The title describes a ball from the M-meter height of the free fall, each landing after the return of the original height of half, and then fall. How high does it bounce when it lands on nth time? How many meters are there? Leave two-bit decimal input m n output how high does it bounce when it lands on nth time? How many meters are there? Keep two decimal places separated by spaces and put in one line sample input1000 5Sample output31.25 2875.00Hint Source#includeint main(){int m,n,i;float h,l=0
Programming | Tutorial 2.5 event handler function
said the usual events, in terms of two different ways of dealing with events. The event-handling code described earlier is added like this: First, select the object that will capture the event (the movie clip instance or button), and then open the script panel and write the "on event name" code. For example, if we want a movie clip instance to capture the
The title description has a fractional sequence: 2/1 3/2 5/3 8/5 13/8 21/13 ... The sum of the first n items of this sequence is calculated, and two decimal places are reserved. Input n output series top N and sample input10Sample output16.481#include"stdio.h"2 3 intMainintargcChar Const*argv[])4 {5 6 intN, M =2, n =1, I;7 floats =0;8scanf"%d", N);9 for(i =0; i )Ten { One intT; As + = (float) m/N; -t =m; -m = n +m; then =T; - } - -printf"%.2f\n", s); + return 0;
The title describes the sum of the following three numbers, preserving the 1~b of the sum of the squares and 1~c of the 2-bit decimal 1~a and the input a B c output 1+2+...+a + 1^2+2^2+...+b^2 + 1/1+1/2+...+1/c Sample input100 50 10Sample output47977.931 intMainintargcChar Const*argv[])2 {3 4 intA, B, C, I;5 floatS1 =0, S2 =0, S3 =0;6 7scanf"%d%d%d", a, b, c);8 9 for(i =1; I )Ten { OneS1 + =i; A } - - for(i =1; I ) the { -S2 + = i *i; - } - + for(i =1
The title description enters two integers, asking them to divide the remainder. Use a macro with parameters to implement, program. Input a b two number output A/b remainder sample input3 2Sample output11#include 2 #defineDivide (A, b) res = a% B;3 intMainintargcChar Const*argv[])4 {5 intA, B, res;6scanf"%d%d", a, b);7 8 Divide (A, b);9 Tenprintf"%d\n", res); One return 0; A}1037:c Language Programming Tuto
Problem DescriptionThis day the teacher again to small Hao out a topic: give you three lengths, respectively, A,b,c match, let you calculate the three matches can make up of the Triangle area.InputEnter each row to include three number a,b,c.OutputThe area of the output triangle for each row (reserved three decimal places), cannot be composed of triangles told the small Hao output "no!".Sample Input1 2 33) 4 5Sample Outputno!6.000HINT1#include 2#include 3 intMain ()4 {5 Doubles,a,b,c,p;6
Problem DescriptionThe teacher gave a title to Xiao Hao: give you a value of n (within 32 bits) in seconds, let you convert to: minutes: seconds output. Now that little Howe is in a quandary, please help him solve the problem.InputEnter a positive integer of n seconds per line.Outputfor each set of test data, output a row of results: minutes: seconds. (24-hour system)Sample Input560Sample Output00:00:0500:01:00HINT#include intHh,mm,ss;voidConvertime (Longsec) {hh=sec/3600; MM= (sec-hh*3600L)/ -;
The title describes the sum of the diagonal elements of a 3x3 matrix. Input matrix output main diagonal sub-diagonal element and sample input1 2 31 1 13 2 1Sample output3 71#include 2 3 intMainintargcChar Const*argv[])4 {5 inta[3][3], I, J;6 intDiagonal1 =0, Diagonal2 =0;7 8 //input9 for(i =0; I 3; i++)Ten { One for(j =0; J 3; J + +) A { -scanf"%d", a[i][j]); - } the } - -Diagonal1 = a[0][0] + a[1][1] +a[2][2]; -Diagonal2 = a[2][0] + a[1][1] +a[
The title description writes a function that enables a given two-dimensional array (3x3) to transpose, that is, the row and column interchange. Enter a 3x3 matrix output to transpose matrices sample input1 2 34 5 67 8 9Sample output1#include 2 3 4 voidConvertinta[][3],intRowintCol//two-dimensional array when making formal parameters, the second must be written5 {6 intI, J, temp;7 for(i =0; i )8 {9 for(j = i; J )Ten { One //Exchange A if(I! =j
Programming | Tutorial 2.6 Event Monitor
event has a habit, is "clique", under normal circumstances, some objects are not receive some events, such as a dynamic text can not accept mouse events. If we write code that specifies the event-handling code for a dynamic text:
Mytextfield_txt.onmousedown = function () {
}
when we click the mouse over it, the code does not execute because it does not re
Programming | Tutorials
1.3.4 Standalone script file
Open the menu "file-> new" and select "Action Script File" from the New Document dialog box to establish independence. As files, the biggest advantage of this file is that it can be reused. For example, the scripts you create in a project can be placed in a separate. As files, you can call this directly if other items use similar functionality. The code in the as file. This can greatly improve the
This article mainly introduces the Linux multithread programming detailed tutorial, provides the code which the thread realizes the communication through the signal quantity, everybody reference uses the bar Thread classification nbsp; threads can be divided into user-level and core-level threads according to their dispatchers. nbsp; (1) User-level thread nbsp; user-level thread is mainly to solve the pro
days floatmoney=0, Ave; while(n -) { money=money+0.8*N; Day++; N*=2;//N each x2} Ave=money/Day ;printf ("I'm a jerk, I buy apples every day.") I am Tao Tao I bought%d apples ", N/2);//Because n exits the loop because the n> or =100 is because the number of X is 2 so I have to/2 to get the amount of the Tao to buy apples printf ("The result is%.6f", Ave); return 0;} I'm a jerk. I buy apples every day. I'm Tao Tao, I bought 64 apples.//The result is 16.799999Code for the preparation of level
to a breakpoint will stop, we can use the mouse at the breakpoint at the various variables when we see the values of these variables.Debug->start without debugging means that it does not run directly without debugging, that is, it does not stop at the breakpoint.Debug->step into (shortcut key is F11) is used for stepping, encountered sub-function to enter and continue stepping;Debug->step over (the shortcut is F10) is also single-step, but when stepping, when you encounter a child function with
OpenMP Tutorial: https://computing.llnl.gov/tutorials/openMP/#ProgrammingModel
Understanding the OpenMP programming model is the first step in learning OpenMP.
(1) shared memory, thread based Parallelism:
OpenMP is a parallel model based on shared memory and threads.
(2) Explain It Parallelism:
OpenMP is clear about parallelism rather than automatic parallelism. Provide parallelFull Control.
code, the thread can call the object's Wait () method, release the object lock flag, enter the wait state, and call the Notify () or the Notifyall () method to notify other threads that are waiting. Notify () notifies the first thread in the wait queue. Notifyall () Notifies all threads waiting on the queue.The Wait () and notify () mechanisms provided in Java are as follows:Called by thread 1 synchronized method1 (...){//Access data variable available = true; Notify ();} Called by thread 2 syn
Python programming for loop statement learning tutorial, pythonfor
A Python for loop can traverse any series of projects, such as a list or a string.Syntax:The syntax format of the for Loop is as follows:
for iterating_var in sequence: statements(s)
Flowchart:Instance:
#! /Usr/bin/python #-*-coding: UTF-8-*-for letter in 'python': # First Instance print 'current letter :', letterfruits = ['bana', 'apple',
. Start the terminal40. Enter the pathwatermark/2/text/ahr0cdovl2jsb2cuy3nkbi5uzxqvaxrjyxn0y3bw/font/5a6l5l2t/fontsize/400/fill/i0jbqkfcma==/ Dissolve/70/gravity/southeast "/>41. Compile and run42. Write a C + + code 1,CC43. Print statements, C + +44. Print out the results45. Drive HelloWorld#include #include Module_license ("Dual BSD/GPL");//Follow the Linux protocolstatic int hello_init (void){PRINTK (Kern_alert "Hello, world\n");//Print driver informationreturn 0;}static void Hello_exit (void
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