beamforming antenna

POJ 3020 Antenna Placement (bipartite graph creation training + minimum path coverage) Antenna Placement Time Limit:1000 MS Memory Limit:65536 K Total Submissions:6692 Accepted:3325 DescriptionThe Global Aerial Research Centre has been allotted the task of building the maximum th generation of mobile phone nets in Sweden. the most striking reason why they got the jo

Antenna Placement Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 6930 Accepted: 3439 DescriptionThe Global aerial Centre have been allotted the task of building the fifth generation of mobile phone nets in swed En. The most striking reason so they got the job, is their discovery of a new, highly noise resistant, antenna. It's called

Antenna Magus 5.5.0 pro\Compusoft.winner.v9.0a2_hao\EPLAN Harness ProD Studio 2.5\Ixray Ixforten 4000 version 4.9.8uu\Mintec.minesight.3d.v7.0.3\NI. Vision.v2015.SP1 1DVD NI Vision 2015\Pix4d.pix4dmapper.pro.v2.0.104.macosx\Techlog learning materials software training \Techlog2014.2\multiphase flow simulation software Schlumberger OLGA 2015.1\[CATIA. P2. V5r16 catia.cadam.drafting.v5r16sp1\338\CPFD. Barracuda.v17.0.0.rarHypermill8.4.zipMpcci v3.03 Lin

The main problem: There are N cities, to establish a radio station in these n cities, each radio station can only cover 2 neighboring cities, ask at least how many wireless power stations need to buildProblem-Solving ideas: English topic good pit, looked at half a day.This problem is similar to POJ-2446 chessboard.All cities can be divided into two point sets, then the connection between the radio station to represent the coverage of the relationship.Because all cities have to be covered, so acc

Question: In a rectangle, there are n Cities '*'. Now all N cities need to cover wireless networks. If a base station is placed, it can cover at most two adjacent cities.How many base stations can be placed to ensure that all cities are wireless? Ideas: Number each city, create two-way edge, run Hungary, and then the number of cities-matching number/2 is the answer Assume that each city needs to build a base station, and then how many matches will reduce the number of base stations. Because the

Question link:Http://poj.org/problem? Id = 3020 Antenna placement Time limit:1000 ms Memory limit:65536 K Total submissions:6692 Accepted:3325 DescriptionThe global aerial research centre has been allotted the task of building the maximum th generation of mobile phone nets in Sweden. the most striking reason why they got the job, is their discovery of a new, highly noise resistant,

Antenna placement Time Limit: 1000 msmemory limit: 65536 K Total submissions: 6342 accepted: 3131Description The global aerial research centre has been allotted the task of building the maximum th generation of mobile phone nets in Sweden. the most striking reason why they got the job, is their discovery of a new, highly noise resistant, antenna. it is called 4 dair, and comes in four types. each type ca

× Winding Process It is a process that combines an antenna and an IC loop to form a module. It takes some time to mount modules one by one on a thin board. Therefore, high costs are not suitable for mass production. However, compared with other manufacturing processes, the tag communication distance is improved. × Etching ProcessIt is a process of forming an antenna by etching aluminum or copper film on

; - }Wuyi the intMainvoid)//POJ 3020 Antenna Placement - { Wu //freopen ("poj_3020.in", "R", stdin); - About intT scanf ("%d", t); $ while(t--) - { - intH, W; scanf ("%d%d", h, W); - for(intI=1; ii) A { +scanf ("%s", S[i] +1); the } - $Un = VN =0; the for(intI=1; ii) the { the for(intj=1; jj) the { - if(S[i][j] = ='*') in { th

#include 2#include 3#include 4 using namespacestd;5 intmatch[ the];6 structnode{7 intx, y;8}dir[4]={{1,0},{-1,0},{0,1},{0,-1}};9Vectorv;Ten intn,m,cnt; one Charmatrix[ -][ -]; a intmp[ -][ -]; - intbook[ the]; - inte[ the][ the]; the voiddeal () { - for(intx=0; x) { - for(inty=0; y) { - if(matrix[x][y]!='*')Continue; + intI=mp[x][y]; - for(intD=0, xx,yy; d4; d++) { +xx=x+dir[d].x; ayy=y+dir[d].y; at if(xx0|| X>=n | | yy0|| Yy

--){scanf"%d%d", m, n);intsum =0;///record number of ' * 'InIt (); for(i=0;i{scanf"%s", G[i]); for(j=0;j{if(G[i][j] = ='*'){///Purchase Relationship DiagramINDEX[I][J] = ++nx;///give me the number.sum++;if(J! =0 g[i][j-1]=='*'){///matches to the left.Addedge (Index[i][j], index[i][j-1]);Addedge (index[i][j-1], index[i][j]);}if(I! =0 g[i-1][J] = ='*'){///with the above can matchAddedge (Index[i][j], index[i-1][J]);Addedge (index[i-1][J], index[i][j]);;}}}}intans = Karp ();printf"%d\n", Sum-ans);}

; memset (Link,-1,sizeof(link)); for(intI=1; i) {memset (Vis,0,sizeof(VIS)); if(Dfs (i)) sum++; } returnsum;}intMain () {intans,i,j,k; while(SCANF ("%d", t)! =EOF) { while(t--) {CNT=0; memset (MM,0,sizeof(mm)); memset (Mark,0,sizeof(Mark)); scanf ("%d%d",n,m); for(i=0; i) { for(j=0; j) {scanf ("%c",temp); if(temp=='*') {Mm[i][j]=++cnt;//each point is represented by a number } } } for(i=0; i)

Reprinted please indicate the source: Thank you Http://user.qzone.qq.com/289065406/blog/1299322779 Tip: do not be misled by the circle of pictures. You can see clearly that '*' is a city, 'O' is an open space, and the antenna of an elliptical circle must cover the city '*', instead of covering the Open Space Question: In a rectangle, there are n Cities '*'. Now all N cities need to cover wireless networks. If a base station is placed, it can cover at

The basis of binary matching. You only need to find out a and B. Search for the four directions of each "*" and record their relationships; Because we read both a-> B and B-> A, we need to divide it by 2; #include#includechar str[41][11];bool mat[40

Question: In a rectangle, there are n Cities '*'. Now all N cities need to cover wireless networks. If a base station is placed, it can cover at most two adjacent cities.How many base stations can be placed to ensure that all cities are

An original Mini-game inspired by gold miners and big fish. In fact, this game has been played for two weeks and is only uploaded until now. Some bugs have not been fixed yet. No way. Busy. Recently, I am engaged in a large-scale webgame with

Black and white coloring and then finding the maximum matching of the Bipartite Graph [cpp]# Include # Include # Include Using namespace std;Const int maxn = 40 + 9;Int n, m;Char a [maxn] [maxn];Struct{Int to, next;} E [maxn * 10*4];Int head [maxn *

Question: In a rectangle, there are n Cities '*'. Now all N cities need to cover wireless networks. If a base station is placed, it can cover at most two adjacent cities.How many base stations can be placed to ensure that all cities are wireless?

Question link: http://poj.org/problem? Id = 3020 First of all, ignore the one that may mislead others (maybe I have poor understanding, or I am misled by a little bit ). An H * w graph is provided. "*" indicates point of interest, and "O" ignores it.

There are n cities in a rectangular grid. Now all N cities need to be covered in wireless networks. For any base station, it can overwrite any adjacent two grids. So if we build a base station together, we can make all the cities covered and use the