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sub-problem are given three volumes of book purchases, the minimum need to use the money, so there is "sub-problem overlap", the problem of three purchase amount is set to parameters, respectively, I, J, K. 4. It does match. 5, the border is a purchase can buy all the books, processing methods please the reader's own consideration. 6, the choice of a maximum of 7 options, and will not be implemented at the same time, so the choice of options do not affect each other, so there is "sub-p

. The variable that receives input when using [] must be a char, signed char, unsigned char array with sufficient storage space. Remember [is also the conversion character, so there is no s anymore. 8. Split the string marked with a character. Char test[]= "222,333,444,,, 555,666"; Char s1[4],s2[4],s3[4],s4[4],s5[4],s6[4],s7[4]; SSCANF (Test, "%[^,],%[^,],%[^,],%[^,],%[^,],%[^,],%[^,]", S1,S2,S3,S4,S5,S6,S7

amount of string s2=s+ "B"; String s3= "12ABCD3"; String s4= "12ABCD3" + ""; String s5= "12ab" + "CD3"; String s6= "12AB" + "CD" + ' 3 '; String s7= ' 1 ' + ' 2 ' + "AB" + "CD" + ' 3 '; String s8= "B"; String S9=new string ("Abcd2"); String S10=new string ("abc" + "D2"); String str1 = "abc"; String str2 = Str1.concat (""); String STR3 = "abc". SUBSTRING (0); System.out.println (s0==st);//true, constant is also the literal, the direct amount of the op

temporary table is the first summary + sorting process (the first processing does not deal with subtotals, totals, etc.) CREATE table #t (project name varchar (10), Project year varchar (10), varchar (10), Applicant Unit varchar (10), support amount int) Insert #t Select ' Name 1 ', ' 2004 ', ' Provincial ', ' 1 company ', 400 UNION ALL SELECT ' Name 2 ', ' 2004 ', ' Provincial ', ' 2 company ', 300 UNION ALL SELECT ' Name 3 ', ' 2004 ', ' Shijiazhuang ', ' 3 company ', 200 UNION ALL SELECT '

mine1;//OK, S1 is a type S2 mine2;//ok,s2 is a type S3 mine3;//Ok,s3 is not a type S1.data = 5;//ERRORS1 is a type S2.data = 5;//ERRORS2 is a type S3.data = 5;//OKS3 is a variable } In addition, there are several ways of writing variables that define the structure itself in the structure. struct S6 { s6* ptr; }; This type of writing can only be used in C + + typedef struct { s7* ptr; } S7; This is a defini

has a significant performance boost over the Vaio duo 11 core i5-3317u. In particular, the difference between the two in the video card test is more obvious: in the 3dmark06 test, Duo 13 scored 6047, whereas his predecessor was only 4807. The former results also beat the Ivy Bridge platform for the best results-the Acer Aspire S7 scored 4918 points. And for overall performance, like the PCMark7 test, we're not seeing that much improvement-in fact, t

| Sname | varchar (10) | YES | | NULL | | +-------+-------------+------+-----+---------+-------+　　Column name specified when creating table: Inconsistent: result ExceptionMysql> CREATE TABLE s7 (Sid int,sname varchar) as select id,name from S1;Exception Result:Mysql> desc s7;+-------+-------------+------+-----+---------+-------+| Field | Type | Null | Key | Default | Extra |+

= S.class }) 3.distinct Remove the duplicate 1 Query teachers All units are not duplicates of the depart column.2 SELECT distinct depart from teacher3 Linq:4 from T in Teachers.distinct ()5 Select T.depart6 Lambda:7 4. Connection query between and 1 query all records in the score table with scores from 60 to 80.2 Select * from score where degree between and 803 Linq:4 from s in Scores5 where S.degree >= S.degree 6 Select S7