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Joal learning notes Class 8 oggvorbis format stream

int numChannels() {return decodedFormat.getChannels();}public float sampleRate() {return decodedFormat.getSampleRate();}public int read(byte[] pcm) throws IOException {return decodedAudioInputStream.read(pcm, 0, pcm.length);}public void dump() {System.out.println("dump!");}} Oggvorbisplayer. Java: Package COM. thrblock. openal; import Java. NIO. bytebuffer; import Java. util. arrays; import COM. jogamp. openal. al; public class oggvorbisplayer {//

Assembly Language hyper-concentration tutorial

to various models, we recommend that you use the 8086 assembly language with the best compatibility. All the languages mentioned in this article are 8086 assembly languages. Registers are internal components of the CPU, so data transmission between registers is very fast. Purpose: 1. perform arithmetic and logical operations on the data in the register. 2. The address stored in the Register can point to a location in the memory, that is, addressing. 3. It can be used to read and write data to p

Assembly Language hyper-concentration tutorial from lbsjs)

ensure that the assembler program is applicable to various models, we recommend that you use the 8086 assembly language with the best compatibility. All the languages mentioned in this article are 8086 assembly languages. Registers are internal components of the CPU, so data transmission between registers is very fast. Purpose: 1. perform arithmetic and logical operations on the data in the register. 2. The address stored in the Register can point to a location in the memory, that is, addressin

To grasp the true kill-free knowledge, you must understand assembly-[assembly language ultra-concentrated tutorial ])

assembler program is applicable to various models, we recommend that you use the 8086 assembly language with the best compatibility. All the languages mentioned in this article are 8086 assembly languages. Registers are internal components of the CPU, so data transmission between registers is very fast. Purpose: 1. perform arithmetic and logical operations on the data in the register. 2. The address stored in the Register can point to a location in the memory, that is, addressing. 3. It can be

Assembly Language hyper-concentration tutorial

components of the CPU, so data transmission between registers is very fast. Purpose: 1. perform arithmetic and logical operations on the data in the register. 2. The address stored in the Register can point to a location in the memory, that is, addressing. 3. It can be used to read and write data to peripheral devices on the computer. 8086 has 8 8 8-bit data registers, which can form 16-bit registers: AH AL = AX: Accumulate registers, which are comm

Linux-0.11 source code read two real mode to protected mode

The Bootsect section has been completed and the program jumps to the Setup section: start:! OK, the read went well so we get current cursor position and save it for! posterity. mov Ax, #INITSEG ! This is do in bootsect already ... mov Ds,ax mov Ah, #0x03 ! Read cursor Pos xor bh,bh int 0x10 ! Save it in known place, Con_init fetches mov [0],dx ! it from 0x90000. First read the location of the cursor, and then stored in the memory 0x90000 address, from the front, the bootsect part

Microkit 3.0

Microkit3.0: an integrated database of midbody, Centrosome and kinetochore.Jian ren, Zexian Liu, xinjiao Gao, Changjiang Jin, MingliangYe, hanfa Zou, Longping Wen, zhaolei Zhang, yu xueAnd xuebiao Yao.Nucleus acids Research. 2010; 38: D155-D160[Abstract][Free full text][Print PDF][Screen PDF] M phase, also calledAs cell division, is the most crucial and fundamental affairOf the eukaryotic cell cycle (AlbertaBEt al., 2002). After the chromosome

Protein acetyl database CPLA1.0

85% of eukaryotic proteins are N α-terminally modified (PolevodaEt al.., 2000; PolevodaEt al., 2002). The second type is N ε-lysine acetylation, which specifically modifies ε-amino group of protein lysine residues (YangEt al.., 2007; ShahbazianEt al., 2007; SmithEt al., 200

[Jia Liwei university mathematics magazine] 322nd sets of simulation papers for Mathematics Competition Training of Gannan Normal University

the unit ball? 18. Set $ a> 0 $ and find the area enclosed by $ \ DPS {Y = \ frac {x ^ 3} {2a-x }}$ and $ x = 2a $. 19. discuss $ f (x) = x \ SiN x, x ^ \ Al \ ln x (0 20. set $ \ Bex f (x) = \ int_x ^ {x ^ 2} \ sex {1 + \ frac {1} {2 t }}^ t \ SEZ {e ^ {\ frac {1} {\ SQRT {T }}- 1} \ RD t, \ quad T> 0. \ EEx $ evaluate $ \ Bex \ vlm {n} f (n) \ sin \ frac {1} {n }. \ EEx $ Advanced Algebra 1. set $ \ mathbb {p} $ to a number field. If $ P_1

"Software Security" assembly language Hyper-Enrichment Tutorial & buffer overflow Attack--1

process 4 hexadecimal numbers sequentiallymov al,bl; transfer bx low eight-bit BL internal data to Aland AL,0FH; zeroing out the useless bitsAdd al,30h, add 30H to the data in AL, and deposit AlCMP al,3ah; compare with 3ahJL PrintIt; less than 3ah transferAdd

Protection Mode: A20 Switch

processed in the keyboard buffer, therefore, you must first process other data: 1.Interruption prohibited; 2.Wait8042 input bufferIt is empty; 3.Send the prohibit keyboard operation command8042 input buffer; 4.Wait8042 input bufferIt is empty; 5.Send read8042 output portCommand; 6.Wait8042 output bufferData available; 7.Read8042 output bufferAnd save the obtained bytes; 8.Wait8042 input bufferIt is empty; 9.SendWrite 8042 output portCommand8042 input buffer; 10.Wait8042 inpu

Assembly source code get times of day (fetch time)

flag, 0 to-use DOS, 1 to-use BIOS example. MODEL TinyUse_bios_flag EQU 1;-----------Stack Area---------------. STACK 500;--------------------------------------. CODE;************* @@@@@@@@@@@@@@ ***************Start proc nearMOV bx,80h index command line datamov al,[bx]; get size of string variableMOV Ax,csmov ds,ax; reset data segmentMOV psp_seg,es; save PSP Addressmov es,ax; reset extra SegmentCMP al,4;

Get jmp esp/jmp ebx/call EBX address in a process

);Stradd1 + = 11; // stradd1 points to "-- JMP Esp --/R/N"Writefileadd (libhandle, stradd1, 18, ret, null );Stradd1 + = 19; // stradd1 points to "0x. 8x/R/N"Fmtstr = stradd1;Stradd1 + = 9; // stradd1 points to "-- jmp ebx --/R/N"//////////////////////////////////////// //////////////////// Create an exception handling code for our own Exception Handling Code// Get JMP ESP_ ASM {// INT 3Lea EDI,MoV eax, dword ptr fs: [0]MoV dword ptr [EDI + 0x08], eaxMoV dword ptr fs: [0], EDI}Counter T [0] = 0

C # 1.x implements "unique arraylist of strongly typed elements"

){System. Console. writeline ("Hello World ");System. Console. writeline ("Hello World ");Class1 C1 = new class1 ();Class1 C2 = new class1 ();Class1 C3 = new class1 ();Class1 C4 = new class1 ();Strongtypeuniquearraylist x = new strongtypeuniquearraylist (system. type. GetType ("class1 "));System. Console. writeline (X. type );X. Add (C1 );X. Add (C2 );X. Add (C3 );X. insert (0, C4 );System. Collections. ienumerator Ie = x. getenumerator ();While (ie. movenext ())System. Console. writeline (ie. C

8086 Summary of assembly instructions

similar to that of mov. (4). Push: in the stack, the top pointer of the stack (SP) = (SP) + 2, and a word of data is stored in the memory unit specified by the SP For example: Push ax; push register push ds: [0]; push memory unitEasy to troubleshoot: Push al; push register (high/low) byte (invalid command), must be a word, 16-Bit Data push 8 h; push constant (invalid command) (5). Pop: read out the stack, read the memory unit indicated by the wor

A20-A pain from the past

used to control the and gate that disables this address bit. the signal is called A20, and if it is zero, bit 20 of all addresses is cleared.Present Why do we have to worry about this nonsense? Because by default the A20 address line is disabled at boot time, so the operating system has to find out how to enable it, and that may be nontrivial since the details depend on the chipset used.Classical A20 control, via the keyboard controller The output port of the keyboard controller has a number of

8080 compilation instructions

8080 Assembly manual data transmission instructions── ─They transmit data between the storage and registers, registers, and input/output ports.1. General data transmission commands.MoV transfers words or bytes.Movsx first extends the symbol and then transmits it.Movzx is zero-scale and then transmitted.Push pushes words into the stack.Pop pops up the word stack.Pusha pushes ax, CX, dx, BX, SP, BP, Si, di into the stack in sequence.Popa pops up the Di, Si, BP, SP, BX, dx, CX, and ax stacks in seq

Natural Language Processing Resource NLP

is numeric representations of words where similar words has similar vectors. Word vectors is often used as input to deep learning systems. This process is sometimes called pretraining.A Neural Probabilistic language model.Bengio 2003. Seminal paper on word vectors.Efficient estimation of Word representations in Vector SpaceMikolov et al. 2013. Word2vec generates word vectors in an unsupervised-by-attempting to predict-words from a corpus. Describes c

Java basics 16-collection framework

writable list; public DuiLie () {list = new writable list ();} // The public void myAdd (Object obj) {list. addLast (obj);} public Object myGet () {return list. removeFirst ();} public boolean isNull () {return list. isEmpty ();}} The queue is implemented. 16-4, ArrayList stores custom objects For example, store the Person object. Person class: public class Person {private String name;private int age;public Person() {super();}public Person(String name, int age) {super();this.name = name;this.a

8086/8088 assembly instruction Summary

1. Data Transmission instructions; Ii. Arithmetic commands; Iii. logical commands; Iv. string processing commands; 5. control transfer instructions; 6. processor control commands. (For details, see the full text) I. Data Transmission instructions1. General Data Transmission commandsMOV (Move) TransferPUSH (Push onto the stack) to stackPOP (Pop from the stack)XCHG (Exchange) Exchange . MOV commandFormat: mov dst, SRCOperation: (DST) . PUSH to stack commandFormat: PUSH SRCOperation: (SP) (S

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