } - Else if(Dis[toit[i]] > dis[now]+Len[i]) Wu { -Dis[toit[i]] = Dis[now] +Len[i]; About if(!inch[Toit[i]])inch[Toit[i]] =true, Team.push (Toit[i]); $ } - } - inch[Now] =false; - } A for(inti =1; I i) Ms.insert ((node) {stack[i],val[stack[i]]}); + } the -InlinevoidWor

VS2012 Offload: Speed up the start-up and reduce the editing jam

My company's notebook configuration is as follows:cpu:i5-3210m @ 2.50 GHz 2.50 ghzmem:4.00 gbos:64bit Win7A very good card when compiling cocos2d-x projects with VS2012. I couldn't stand it today, so I decided to lighten it.1. Click the "Tools" drop-down menu to open the "Options" panel--environment-friendly extensions and updates: Uncheck "Automatically check for updates" and "load per user extensions when running as administrator"-Environment--Startup: "Show empty Environment"--environment--au

Code Jam APAC Local onsites problem C. millionaire--probability DP

Test instructionsYou have x dollars for the M-wheel gambling game. Each round can be held by any part of the money as a bet (bet 0 yuan for this round), the bet can be fractional, not necessarily an integer. Each round wins the probability is P, wins the wager to double, loses the wager to be gone. If you finally hold at least 1000000 yuan, you can take all the money. It is required to calculate the probability of obtaining at least 1000000 yuan in the optimal strategy.Data range:0111 intM, X; 2

HDU 5617 Jam ' s Maze dp+ scrolling array

//scrolling arrays is a great place to pay attention!!! Initialize every time!!! Initialize!!! Initialize!!! theDp[x1][x2][u] =0; + - //if (i = = nx1! = x2) Continue; $ $ if(Str[x1][y1] = =Str[x2][y2]) { - //printf ("fuck!"); - intcur =Dp[x1][x2][u]; theCur = Add (cur, dp[x1][x2][!u]); -Cur = Add (cur, dp[x1][x2 +1][!u]);WuyiCur = Add (cur, dp[x1-1][x2][!u]); theCur = Add (cur, dp[x1-1

How do I clear the paper jam? (SL-M2876HN, SL-M2676FH)

Step 1. Clear the cards on the paper diskIf the machine is stuck in the paper area, open and close the front cover. The stuck paper will automatically exit the printer. If not, follow these steps:1. Pull out the paper tray.2. Gently pull out the paper jam.If you do not pull the paper jam, or there is no paper in this area, check the timer area near the toner box. (Click here to query the machine's internal paper extraction operations .)3. Load the

Laser black and white printer ML-2850D (ML-2851ND) how to clear paper area jam

1. Gently pull the paper from the tray.If you do not see the paper jam or are struggling to pull it, stop the operation and go to the next step.2. Open the back cover, press the pressure bar on both sides (back guide plate) and take out the paper, and push the pressure bar (back guide plate) back to the initial position.3. Close the back cover and the printing will be automatically restored.

Bestcoder Round #70 1001 Jam ' s math problem

Ideas: A,b,c are 10^9, direct multiplication will explode int, directly sentenced sqrt (B^2-4AC) is not equal to 0 of the integer can be #include Problem description Jam A math problem I want to ask you, he just learned to factorization for example, x^2+6x+5= (x+1) (x+5) x 2 +6x+5= (x+1) (x+5) is like a ax^2+bx+cax 2 +bx+c = pqx^2+ (qk+mp ) x+km= (px+k) (qx+m) PQX 2 + (QK+MP) x+km= (px+k) (qx+m) But he was stupid, he would only do p,q,m,kp

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