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Fast Power, Fast Power modulo As the name implies, a quick power is to quickly calculate the power of a certain number. The time complexity is O (log complexity N), which greatly improves the efficiency compared with the simple O (N. Principle: The following is an introduction to B

Question Given n numbers and Q queries, the super power of the [L, R] interval is output each time, modulo m is obtained.Ideas The super power problem is solved by Euler's power reduction. Euler's power reduction formula: $ A ^ B \ % m = a ^ {B \ % \ varphi (m) + \ varphi (m)} \ % m, (B> \ varphi (M) $ This article use

My motherboard is a 24PIN power interface, the power is 20PIN interface, compared, the more out of the interface is (+12V, +5v) and (+3.3v, GND) Two groups, now the motherboard only one +3.3v output used in the SATA power sockets, Want to use a large 4-pin socket to transfer into the 4-pin motherboard power connector,

I checked the Chinese data of lm3914 on the network for 2 hours and found no results. The most detailed one is the following sentence: " Lm3914 is a double 18-pin package; power supply voltage> = 3 ~ 20 V; adjustable output current = 2 ~ 30mA; reference voltage adjustable = 1.25 ~ 12.5 V; Voltage Divider resistance = 1 kb Ω; static current = 6mA; Voltage Divider precision = 0.5%, amplification gain = 3 ~ 8 dB. The reference voltage source output

Original question: zoj 3774 http://acm.zju.edu.cn/onlinejudge/showProblem.do? Problemcode = 3774. Bytes ---------------------------------------------------------------------------------------------------------------------- This question is more complex, see this more detailed: http://blog.csdn.net/acdreamers/article/details/23039571 Conclusion: Make full use of the Fast Power and reverse element. Code: #include View code

Question: Given matrix; Evaluate A ^ 1 + A ^ 2 + A ^ 3 +... A ^ K Using quick power Sum (6) = A ^ 1 + A ^ 2 + A ^ 3 + A ^ 3 * (A ^ 1 + A ^ 2 + A ^ 3 )... So you can get a general item. Sum (n) If (n 1) { Sum (n) = sum (n-1) * A ^ n; } Else sum (n) = sum (n/2) + A (n/2) * sum (n/2 ); #include #include #include #include #include #define N 30typedef long long LL;using namespace std;int n,mod;struct matrix{ int a[N

Steps: 1, press the "Win+r" key combination to open the operation; 2, in the box input: control USERPASSWORDS2 Click OK open local account management; 3. In the "User account" attribute, cancel "to use this machine, the user must enter username and password (E)" Check, and then press "OK" 4, in the pop-up box input after the boot automatically login username and password, click OK, restart the computer can not use the local account log in. The above is a small series of Win10 to can

In the iphone has a special power-on password setting option, the default state is off, that is not encrypted, the following step-by-step teaching you to complete the password settings: 1th Step, open the iphone and find the "Settings" icon, bash into: 2nd step, in the "Settings" option, find the "general" sub-item icon, click to enter; The 3rd step, find the "Password lock" option, the default state is "off", click to enter the detailed settin

M Fibonacci Sequence Time Limit: 1000MS Memory Limit: 32768KB 64bit IO Format: %i64d %i64u Submit StatusDescriptionM Fibonacci Sequence F[n] is an integer sequence, which is defined as follows:F[0] = aF[1] = bF[n] = f[n-1] * F[n-2] (n > 1)Now give a, B, N, can you find the value of F[n]?InputInput contains multiple sets of test data;One row per group of data, containing 3 integers a, b, n (0 OutputFor each set of test data output an integer f[n],

First of all, the purpose of the fast power is to do a quick exponentiation, assuming we ask a^b, according to the naïve algorithm is to connect A to B, so that the time complexity is O (b) is also the O (n) level, fast power to do O (Logn), a lot faster. It has the following principles:Suppose we ask for a^b, then in fact B is can be split into binary, the second number I bit the right to 2^ (i-1), such as

Failure phenomenon: The Ideacentre B5 series computer presses the host power source not to add electricity. Solution: 1. Check whether the power supply is normal First check whether the rest of the household electrical use is normal, the same socket on whether other appliances can work properly. You can plug the computer into other outlets. Test if there is a problem with the socket: use the lamp to tes

1. On Note4 Mobile Desktop we find "application" details as shown in the following figure. 2. Then find the "Settings" menu click Open. 3. Then you will see there is a "power saving" button for our war drums it. 4. Into the provincial power interface, we find "power-saving mode" (there is a close below, the default is closed we want t

1. This mobile phone with the power-saving mode, we click on the "Application." 2. Click the "Set" option to open the entry. 3. Here you will see a "Save power" option, we click to open the power to enter. 4. Click "Save power Mode", the following figure has a close, the representative is clo