bdp s470

the code! The code is saved as bdp. php. The code is as follows: Require_once ('Snoopy. class. php '); // Http://www.abc.com/bdp.php? Consumer id = 29160 uk = 2855065916 $ Url = 'http: // pan.baidu.com/#/link? Upload id = '. $ _ GET ['upload id'].' uk = '. $ _ GET ['UK']; $ Snoopy = new Snoopy (); $ Snoopy-> read_timeout = 0; $ Snoopy-> fetch ($ url ); $ N = $ snoopy-> results; $ Regex = '/(_. src = ") (. + )(";)/'; $ Match = ''; Preg_match ($

Huawei online storage has a straight-chain function, but it requires money. I have a Baidu network disk, but Baidu's external network disk chain cannot be directly used in the web page. Baidu can also have this function one day. First Code: less codeUse regular expressions to obtain the real address of Baidu online storage files to achieve straight-chain effect. Save the following code as downbd. php The code is as follows: $ Canshu = $ _ SERVER ["QUERY_STRING"];If ($ canshu = ""){Die ("fi

parameters for using TCP memory resources Echo 16777216>/proc/sys/NET/CORE/rmem_maxEcho 16777216>/proc/sys/NET/CORE/wmem_maxCAT/proc/sys/NET/IPv4/tcp_memEcho "4096 65536 16777216">/proc/sys/NET/IPv4/tcp_rmemEcho "4096 87380 16777216">/proc/sys/NET/IPv4/tcp_wmem Rmem_max defines the maximum value that can be used in the Receiving Window and can be adjusted according to the BDP value.Wmem_max defines the maximum value that can be used in the sending wi

and de equal to the corresponding side then their diagonal also should be equal, de is the ∠dce, because the CE is the angle evenly line, so ∠ace is 60°, so ∠dce=120° ad diagonally should also be 120°, So the parallel line over D to AC is Tong ∠bpd=60° ab in P,∠bac, thus creating ∠apd=120°, equilateral BPD, and AP=CD, in APD and DCE, Ap=cd,∠apd=∠dce, One more condition. Take a look at ∠pad and ∠CDE, according to the outer theorem: ∠adc=∠pad+∠b=∠pad+60°, and ∠ADC is ∠CDE and ∠ade splicing into,

Part of the practice is many, but every thought out of one also more 5~10 points. The positive solution is not yet, the following are a variety of partial approaches:Subtask 1:k=1The length of the LCS is up to 1, which means that there is no j>i and a[j]>a[i] at the same time. is obviously an LDS, the tree-like array directly to ask.Subtask 2:k=2Up to two, which can be combined by two LCS, F[i][j] indicates that the first LCS ends with I, the second is the number of scenarios ending with J, and

all of the time adjusting the execution speed of Delphi 2007 for Win32 in this version, the second reason is that Delphi 2007 for Win32 uses the Fastcode project's results, In particular, the bottom of the System.pas and Sysutils.pas two files. In addition, Delphi 2007 for Win32 compiling and executing the application speed is more than the Delphi 2005/2006 Fast, and Delphi 7 faster than really comparable, if we consider Delphi 2007 for Win32 have than Delphi More than 7 new IDE features, so I

.conf.default.dad_transmits = 0 net.ipv6.conf.default.max_addresses = 1 # optimize the ports used by LB # Increase System File Descriptor restrictions Fs.file-max = 65535 # allow more PIDs (reduce rollover problems); May-Break Some programs 32768 Kernel.pid_max = 65536 # Increase system IP Port limits Net.ipv4.ip_local_port_range = 2000 65000 # increase TCP Maximum buffer size Net.ipv4.tcp_rmem = 4096 87380 8388608 Net.ipv4.tcp_wmem = 4096 87380 8388608 # Add Linux to automatically a

6.conf.default.accept_ra_pinfo = 0 Net.ipv6.conf.default.accept_ra_defrtr = 0 net.ipv6.conf.default.autoconf = 0 Net.ipv6.conf.default.dad_transmits = 0 net.ipv6.conf.default.max_addresses = 1 # optimization for Port usefor LBs # Incre ASE System file descriptor Limit Fs.file-max = 65535 # Allow for more PIDs (to reduce rollover problems); May-Break Some programs 32768 Kernel.pid_max = 65536 # Increase system IP Port limits Net.ipv4.ip_local_port_range = 2000 65000 # Increase TCP max buffer si

to make full use of the bandwidth, it can get much higher bandwidth than TCP Reno in the high-speed network, But it has a very serious RTT inequity. Fairness refers to the equality of network resources that are held between multiple streams that share the same network bottleneck.The TCP send side dynamically adjusts the increment function of the hstcp congestion window by the desired packet loss rate of the network.Window growth mode when congestion avoidance: CWnd = CWnd + A (CWnd)/CWndThe win

product form it is trying to provide behind the name. And the wheels, the business intelligence systems, what's the problem? There are many commercial BI products, foreign more well-known products, such as Tableau, Qlikview, Power BI, domestic claims have been agile, such as Yonghong BI, sail soft Finebi and BDP. In addition, there are products from the Internet industry Company's new recruits, such as Aliyun's quick BI, NetEase's netease

the normal level ... At the end of this article, let's take a look at some topics of the BBR algorithm itself.In fact, as early as 1981, Gail Kleinrock discovered the model used by BBR:Rather than using events such as loss or buffer occupancy, which are only weakly correlated with congestion, BBR starts FR Om Kleinrock ' s formal model ofCongestion and its associated optimal operating point.However, at the time and for the next 30 years, it was thought to be a difficult thing, how do you know

Analysis of traffic and congestion control based on UDP transmission protocol Traffic Control For a network with a bandwidth of 1 Gbps and a RTT of MS BDP = 1,000,000,000*0.1/8 = 12,500,000 bytes = 12207 K = 12 M Traditional TCP receiving window size = 65535 byte = 64 K, obviously not enough The udt uses the package size of 1500 bytes. The default Interface window size is 8192. Therefore The size of the receiving window is = 1500*8192 = 12,288,000 by

[Error] winform1.pas (94): Missing operator or semicolon[Fatal error] project2.dpr (19): cocould not compile used unit 'winform1. pa' If it doesn't work, modify it by yourself and add the following line to the Code:Uses localhost1.webservice1;Then modify the Code as follows:Procedure twinform1.button1 _ click (Sender: system. object; E: system. eventargs );VaR WS: localhost1.webservice1. twebservice1;BeginWS: = localhost1.webservice1. twebservice1.create ();Button1.text: = ws. helloworld ();End;

.conf.default.router_solicitations = 0net.ipv6.conf.default.accept_ra_rtr_pref = 0net.ipv6.conf.default.accept_ra_pinfo = 0net.ipv6.conf.default.accept_ra_defrtr = 0net.ipv6.conf.default.autoconf = 0net.ipv6.conf.default.dad_transmits = 0net.ipv6.conf.default.max_addresses = 1 # Optimization for port usefor LBs# Increase system file descriptor limitfs.file-max = 65535 # Allow for more PIDs (to reduce rollover problems); may break some programs 32768kernel.pid_max = 65536 # Increase system IP por

), resulting in at least 43680 bytes O F traffic for the connections to each remote Steelhead. Additionally, the total size of the packet over your WAN media would also depend on the particular link-layer (such as EThe Rnet header), as well as any other TCP options, the other WAN devices in your network add to these packets.Part 5:high speed mx-tcpHSTCP is a feature you can enable in Steelhead appliances to help reduce WAN data transfers inefficiencies this is caused By limitations with regular

bytes ). 131071 513920/proc/sys/net/core/netdev_max_backlog maximum number of packets that can be sent to the queue when each network interface receives packets at a rate faster than the rate at which the kernel processes these packets. 1000 2000/proc/sys/net/core/somaxconn defines the maximum length of the listening queue for each port in the system. this is a global parameter. 128 2048/proc/sys/net/core/optmem_max indicates the maximum buffer size allowed by each socket. 20480 81920/proc/sys/

, which is a global parameter. 128 2048 /proc/sys/net/core/optmem_max Represents the size of the maximum buffer allowed for each socket. 20480 81920 /proc/sys/net/ipv4/tcp_mem Determine how the TCP stack should reflect memory usage, and each value is in a memory page (usually 4KB). The first value is the lower limit for memory usage, and the second value is the upper limit of the applied pressure that the memory pressure pattern begins to

of the Master 2 before the Master 1, but the Master 1 gave me the direction and method of concrete how to do, I except from the heartfelt gratitude, can do is to write some "attack TCP congestion Control algorithm" article to put people for me, I for everyone's Christian philosophy to pass to more people. Due to the respect of two masters and various friends, I will not post the relevant code, the original message and the chat record, digest the idea of processing, from my direct origin here.BB

system. This is a global parameter. 128 2048/proc/sys/net/core/optmem_max indicates the maximum buffer size allowed by each socket. 20480 81920/proc/sys/net/ipv4/tcp_mem determine how the TCP stack reflects memory usage. The unit of each value is a memory page (usually 4 kb ). The first value is the lower limit of memory usage, the second value is the upper limit of the application pressure on the buffer zone starting from the memory pressure mode, and the third value is the upper limit of memo

= 1 # Tuen IPv6net.ipv6.conf.default.router_solicitations = 0net.ipv6.conf.default.accept_ra_rtr_pref = 0net.ipv6.conf.default.accept_ra_pinfo = 0NET.IPV6.CONF.DEFAULT.ACCEPT_RA_DEFRTR = 0net.ipv6.conf.default.autoconf = 0net.ipv6.conf.default.dad_transmits = 0net.ipv6.conf.default.max_addresses = 1 # optimization for Port usefor LBs# INCR Ease System file Descriptor Limitfs.file-max = 65535 # allow for more PIDs (to reduce rollover problems); May break some programs 32768kernel.pid_max = 65536