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', ' y ', ' Z '}};ArrayList classA dynamic Array (ArrayList) represents an ordered collection of objects that can be individually indexed. It can basically replace an array.However, unlike arrays, you can use an index to add and remove items at a specified location, and the dynamic array will automatically resize it.It also allows dynamic memory allocations, additions, searches, and sorting of items in a list.ArrayList Al =NewArrayList (); Console.Wr

Refer to "Deeplearning.ai convolutional neural Network Week 2 Lecture Notes".1. AlexNet (Krizhevsky et al. 2012), 8-layer network.Learn to calculate the shape of the output for each layer: for the convolution layer, the edge length of the output = (input side length-filter side length)/step + 1, the output number of channels equals the number of filter. The number of channels per filter equals the number of channels entered. The parameters of the conv

* we ' re safe again * * Mov_mem_to_al (ABS (boot_drive))/ * MOVB ABS (boot_drive),%al/ cmpb $GRUB _invalid_drive, %al JE 1f movb %al,%DL Enter Real_start, Ax clear Zero, DS assignment 0,ss assignment 0, assign stage1_stackseg (0x2000) to SP, so set the stack segment address (stack top position) SS:SP = 0x0000:0x2000

[Label_ldt2_desc_codec + 4], ALmov byte [Label_ldt2_desc_codec + 7], ah ; Preparing to load GDTRxor eax, EAXmov ax, DSSHL EAX, 4add eax, LABEL_GDT; EAX MOV DWORD [gdtptr + 2], eax; [Gdtptr + 2] ; Load GDTRLGDT [Gdtptr]; Off interruptCli; Open Address line A20In Al, 92hOr AL, 00000010bOut 92H, AL; Ready to switch to protected modemov eax, CR0or EAX, 1mov cr0, eax

Get_keyinput_to_1Turn_sound_off_to:Call Sound_offMOV sound_flag,0JMP Get_keyinput_to_1Get_keyinput_to ENDP;^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^;************　@@@@@@@@@@　************; ### code Entry point #####Start_table_sound proc Near; subroutine to start background sound output; On entry BX Indexes sound data tablePublic Start_table_soundPush AXPush BXMOV AX,[BX]Call Get_time_plus_axMOV sound_time_m,cxMOV Sound_time_l,axInc BXInc BXMOV AX,[BX]Inc BXInc BXMOV sound_table,bxCall Sound_out_axM

equ 80h; Buffer for Command tail; DOS 2.0 pre-defined Handlesstdin equ 0000; Standard input FileSTDOUT equ 0001; Standard output filestderr equ 0002; Standard error fileStdaux equ 0003; Standard auxilliary fileSTDPRN equ 0004; Standard printer fileCSEG segment para public ' CODE 'Assume Cs:cseg,ds:csegORG 100H; Start. COM at 100Hclean proc far; Entry point from Pc-dos.Push DS; Push a long backXOR Ax,ax; To DOS onto the stack.Push AXClean3:call Get_char; Get a character from input.and

table entry 0000:0634-Dec CX. # entries left 0000:0635 jz short Loc_tabok, all entries look OK 0000:0637 2C CMP [Si],ch; Other entries = 0? 0000:0639 F6 JE Loc_nextrpe; Yes, this one is OK 0000:063b Loc_bad:; Found a invalid entry: ; A). From 0624:boot ID!=0 and!=80h ; B. From 0639:multi entries with id=80h 0000:063b. is 0710 mov si,offset msg1+1; ' Invalid partition ' 0000:063e loc_halt:; show msg then halt 0000:063e 4E Dec si 0000:063f loc_msg:; xref 064B, 06BA 0000:063f AC LODSB

another list. You can also use the repeating operator to recognize the operator as a multiplication operator so that you can build a larger list from a small fragment. The previous example shows you how to add elements to the list and how to modify the entries in the list. The previous example also shows how to remove an object from the list. The first way to delete an entry is to use the Del method. Use this method to delete an entry or a range of entries. You can also use a flexible and powe

: The code is as follows Copy Code ArrayList al = new ArrayList ();for (int i = 0; i {Al. ADD (i);Response.Write (Al[i]. ToString () + "Response.Write (al[i]+ "}Response.Write (al. Count + "foreach (int obj in

202 mov es, dx 203 204 mov eax,esp 205 206 Inc DWORD [K_reenter] 207 CMP DWORD [K_reenter], 0 208 jne. 1 209 with mov esp, Stacktop ; cut to the kernel stack 211 push restart 212 jmp. 2 213.1: 214 Push Restart_reenter 215.2: 216 jmp [Eax+retadr-p_stackbase]Partial content of the interrupt handler: 158 hwint00: ; Interrupt routine for IRQ 0 (the clock). 159 ; Inc Byte [gs:0]; Change the No. 0 row of the screen, the charact

concentrate. Of course, some programs may not be condensed because of the amount of work and the details of the processing. 2, in a similar program, to find different instructions or processes, and if not, that is repeated, it is desirable to merge. 3, replace the different instructions or processes with variables, or put the entry of the various programs in the register. 4, the program in the application of the process, set the variables and the use of registers. 5, merging similar program

want to know what will happen if each entry is replaced by a list. The result is an array or a matrix in mathematics. Listing 7 shows how to use list to maintain a two-dimensional (2-D) or three-dimensional (3-D) array.Listing 7. list as an array >>> al = [[0, 1, 2], [3, 4, 5], [6, 7, 8]]>>> al[[0, 1, 2], [3, 4, 5], [6, 7, 8]]>>> al[0][0] # First element in

farmer, ship, wolf, goat, cabbage, corresponding to the ¬al (x) indicated on the right bank.Initial state of the problem: Al (Farmer), AL (ship), AL (Wolf), Al (Goat), AL (cabbage).The target state of the problem: ¬

In and Outout 0fah,al (does it refer to a port that outputs a byte to 0FAH from AL?) ) out Dx,al out 0fah,ax (AX is a word why can it also output to the 8-bit port referred to in 0FAH?). Out 03f8h,al (This command has an error why?) This is because in the out instruction directly with the digital address, the port nu

complementing functions ([Tab] Key Usage) The command and file completion functions allow you to: Make sure that the input data is correct. The rules for using the tab key are as follows: [Tab] after the first word of a command string, the command is supplemented;[Tab] after the second word of a string of commands, the file is complete. Command completion: if you do not want to press too many buttons during command execution, for example, the command pcprofiledump. If you enter pcprofile, press

small hard disk): 0001.0048 7732 ja 007c; if the value is greater than 0: 0001.004a 668b461c mov eax, [bp + 1C]; eax = number of hidden sectors: 0001.004e 6683c00c add eax, 0000000c; number of hidden sectors + 0c: 0001.0052 bb0080 mov BX, 8000; BX = 8000: 0001.0055 b90100 mov CX, 0001; Cx = 1: 0001.0058 e82b00 call 0086: 0001.005b e94803 JMP 03a6; 03a6 ?????? * Referenced by a (u) nconditional or (c) onditional jump at address:|: 0001.0106 (c)|: 0001.005e a0fa7d mov

Transferred from the oldlinux Forum This is what I learned from the bootsect. s file. After reading this version of the bootsect file, I collected it. Some problems are really obvious in the book, so I didn't extract them.Some problems are really the same as bootsect.CodeIt does not matter, and I have not excerpted it. They are all questions you want to ask. I have read it several times and there are still many problems.In fact, many questions have been asked before. This is indeed the c

in the instruction. The default segment base address is the DS segment register. Enclose a valid address in brackets to express the content of the storage unit. Valid address = 16-bit displacement The assembly language format is as follows: MoV ax, [2010 H]; ax MoV [1010 H], Al; DS: [1010 H] MoV BX, ES: [3020 H]; BX Indirect addressing of registers: The valid addresses of operands are all in the registers of the CPU. Because the valid address is

32-bit CPUs contain the following registers: Four data registers (eax, EBX, ECx, and EDX)2 address changes and pointer registers (ESI and EDI) 2 pointer registers (ESP and EBP)Six segment registers (ES, Cs, SS, DS, FS, and GS)1 Instruction Pointer register (EIP) 1 flag register (eflags) 1. Data RegisterData registers are mainly used to save information such as the operands and operation results, thus saving the time required to read the operands by occupying the bus and accessing the memory.The

Program 0: Convert the string "Adcdef" to uppercase, and change the string "FGHJK" to lowercaseData segmentDB ' Adcdef 'DB ' xcvbnm 'Data endsCode segmentStartMOV Ax,dataMOV Ds,axMOV bx,0MOV cx,6MOV di,0S:mov AL,DS:[BX]and al,1011111bMOV Ds:[bx],alMOV al,ds:[bx+6]or al,0100000bMOV Ds:[bx+6],alAdd bx,1Loop sMOV ax,4c00h