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. Enqueue (3 );Qq. Enqueue (4 );Qq. Enqueue (5 ); Qq. Dequeue (); // removes the top oneInt c = qq. Count; // Count Qq. Peek (); // view only, do not kick out Qq. Clear (); // Clear the setBool bb = qq. Contains (3); // determines whether the element is contained. Foreach (object B in qq){Console. WriteLine (B );} Console. ReadLine (); Foreach traversal setForeach (object aa in name){Console. Write (aa + "\ t ");} Console. ReadLine (); Object;Int B = 4;A = B;Double c = 3.14;A = c;Bool d = true;A

1. Draw a pixel [cpp] view plaincopyprint? Unrecognized INT 0x10 recognizable video image mode ---------------------------------------------------------------------- mode resolution (column * Row, pixel) color count 6 640x200 2 0DH 320x200 16 0EH 640x350 16 0FH 640x350 2 10 H 640x200 16 11 H 640x480 2 12 H 640x480 16 13 H 320x200 256 6AH 800x600 16 ----------------------------------------------------------------------- when the Video Controller is in graphic mode, INT 0 The x10 function 0CH draw

learning-related academic activities is that it has had an empirical significance of success in academia and industry. Below are some simple points to focus on. 2.1 speech recognition and signal processing Speech is also one of the earliest applications of neural networks, such as convolution (or latency) neural networks (bengio's work in 1993 ). Of course, after Hmm's speech recognition is successful, the neural network is also relatively quiet. Up to now, the rise of neural networks, deep le

(Yuanma) diffsub = 0000000000000010; bad original codeHex sumhex= 0002 ; /*************************************** *********/;; Bsub. ASMHbyufan@163.com; Tsout macro dx0MoV ah, 09 hMoV dx, offset dx0Int 21 hEndm Data SegmentNum1 dB 19 DUP ('$ ')Num2 dB 19 DUP ('$ ')Sum dB 19 DUP ('$ ')Hexsum DB 5 DUP ('$ ') Tsnum1 dB 0ah, 0dh, 'binary (Yuanma) num1 = $'Tsnum2 dB 0ah, 0dh, 'binary (Yuanma) num2 = $'Tssum dB 0ah, 0dh, 'binary (buma) diff sub = $'Tsnum11 dB 0ah, 0dh, 'binary (buma) num1 Bm = $'Tsnu

MACRO dx0MOV ah,09hMOV Dx,offset dx0int 21hEndmData segmentNUM1 db DUP (' $ ')NUM2 db DUP (' $ ')Sum db DUP (' $ ')Hexsum DB 5 dup (' $ ')TSNUM1 db 0AH,0DH, ' binary (Yuanma) num1=$ 'TSNUM2 db 0AH,0DH, ' binary (Yuanma) num2=$ 'Tssum db 0AH,0DH, ' Binary (Buma) diff sub=$ 'TSNUM11 db 0AH,0DH, ' binary (buma) num1 bm=$ 'TSNUM22 db 0AH,0DH, ' binary (buma) num2 bm=$ 'TSSUM33 db 0AH,0DH, ' binary (Yuanma) diffsub=$ 'Tssumhex db 0ah,0dh, ' Hex sumhex=$ 'Data endsCode segmentAssume Ds:data,cs:codeSt

informationEscape db ' Press ESC to exit. 'Text1 db ' This is a example showing for you/make a menu with assemble. 'Text2 db ' and you could get it to free from http://lucky7.yeah.net. 'Text3 db ' You could use it in your software freely. 'TEXT4 db ' But please send me a copy of the Your software. 'TEXT5 db ' Thank you. Have a good time. 'Text6 db '--yours truly Mikespook 'SUB11 db ' Select Save 'SUB12 db ' Select Open 'Sub13 db ' Select Exit 'Sub21 db ' Select cut 'Sub22 db ' Select past 'Sub2

(pm32.c), executable readable}; GDT Selector, set the offset value according to the GDT bounds #define SELECTORCODE32 8*1//points at 32-bit segment #pragma pack (1) struct GDT_PTR {unsigned short size; void *a Ddr }gdtptr = {sizeof (LABEL_GDT), (char*) LABEL_GDT}; Segment bounds, base address #pragma pack () ASM void Main () {MOV ax, CS mov ds, ax mov es, ax//clear screen mov ah, 06h//screen initialization or roll mov aL, 00h//ah = 6,

JAVA course 42nd-generic (II)-generic interface amp; wildcard Application I. Generic Interfaces Interface Inter {Public void show (T t);} class InterImple implements Inter {// It is known that the String type is public void show (String str) {System. out. println ("show" + str) ;}} class InterImple_2 Implements Inter{// Do not know what type it is. public void show (Q q) {System. out. println ("InterImple_2.show () +" + q) ;}} public class Main {public static void main (String [

;parameters.deviceiocontrol.iocontrolcode; Switch (IoControlCode) { Case Ioctl_write: __asm { Push EAX Push edx //--------------------------------------------------- The following code writes the primary boot area with the I/O port MOV dx,1f6h//To read the disk number and magnetic number one MOV al,0a0h//Disk 0, head 0 Out Dx,al MOV dx,1f2h//number of sectors to write MOV

x_2y_3 x_3y_3 \ cdots x_3y _ {n-1} 0 \\\ vdots \ ddots \ vdots \ x_1y _ {n-1} x_2y _ {n-1} x_3y _ {n-1} \ cdots X _ {n-1} y _ {n-1} 0 \ x_1y_n x_2y_n x_3y_n \ cdots X _ {n-1} Y_n x_ny _ {n-1}-X _ {n-1} -Y_n \ EA }\\\ \ quad \ sex {\ mbox {Column n''-column n-1 ''}}\\ = Y_n (x_ny _ {n-1}-x _ {n-1} Y_n) D _ {n-1 }. \ EEA \ eeex $ with a recursive formula, evaluate $ D_n $: $ \ beex \ Bea Y _ {N-2} y _ {n-1} D_n = Y_n (x_ny _ {n-1}-X _ {n-1} Y_n) \ cdot Y _ {N-2} D _ {n-1} \ = Y

automatic circulation mode; The r=0 is the priority fixed mode. D4, D3 is the OCW2 flag bit. (3) format of the OCW3 The OCW3 is used to set or clear the status of special shielding and read registers, as shown in format 6.19. RR (read register command): Read ISR and IRR command bit, RIS (read interrupt register Select) Read register select bit. When Rr=1,ris=0, read the IRR command, and when Rr=1,ris=1, read the ISR command. When performing a read ISR or IRR operation, the Read command OC

This is the past DOS era of the compilation of source code, although has passed, but for the study of the assembly is still helpful, assembly language is just a basic programmer language, most people can grasp, not necessarily in-depth research. Comment *Sertype. AsmPurpose:Determines the type of UART in each serial portAuthor:Douglas Boling, in PCMag. With some modifications by Yousuf Khan.*DossegBDSEG segment at 40h; BIOS data segmentCOM1 DW?COM2 DW?COM3 DW?COM4 DW?Ends_DATA segment para ' da

INT 21H Interrupt AH Function Calling parameters return parameters xx program termination (same as int 20H) cs= program Segment prefix on keyboard input and Echo al= Input Characters Geneva Display Output dl= Output Characters Geneva Asynchronous Communication Input al= input Data

PreambleThis repository contains the lecture slides and course description for the deep Natural Language processing course offered In Hilary for the University of Oxford. This is a advanced course on natural language processing. Automatically processing natural language inputs and producing language outputs is a key component of Artificial general I Ntelligence. The ambiguities and noise inherent in human communication render traditional symbolic AI techniques ineffective for repres Enting and a

The Calculates the number of a+b within two bits. ;---------------------------assume CS:CC, ds:qw;---------------------------QW SEGMENT; data segment;D B One byte, dw two bytes, dd four bytes M1 DB ' Please input n1: $ ' M2 db in a, ' please input N2: $ ' M3 db, ' SUM = $ ' M4 db, ' Pres s any key to continue ... $ ' N1 DB? N2 DB? S DB? QW ENDS;---------------------------CC SEGMENT; code snippet START:; introduce QW segment mov ax, QW mov DS, ax; show M1 LEA DX, M1 mov ah, 9;D

;Cd_rom_driver DW?; CD drive letterRed_max_h DW?red_max_l DW?CD_INT macro control of Cd-audio macrosMOV ax,1510hMOV cx,cd_rom_driverint 2FHEndmmy:; This program's Mouse event myPushfCMP bx,7 if three keys are pressed at the same timeJNZ TTTMOV cs:ctrl,stop; stopJMP LLTttCMP bx,3 If two keys are pressed at the same timeJNZ qCMP dx,1 the top of the mouseJNB OtherMOV cs:ctrl,stop; stopJMP LLOtherCMP cx,599, mouse on the rightJB QQQMOV Cs:ctrl,next; forwardJMP LLQqqCMP cx,1Jae Qmov cs:ctrl,back; Mou

, see 103h char, change ' t ', on output, type TXT, see 1~4. act=2Ifdef ARGIF Arg GT 2IF Arg EQ 30Act=30ENDIF IF Arg EQ 31Act=31ENDIF IF Arg EQ 41Act=41ENDIF Std_=arg/10ELSEIF Arg GE 0Act=1Std_=arg IF Arg EQ 0Act=0ENDIFENDIFENDIFENDIF IF ACT EQ 2 is invalid%out/darg=0|1|2|30|31|41. ErrENDIF Just macroLocal J MOV di,es:[26] hit the key, I9 write low ASC, high scan to [1Ch tail text ++],i16 read [1Ah primer + +] to 3f function axSub di,2 CMP di,1ch not reset key area, now turn aroundJA j

jump have unconditional jump: JMP. and conditional jump, JX. There are 19 instructions on X. DATA SEGMENT XX db 5 YY db? DATA ENDS Stack SEGMENT stack DB DUP (?) STACK ENDS CODE SEGMENT assume Cs:code, Ds:data, Ss:stack START: mov ax, DATA mov DS, ax ; Core code segment MOV al, XX CMP al, 0; X-0 to establish the Jge Biger of sign position; X>=0 jump to Biger MOV

Your current location: home page of compilation studio --> data sharing: 　 　 The following information is for reference only: Bytes ---------------------------------------------------------------------------------------- Int 10 h: int 10 h, 12 h, Mouse mask, and other materials Int 10 h In Out Ah = 00 set display mode Ah = 0 Al = video mode 　 Ah = 01 set the cursor type Ah = 1 Ch = start Scan Line Cl = end Sc

of lights in each state. You can use the ROL command to implement the Left shift effect. In the process, you must save the value after the Left shift, in addition, when the switch status is changed during operation (two lights are increased to three lights), the light effect will also change.It took me one afternoon to complete the computer hardware experiment that day. Later, I found that there was an error in the function of changing the switch status during operation. I directly assigned the