It seems a bit of a headache, but it's easier to figure out the rules:1. The version number is different from the current number, then compare, return-1 or 12. The version number is the same as the current number, then the subsequent number is compared. such as 1.1:1 large, but 1.0 and 1 are the same; but 1.0.1 is bigger than 1.It's not too long to write a good code: D.Class Solution {Public:int compareversion (string version1, String version2) {while
Calculates the MD5 value in the/etc directory for the file to be tampered with, following the command:find/etc/-maxdepth 1-type F | Xargs-n1 md5sum>/root/etc_sum-$ (date +%f). logThe same truth,We can/usr/bin/usr/sbin//usr/local/bin/root/bin and so on the important directory of the file checksum is calculated once, so that the regular execution of the command, generate a new checksum, Compare the generated log file with the original md5sum.log by usin
--warn: When checking, check the input MD5 information is not illegal line, if any, output the corresponding information.4. Example(1) The MD5 value of a file is produced as follows:[ROOT@LINUXIDC www.linuxidc.com]# md5sum p182 > Cc.txtIn this way, to produce the file p182 MD5 check file cc.txt, open Cc.txt can see the following:[ROOT@LINUXIDC www.linuxidc.com]# Cat Cc.txtdd05e55e3aca2d39e49a1a7d1b3fd404 p182(2) Check whether two files are the same, you can
Compare numbers version1 and version2.If version1 > version2 return 1, if version1 version2 return-1, otherwise ret Urn 0.Assume that the version strings is non-empty and contain only digits and the . character.The . character does not represent a, decimal point and was used to separate number sequences.For instance, was not "both and 2.5 a half" or "half-to-version three", it is the fifth Second-level revision of the S Econd first-level revision.Here
Compare numbers version1 and version2.If version1 > version2 return 1, if version1 version2 return-1, otherwise ret Urn 0.Assume that the version strings is non-empty and contain only digits and the . character.The . character does not represent a, decimal point and was used to separate number sequences.For instance, was not "both and 2.5 a half" or "half-to-version three", it is the fifth Second-level revision of the S Econd first-level revision.Here
To compare the size of two numbers, customize the method of comparing the size of two integers:
Returns 1 if the first number is large
Returns 0 if equal
If the first number is small, return-1
Enter a two number in the main () method to call this method
Example:
Please enter two number:4556The second number is a largePress any key to continue ...1 usingSystem;2 usingSystem.Collections.Generic;3 usingSyste
Compare numbers version1 and version2.If version1 > version2 return 1, if Version1 version2 return-1, otherwise return 0.Assume that the version strings is non-empty and contain only digits and the.Character.The.Character does not represent a decimal point and was used to separate number sequences.For instance,2.5is not "both and a half" or "half-to-version three", it is the fifth Second-level revision of the second first-level re Vision.
Compare numbers version1 and version1.If version1 > version2 return 1, if version1 version2 return-1, otherwise ret Urn 0.Assume that the version strings is non-empty and contain only digits and the . character.The . character does not represent a, decimal point and was used to separate number sequences.For instance, was not "both and 2.5 a half" or "half-to-version three", it is the fifth Second-level revision of the S Econd first-level revision.Here
#include using namespace Std;int main (){float sum=0.0;for (int i=0;i{sum=sum+0.01;}coutif (sum==0.1){cout}Else{cout}return 0;}/*Summary:1) Running results0.1Not equal2) explanationThrough analysis, the expression sum==0.1, while mathematically true, is not true in the program.The reason is that the finite precision of a floating-point type causes rounding errors to be introduced in a repeating accumulation operation, soThe results in the program are not equal3) Resolve:In general, when checking
Compare two versions of the size.Idea: Determine the size of the corresponding interval by separating the dots. Because of the length of the problem, there are 0 of the existence, so if one to the end of the other, if not, it may be assumed that the end of the interval after the value of "0".The Stoi () function is used. If the version in the interval is the same, and it is already at the end, then it is equal. Otherwise, always judge until two versio
Compare numbers version1 and version2.If version1 > version2 return 1, if version1 version2 return-1, otherwise ret Urn 0.Assume that the version strings is non-empty and contain only digits and the . character.The . character does not represent a, decimal point and was used to separate number sequences.For instance, was not "both and 2.5 a half" or "half-to-version three", it is the fifth Second-level revision of the S Econd first-level revision.Here
Array_intersect_key () computes the intersection of an array using the key name comparison
functionThe function will return an array,The array contains all of the values in array1 but not in any other parameter array."Scope of Use"php5>php5.1.0.UseArray Array_intersect_key (array array1, array array2[,array ...])array1/Required/Array 1array2/required/Compared arrays must have at least oneArray.../Optional/used to compare the arrayExample[PHP]
Defi
ARRAY_INTERSECT_UASSOC () with index check the intersection of the computed array, and use the callback function to compare the index
functionThe function will return an array,The array contains all of the values in array1 but not in any other parameter array.Note that unlike the Array_intersect () function, the key name is also used for comparison."Scope of Use"PHP5.UseArray Array_intersect_assoc (array array1, array array2[,array...,callback Key_co
Array_intersect_ukey () computes the intersection of an array using a callback function to compare the key names
functionThe function will return an array,The array contains all the values in array1 but not the key names in any of the other parameter arrays.This comparison is done through a user-supplied callback function.If you think that the first parameter is less than, equal to, or greater than the second argument, you must return aAn integer les
Compare numbers version1 and version1.If version1 > version2 return 1, if version1 version2 return-1, otherwise ret Urn 0.Assume that the version strings is non-empty and contain only digits and the . character.The . character does not represent a, decimal point and was used to separate number sequences.For instance, was not "both and 2.5 a half" or "half-to-version three", it is the fifth Second-level revision of the S Econd first-level revision.Here
Compare numbers version1 and version1.If version1 > version2 return 1, if version1 version2 return-1, otherwise ret Urn 0.Assume that the version strings is non-empty and contain only digits and the.Character.The.Character does not represent a decimal point and was used to separate number sequences.For instance,2.5is not "both and a half" or "half-to-version three", it is the fifth Second-level revision of the second first-level re Vision.Here are an
Comparing strings and numeric stringsTo compare strings (type C) and numeric literals (type N), you can use the following operators in logical expressions.CO contains onlyCN contains not onlyThe CA contains anyNA does not contain anyCS contains stringNS does not contain stringsCP include modeNP does not contain patternsBecause except for types N and C, the system cannot perform any other type conversions,When calculating one of the comparisons, the op
Compare numbers version1 and Version2.If Version1 > Version2 return 1, if Version1 Assume that the version strings is non-empty and contain only digits and the. Character.The. Character does not represent a decimal point and was used to separate number sequences.For instance, 2.5 are not "both and a half" or "half to version three", it is the fifth Second-level revision of the SEC Ond first-level revision.Here's an example of version numbers ordering:
Problem Definition:Compare numbers version1 and version2.If version1 > version2 return 1, if version1 version2 return-1, otherwise ret Urn 0.Assume that the version strings is non-empty and contain only digits and the . character.The . character does not represent a, decimal point and was used to separate number sequences.For instance, was not "both and 2.5 a half" or "half-to-version three", it is the fifth Second-level revision of the S Econd first-level revision.Here are an example of version
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