apply for fidelis

Apply ()Apply (M,dimcode,f,fargs) M is a matrix. DimCode is the dimension number, 1 is applied to the row, and 2 is the function for the column. F is a function Fargs is an optional parameter set for F > z > f + x/c(2, 8)+ }> apply(z,1,f) #f函数得到两个元素，则为几行，竖着来的 [,1] [,2] [,3][1,] 0.5 1.000 1.50[2,] 0.5 0.625 0.75Lapply ()Lapply ()

Why What's call,apply,bind doing? Why do you want to learn this?This is typically used to specify the environment for this, which is usually the problem before it is learned.var a = { User: "Chasing the Dream", fn:function () { console.log (this.user); }} var B = a.fn;b (); UndefinedWe want to print the user in object A but print out what's going on with the undefined? If we directly execute A.fn () is possible.var a = { User: "Chas

Why What's call,apply,bind doing? Why do you want to learn this?This is typically used to specify the environment for this, which is usually the problem before it is learned.var a = { User: "Chasing the Dream", fn:function () { console.log (this.user); }} var B = a.fn;b (); UndefinedWe want to print the user in object A but print out what's going on with the undefined? If we directly execute A.fn () is possible.var a = { User: "Chas

Original address: http://www.cnblogs.com/pssp/p/5215621.htmlWhy What's call,apply,bind doing? Why do you want to learn this?This is typically used to specify the environment for this, which is usually the problem before it is learned.var a = { User: "Chasing the Dream", fn:function () { console.log (this.user); }} var B = a.fn;b (); UndefinedWe want to print the user in object A but print out what's going on with the undefined? If we d

Call (Thisobj,arg1,arg2 ...), apply (Thisobj,[obj1,obj2 ...]) These two methods are non-inherited methods that are included in each function Call (thisobj[, args]) and apply (thisobj[, args)) function is the same, in simple terms is to change the current use of this method in the object of this point, point to the calling method of the Thisobj object the difference between the two (the first argument is t

Category: Angularjs JavaScript 2014-08-20 13:49 13320 people read comments (3) Collection reportAngularjsjavascriptangularApply () and apply () and digest () are two core concepts in angularjs, but sometimes they are confusing. To understand how ANGULARJS works, you first need to understand how apply () and apply () and digest () work. This article is intended to

Apply: Methods can hijack another object's method, inheriting another object's properties. Function.apply (Obj,args) method can receive two parametersOBJ: This object will replace the This object in the function classArgs: This is an array, which is passed as a parameter to function (args-->arguments) Call: Same as apply, except that the argument list is not the same. Function.call (o

This is the SQL Server Help documentation for the description of apply:Use the APPLY operator (version 2005 or later) to invoke a table-valued function for each row returned by an external table expression that implements a query operation. The table-valued function acts as the right input and the outer table expression as the left input. The resulting row is combined as the final output by evaluating the right input for each row in the left input. Th

This article was reproduced from: Https://www.jianshu.com/p/e5d801b936b6Premise: Generate Patch: git format-patch-m master generates the specified patch, 0163BED3BF59AE74C36CC5138B4C24F1556D8304 is a commit id,-1 is the start of the current ID, the number of commits down, including this and the count starting from 1. that is, I want to 0163bed3bf59ae74c36cc5138b4c24f1556d8304 the current patch, then: git format-patch 0163bed3bf59ae74c36cc5138b4c24f1556d8304-1 To make a patch

The new APPLY table operator applies the right table expression to each row in the left table expression. Unlike JOIN, it can calculate the table expression first. APPLY must calculate the left expression logically first. The logic order of input calculation allows the right expression to be associated with the left table expression. APPLY has two forms: outer

If you encounter this feeling when learning JavaScript, a free and ever-changing language, let go of your "prejudice ", because this is definitely a new world for you, let the cyber Crip slowly melt the previous set of solidification programming consciousness, inject new life!Well, let's get down to the point. First, let's understand the context feature of JavaScrtipt's dynamic transformation runtime. This feature is mainly reflected in the application and call methods.Differentiate

This, call, apply in JavaScript and their usage and differences are described in detail. javascriptapply Learning cause: In the previous JavaScript study, this, call, and apply are always confusing to me, but they are widely used. It took a special day to understand JavaScript's this, call, and apply. There are also a lot of books to be referenced in the middle,

Problem:What is the difference between 1.apply and call?2. Under what circumstances use apply, and under what circumstances callOther clever uses of 3.apply (generally under what circumstances you can use apply)I first looked at the definition of apply and call from the Inte

Role:Replaces this in the method of the current object.Understand:Call and apply are used to dynamically change The this occurrence, when an object does not have a method, but others have, we can use call or apply the method of other objects to operate.The DOM node chosen by document.getElementsByTagName is a type of array that is similar to array.It cannot apply

A simple understanding of call in Javascript and the ability to apply javascript to object orientation was later added. For compatibility, many strange things were made, Function Animal () {this. name = "Animal"; this. showName = function () {alert (this. name) ;}} function Cat () {this. name = "Cat";} var animal = new Animal (); var cat = new Cat (); // use the call or apply method to convert the showNa

Help the company to apply for a developer program for nearly one months, has no time to tidy up, today to take a moment to put their own record of the process here to post ...Pretty pit, a full one months to apply down, and among them in the application of Deng's coding process appeared a number of problems also need to use English mail to Dunkleosteus coding company, Khan Ah, my English they can read ....T

= {Num:42};var second_object = {Num:24};function Multiply (mult) {return this.num * mult;}Multiply.call (First_object, 5); Returns 42 * 5Multiply.call (Second_object, 5); Returns 24 * 5Second, apply methodThe first parameter of the Apply method is also the object to pass to the current object, which is the this within the function. The arguments that follow are all arguments passed to the current object.Bo

= {num:42}; var second_object = {num:24}; function Multiply (mult) {return this.num * mult;} multiply.call (First_object, 5); Returns * 5 Multiply.call (Second_object, 5); Returns 24 * 52, apply method The first parameter of the Apply method is also the object to pass to the current object, which is the this within the function. The arguments that follow are all arguments passed to the current object. Both

Apply and call are important methods in JavaScript, and although programming is seldom accessible, the JS framework uses these 2 methods everywhere.These 2 methods are in Function.prototype, which means that each JS function has these 2 methods.Alert (Function.prototype.hasOwnProperty ("apply"));//truealert (Object.prototype.hasOwnProperty ("Apply");// FalseThe f

JS call method _ apply method _ caller attribute _ callee attribute Address: http://aweber.blogbus.com/logs/46751586.html I. Call MethodCall a method of an object to replace the current object with another object (in fact, it is to change the internal pointer of the object, that is, to change the content pointed to by this object ).JS Code Call ([thisobj [, arg1 [,Arg2 [,[,. Argn]) ParametersThisobjOptional. Will be used as th