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1, "." is a wildcard that represents any one character, for example: "A.C" can match "ANC", "ABC", "ACC"; 2, "[]", in [] can specify the required matching characters, such as: "A[nbc]c" can match "ANC", "ABC", "ACC" But can not match "ANCC", A to Z can be written [a-z],0 to 9 can be written [0-9]; 3, Quantity qualifying symbol, indicating the number of matches (or length) of the symbol: Includes: "*"--0

1. ". "is a wildcard that represents any character, for example,". c can match "anc", "abc", and "acc". 2. "[]". You can specify the matching characters in []. For example: "a [nbc] c" can match "anc", "abc", and "acc", but it cannot match "ancc". a to z can be written as [a-z], 0 to 9 can be written as [0-9]; 3. quantity limit symbol, indicating the number of matches (or length): including: "*" -- 0 or mul

-1]); DOWN[I][J]=max (down[i][j-1],down[fa[i][j-1]][j-1]); DOWN[I][J]=max (down[i][j],mxx[i][j-1]-mii[fa[i][j-1]][j-1]); }}intLCA (intAintb) { if(c[a]c[b]) swap (A, b); intt=c[a]-C[b]; for(intI=0; i -; i++) if((1Fa[a][i]; if(a==b)returnA; for(intI= -; i>=0; i--) if(fa[a][i]!=Fa[b][i]) {a=Fa[a][i]; b=Fa[b][i]; } returnfa[a][0];}intUp_lca (intAintb) { intt=c[a]-c[b],ret=0, minner=inf; for(intI=0; i -; i++) if((1t) {ret=Max (ret,up[a][i]); RET=max (ret,mxx[a][i]-Min

]) ==10) { $id =substr ($cos [$c],0,2); eval ("$id =0x$id;"); $tim =substr ($cos [$c],2,8); eval ("$tim =0x$tim;"); if ($tim >= $conf->wtime) $ANCW [$id]= $cos [$c]; } } if (isset ($_cookie[' an1 ')) $co 1=$_cookie[' An1 ']; ElseIf (isset ($HTTP _cookie_vars[' an1 ')) $co 1= $HTTP _cookie_vars[' an1 ']; Else $co 1 = '; $cos =preg_split ("/x/", $co 1); $max =sizeof ($cos); for ($c =0 $c if (strlen ($cos [$c]) ==10) { $id =substr ($cos [$c],0,2); eval ("$id =0x$id;"

) { if(!dep[it->ID]) {rt[0][it->id]=POS; DFS (it->id,deep+1); Siz[pos]+=siz[it->ID]; } }}voidPrelca () { for(intI=1; i -; i++){ for(intj=1; j) {Rt[i][j]=rt[i-1][j]==-1?-1: rt[i-1][rt[i-1][j]]; } }}intLCA (intUintv) { if(dep[u]Dep[v]) swap (U,V); for(intI=0;i +; i++){ if((Dep[u]-dep[v]) >>i1) {u=Rt[i][u]; } } if(U==V)returnu; for(intI= +; i>=0; i--){ if(rt[i][u]!=Rt[i][v]) {u=Rt[i][u]; V=Rt[i][v]; } } returnrt[0][u];}intJumpintPosintnum) { f

algorithm for a long time, but also to ramble on the reasons for writing this article, I hope not understand wrong =For this problemTest instructions: Seeking the recent public ancestor LCAHere's the Tarjan code you learned.1#include 2#include 3#include 4#include 5#include 6#include 7#include 8 9 using namespacestd;Ten One classEdge A { - Public: - intto ; the intNext; -}e[11000]; - - intn,t,cnt; + intf[11000],depth[11000],anc[11000],p

1. "." is a wildcard that represents any character. For example, "a. c" can match "anc", "abc", and "acc "; 2. "[]", you can specify the matching characters in []. For example, "a [nbc] c" can match "anc", "abc", and "acc" But it cannot match "ancc". a to z can be written as [a-z], 0 to 9 can be written as [0-9]; 3. quantity limit symbol, indicating the number of matching times (or length: Including: "*" --

Simplest tree split update + segment tree Interval summation1#include 2#include 3#include 4 using namespacestd;5 #defineLson l,m,rt6 #defineRson m+1,r,rt7 Const intMAXN =30005;8 intSIZ[MAXN],SON[MAXN],DEP[MAXN],TID[MAXN],TOP[MAXN],FA[MAXN];9 intsum[maxn2],VAL[MAXN];Ten inthead[maxn],cnt,lable; One structnode A { - intV,next; -}e[maxn*2]; the intN; - voidInit () - { -memset (head,-1,sizeof(head)); +CNT = lable =0; - } + voidAddintUintv) A { atE[CNT].V =v; -E[cnt].next =Head[u]; -Head[u] = cnt

vector int>Q[n];intFind (intx) {if(x! = Fa[x])returnFA[X] = Find (fa[x]);returnx;}voidUnion (intXintY) {intFX = Find (x), FY = find (y);if(FY! = FX) Fa[fy] = FX;}voidDfsintu) {Anc[u] = u; for(inti = Head[u]; ~i; i = e[i].next) {intv = e[i].v; DFS (v); Union (U, v); Anc[find (u)] = u; } Vis[u] =true;intSZ = Q[u].size (); for(inti =0; I intv = q[u][i];if(Vis[v]) {printf("%d\n",

1, "." is a wildcard that represents any one character, for example: "A.C" can match "ANC", "ABC", "ACC"; 2, "[]", in [] can specify the required matching characters, such as: "A[nbc]c" can match "ANC", "ABC", "ACC", but can not match "ANCC", A to Z can be written [a-z],0 to 9 can be written [0-9]; 3, Quantity qualifying symbol, indicating the number of matches (or length) of the symbol:Includes: "*"--0 o

the tableMysql> Select Goods_id,minigoods.cat_id,goods_name,category.cat_id,cat_name from Minigoods,category limit 3;+----------+--------+--------------------+--------+----------+| goods_id | cat_id | Goods_name | cat_id | Cat_name |+----------+--------+--------------------+--------+----------+| 1 | 4 | KD876 | 1 | Phone type || 4 | 8 | htcN85 Original Charger | 1 | Phone type || 3 | 8 | Nokia Original 5800 Headphones | 1 | Phone type |+-

} $ for(inti = h[p]; I i =e[i].pre) - { - intto =e[i].to; - if(to = = f)Continue; ACUR[P] =to ; + DFS2 (to, p); theFa[to] =p; - } $VIS[P] =1; the intQsz =q[p].size (); the for(inti =0; i ) the { the intto = Q[p][i].first, id =Q[p][i].second; - if(!vis[to])Continue; in intANC =Find (to); the if(ANC = =to ) the { AboutLL d = dep[p]-Dep[to] +1; theAns[id] = (1.0* Dis[p

Wellington National Cemetery Arlingtonnationalcemetery is the largest and most famous national military cemetery in the United States. The family of arms: the unknown soldiers who died in the war and the Vietnam War, known as the tomb of unknown soldiers (Tomb of unknowns ); The arington house, built on a hill, is surrounded by soldiers of the northern army who died in the war of north and south. Information-based work of the National Cemetery in arn In order to carry out daily s

Rogu p31_lca, HDU2586, rogu P1967 freight car transportation, multiplication lca, tree multiplication, p3w.lcap1967 Multiply lca board loogu P3379 1 #include How far away? HDU-2586 (two points on the tree) The method is to find the distance from dis [I] to the root node, then two points, the distance between B is $ dis [a] + dis [B]-2 * dis [lca (a, B)] $ Error notes: Line 2 is written as anc [x] [I] = anc

Fever fish:Recently, some netizens often asked me how to renew my earphones. In fact, I have never been reluctant to deliberately hide a pair of headphones, because if it is done well, it is just a little faster to enter the status, such as hd600, it would have taken about two hours to get into the status every day. However, if you do not have a hard time, it may shorten the service life of your earphones and even cause permanent physical damage to yo

1 intn,m,hcnt,qcnt;2 intHEAD[MAXN],QUERY[MAXN],VIS[MAXN];3 intAnc[maxn],fp[maxn],indu[maxn],ans[n];4 structnode{5 intTo,next;6 }NODE[MAXN];7 structquery{8 intTo,next,index;9 }que[n];Ten intFINDP (intx) {returnfp[x]==x?x:fp[x]=FINDP (fp[x]);} OneInlinevoidinit () { AMST (ANC,0); MST (Indu,0); MST (NUM,0); -MST (head,-1); MST (query,-1); MST (Vis,0); -MST (ans,0); hcnt=qcnt=0; the } -InlinevoidAddintXinty) { -node[hcnt].to=y;node[hcnt].next=Head

1 intn,m,hcnt,qcnt;2 intSx,sy;3 structnode{4 intTo,next;5 }NODE[MAXN];6 structquery{7 intX,ne;8 inti;9}query[maxn1];Ten intHEAD[MAXN],VIS[MAXN],INDU[MAXN]; One intfp[maxn],anc[maxn],que[maxn],ans[maxn1]; A intFINDP (intx) {returnfp[x]==x?x:fp[x]=FINDP (fp[x]);} -InlinevoidAddintXinty) { -node[hcnt].to=y;node[hcnt].next=Head[x]; thehead[x]=hcnt++; - } -InlinevoidADDQ (intXintYinti) { -Query[qcnt].x=x;query[qcnt].ne=Que[y]; +query[qcnt].i=i;

. Over the years, we have spent more than 6% of our sales on research and development, or even 10% in years. Our plan is to use new products to guide the public, rather than asking them what they need. The public does not know what they can buy, but we know. Therefore, we do not conduct a lot of market research, but improve our ideas on the use of products and products, and then educate the public through communication to create a market. Sometimes, I naturally come up with a new product idea.Fo

I have no interest in pop songs. I did not know who the Four Kings were for a long time in elementary school, I used to think that "Andy Lau" is the one who played the pig in "Journey to the West" (that is called Andy Ma ). I was surprised and puzzled when I saw the girls chasing the Tigers frantically. When I got to high school, I only occasionally listened to broadcast programs. But from college, I became addicted to music. If we trace it back, we should have got our first Walkman from the fre

], UFS[MAXM];structedges{intS, T, Maxi; Edgesints =0,intt =0,intMaxi =0): s (s), T (t), Maxi (maxi) {}BOOL operatorConstedges b)Const{returnMaxi > B.maxi; }}EDGE[MAXN >>1];intU[MAXN], V[MAXN], W[MAXN], NXT[MAXN], PNT[MAXM], E;intfa[ the][MAXM], g[ the][MAXM], DEP[MAXM];BOOLVIS[MAXM];intFindanc (intx) {returnx = = Anc[x]? X:ANC[X] = Findanc (anc[x]); }intFindufs (intx) {returnx = = Ufs[x]? X:UFS[X] = Findufs