athlon x3

# #数据获取X1=round (runif (100,min=80,max=100))X2=round (Rnorm (100,mean=80, sd=7))X3=round (Rnorm (100,mean=80,sd=18))X3[which (x3>100)]=100Num=seq (2005138101,length=100)X=data.frame (NUM,X1,X2,X3)Write.table (x, "Grade.txt")# #数据分析Y=read.table ("Grade.txt")Mean (y)Colmeans (y)Colmeans (Y) (C ("x1", "X2", "

network,Into the layer, the cycle, until the error reaches the desired minimum, that the network training success. After that, we can use the trained network to deal with the new teaching quality index and get the accurate evaluation result of teaching quality.The BP neural network logical structure diagram is as follows:2. Application of BP neural network teaching quality evaluation ModelTeaching Evaluation Index (scoring range of each indicator 0-10): x1: Paragon, affect the students by their

For example, Party A, Party B, and Party C each have a cost of 100 yuan. Based on the above-mentioned winning/losing relationship, let's play with it: A lost 50 yuan to B and 50 yuan to CB lost 100 yuan to CC lost 100 yuan to If you just play, it's easy to figure out who winsBut what would they do if they kept the winning or losing relationship and the winning money was invested in another round of gambling? We can write a single machineProgramLook, for ease of computing,

;return ax * by - ay * bx;}bool inTri(int x, int y, int x1, int y1, int x2, int y2, int x3, int y3) {return abs(cross(x1, y1, x2, y2, x3, y3)) == abs(cross(x1, y1, x2, y2, x, y)) +abs(cross(x1, y1, x3, y3, x, y)) +abs(cross(x3, y3, x2, y2, x, y));} The area is relatively intuitive: double getsquare(int x1,int y1,in

configure scripts use these two environment variables to replace the values in makefile.However, a few configure scripts do not. They must be manually edited. To set the cflags and cxxflags environment variables, You can execute the following command in bash (or write it into. bashrc to be the default value ):Export cflags = "-O3-March = This is the minimum setting to ensure that it works on almost all platforms. The "-March" option indicates that binary code is compiled for a specific CPU type

athlon XP 1800 + is equivalent to the frequency of 133mhz external frequency X 11. 5. As long as we increase the frequency to 12.5, the CPU clock speed will become 133mhz × 12. 5 ≈ 1.6 GHz, equivalent to athlon XP 2000 +. If we increase the frequency to 13.5, the CPU clock speed will become 1.8 GHz, and the athlon XP 1800 + overclock will become

CPU, memory, card chip clock frequency increase, the speed of the CD-ROM drive faster, the increase of cooling fan, so the power supply performance requirements are greatly increased. Especially after the introduction of P4, as the current power of the largest desktop CPU processing chips, its power can be up to 60w or more, if the power supply performance is likely to be inadequate. Therefore, on the chassis and power requirements. The P4 has new requirements. We must pay attention to the chas

when the FSB is 100MHz, and changed to 2-3 of the way, the FSB is promoted to 133MHz. The Celeron 1.7GHz default FSB is 100MHz, we just upgrade the FSB to 133MHz, the original Celeron 1.7GHz will be overclocking to 2.2GHz work, is not very simple:). Another piece with the AMD CPU using the VIA KT266 chipset motherboard, using the DIP switch set the way to set the CPU frequency multiplier. Most AMD has no multiple frequencies locked, so it can be overclocking by modifying the frequency multipli

frequency of the CPU. We need to know that the actual CPU operating frequency should be consistent with the standard operating frequency, but the reason is that the adjustment frequency of the motherboard of each manufacturer is inconsistent, the frequency here has a certain error. If the difference between the two frequencies is too large, the standard operating frequency is 2.40 GHz, and the actual operating frequency is 3.21 GHz, then you will encounter CPU overclocking, if you purchased the

of the way when the FSB is 100MHz, and changed to 2-3 of the way, the FSB is promoted to 133MHz. The Celeron 1.7GHz default FSB is 100MHz, we just upgrade the FSB to 133MHz, the original Celeron 1.7GHz will be overclocking to the 2.2GHz work, is not very simple. Another piece with the AMD CPU using the VIA KT266 chipset motherboard, using the DIP switch set the way to set the CPU frequency multiplier. Most AMD has no multiple frequencies locked, so it can be overclocking by modifying the frequ

, but it is not easy to use the direct method. Now, we can try another way. This is: the Laplace polynomial. 3. The structure of the Laplace polynomial, with four points as an Example Since the function goes through four points (x0, y0), (x1, Y1), (X2, Y2), (X3, Y3), you can set the function: F (x) = b0 (x) * y0 + B1 (x) * Y1 + B2 (x) * y2 + B3 (x) * Y3 Note: B0 (x),..., B3 (x) are all three polynomials of X, called the Laplace Interpolation Basis

enumerate, to see if all of the pins are selected, then the enumeration of {0, ..., 0} to {1, ..., 1}, which requires 2 of the n-th-exponent. Obviously, when n is large, the efficiency of this approach is very low. The implicit enumeration method introduced in this paper can improve the efficiency of solving the optimal solution.The so-called implicit enumeration method, in the literal sense, is to implicitly remove some cases that do not require enumeration, and from an example, the steps of t

Three-point SequenceTime Limit: 1000 MS | memory limit: 65535 KBDifficulty: 3DescriptionThe coordinates of the three non-collocated vertices A, B, and C must be A triangle. Now let you determine the coordinates of A, B, is C provided clockwise or counterclockwise? For example: Figure 1: clockwise Figure 2: counter-clockwise InputEach row is A set of test data, with six integers x1, y1, x2, y2, x3, and y3 representing the horizontal and vertical coo

* @param imageview/private void Startanimation (final ImageView ImageView) of the image to start animation {KEYFR ame[] keyframes = new Keyframe[count]; Final float Keystep = 1f/(float) count; float key = Keystep; for (int i = 0; i The call is very simple: startanimation (ImageView) can, Propertyvaluesholder, and so on their own look at the information. An algorithm for solving the parabolic equation with the known parabola three points is attached: Package com.freesonfis

Fractal geometry is a new subject in the field of mathematics, if each element of the graph is deformed according to some rules, the new figure is obtained, and so on, the graph obtained after several times of deformation is fractal shape. The couch curve is the most typical fractal shape: To transform a line segment according to Figure 1, get figure 1, and then the figure 1 of each line in Figure 1 of the line transformation to get figure 2, and so on, 6 times to transform to get figure 6, i

combinations:cn+r-1rTheorem 2: The R-no-difference ball, put in N marked box, each box can more than one, then a total of Cn+r-1r SchemeExample: (x+y+z) 4 Total number of items:It is equivalent to putting 4 balls into 3 boxes, and there is no limit to the number of boxes in each one. As X4 can be understood to put 4 balls into box X.N=c (n+r-1,r) =c (3+4-1,4) =c (6,4) =154 Non-contiguous combinationsRefers to: from the sequence a={1,2,.... n} takes R, which does not exist, i,i+1 two neighbors a

Problem:Three point coordinates on the known circle (x1,y1), (X2,y2), (X3,Y3)Find Circle radius r and Center coordinates (x, y)X,y,r is unknown, X1,y1,x2,y2,x3,y3 is constantThen by the Circle formula:(x1-x) ²+ (y1-y) ²=r² (1) -(x2-x) ²+ (y2-y) ²=r² (2) -(x3-x) ²+ (y3-y) ²=r² (3) -(1)-(2), Left side minus left, right minus right, getx1²-2xx1+x²+ (y1²-2yy1+y²)-(x2

;='0'ch'9') the { -x=x*Ten+ch-'0'; -Ch=GetChar (); - } + returnx*F; - } + intMain () A { at intn,m,b1=0, b2=0, b3=0, b4=0; -N=read (); m=read (); - for(intI=1; iread (); - for(intI=1; i) - { - inttemp; intemp=read (); - if(temp==1) b1++; to Else if(temp==2) b2++; + Else if(temp==3) b3++; - Elseb4++; the } *f[0][0][0][0]=a[1]; $ for(intx4=0; x4)Panax Notoginseng { - for(intx3=0;

assignment, if + + and--at the back is first assigned value and then self reduction. Two Assignment operator symbol The main operations include: = (Assignment), +=,-=,*=,/=,%=. Assignment = operation is very simple, the basic is to two types of variables, one of the values assigned to the other. int x = 0;int y; y = x; the remaining four operating principles are the same, as shown in the following example: int x1, x2, x3; x1 = 11;x2 = 12;

of an expression is true, then the corresponding statement after execution executes, the entire if statement ends, and the remaining statements are not executed; if none of the statements is true, then the last else statement is executed.//input Three number x1,x2,x3, three number of output by small to large order#includeintMain () {//define four variables intx1,x2,x3,temp; //Prompt user to enter three