array of function pointers c

The last time, we mainly described the basic concepts of arrays, pointers, pointer arrays, and array pointers,But one thing I did not mention last time is that we use typedef to define a pointer to an array.Array, this is not very easy to call, but we can see the specific program clearly. File: // ---------- array ----

#include intMainintargcChar**argv) { Char*s[Ten];//Array of pointers Char(*S1) [Ten];//Array Pointers//The previous one is an array of pointers, that is, the pointer is an adjective used to modify the

allocated memory space, or else an error will occur.Note:1, if the allocation of space is too large, the operating system can not find enough memory to meet, then the dynamic memory allocation will fail. The program throws an exception at this point.2, if an array is dynamically allocated, but is freed with the "delete pointer", without "[]", there is no problem at compile time, the runtime also generally does not have an error, but actually causes t

As for the relationship between pointers and arrays, it is estimated that there is some ambiguity about the relationship between the array and the pointer address, and I would like to make a small summary of this today.We already know the use of pointers and arrays is similar, but the address of the pointer and the pointer to the address is not the same, the addr

---restore content starts---#include intMain () {inta[8]={1,2,3,4,5,6,7,8};//I study number mantissa 4 definition a[8]int*p;//Defining Pointers for(p=a;p8);p + +)//define a For loop reduction step and an array a traversalprintf"%d\n", *p);//using the pointer output array } Summary: An error occurred in the middle when I defined the pointer *p and then redefined t

Four pointers and arrays1 define int *p;2 Initializing int a,*p=a;Give the address of a to *p.The pointer variable has whose address is pointing to WHO. The *p represents this variable. *P represents a3 operationint a,*p=a;*p=5; int *p,a;*p=[*]a;| Offset the*p NOTE: * Three uses 1 multiplication operation 2 operator 3 specifierDefine time to use such as int a,*p=a;A two-array character

Let's look at a program that uses the switch statement:#include look at a program that uses an array of function pointers#include When a switch judgment statement in the number of case, the above two programs are similar. However, using a function pointer array is much faster if there are many case.Similarly, in Java, you can use reflection to replace the Swith s

Today I saw an article under chinaunixArticleTo discuss the relationship between array names and pointers. The original post link is: Http://bbs.chinaunix.net/thread-871769-1-994.html I feel that the text written by the landlord is quite good, but the content is somewhat misleading. I would like to share some of my personal views here. Exp1: # Include Int main (INT argc, char * argv []){Char STR [10

#include intSump (int*,int*);intMainvoid){ intArray[] = {1,3,4,7,8}; printf ("total=%d\n", Sump (array,array+5)); return 0;}intSump (int* Start,int*end) { intTotal =0; while(startend) Total+ = *start++; returnTotal ;}Sump Method Description:1 Array name multi-hold pointer is the first address of the array2 Total + = *start++;start The prototype of the poin

The C language does not have the same string type as in Java, so in the C language, by using a character array to hold the string, in order to distinguish it from the normal character array, we need to add the trailing end of the stringAn end flag: ' \ s ', so, for example, a string: "Bht", the character array that holds the string is 4 long.Initialization of the