best buy software

.　　Sima Zhao shouted: "The real estate industry is a fart, and no one needs to pretend to be forced. You think I don't know that you hire people to buy these houses ."　　Zhuge Liang smiled lightly: "Look at it carefully ."　　Sima Zhao took a close look. the buyers and sellers signed contracts with the real estate agents, which were black and white. They were not fake and unknown. So he shouted, turned over and fell into the horse, and vomited blood for

Tags: des style blog color Io AR for SP Div Say you have an array for whichITh element is the price of a given stock on dayI. Design an algorithm to find the maximum profit. you may complete as your transactions as you like (ie, buy one and every one share of the stock multiple times ). however, you may not engage in multiple transactions at the same time (ie, you must wait the stock before you buy again ).

121. Best time to Buy and Sell StockSay you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Example 1:Input: [7, 1, 5, 3, 6, 4]output:5max. difference = 6-1 = 5 (Not 7-1 = 6, as selling-price needs-be-larger than buying price)

Question 1: Buy Books A bookstore has introduced a set of books with a total of 3 volumes. Each volume is priced at 60 yuan. The bookstore has launched an activity to engage in promotions. The activity is as follows: If you purchase one of these volumes separately, you can enjoy a 9.5 discount. If you purchase two different volumes at the same time, you can get a discount. If you purchase three different volumes at the same time, you can get a 8.5 di

Tags: leetcode Best time to buy and buy stock I Only one operation: Minimum value that appears before the premin record is maintained The Code is as follows: Int maxprofit (vector Best time to buy and stock Stock II Unlimited operation: When ==> current price> purchase price, sell The Code is as follows: Int maxprofit (vector Best time to

The experiment of queue data structure: line up to buy food Time limit:1000ms Memory limit:65536k Topic Description NarrationThere are many people who buy rice at noon, canteen is really too crowded, buy a meal laborious, science and technology big Child is very clever, straight to the political pass supermarket, haha, indeed, political pass supermark

1 Public classSolution {2 Public intMaxprofit (int[] prices) {3 intLastbuy = 0, Lastsell = 0, buy = integer.min_value, sell = 0;4 for(inti = 0; i ) {5Lastbuy =buy;6buy = Math.max (Buy, Lastsell-prices[i]);7 8Lastsell =sell;9Sell = Math.max (Sell, Lastbuy +prices[i]);Ten } One returnsell; A } -}Lastsell = Sell

{BS Trading formula--b Point buy, s point sell, Red Holding, Green}var1:=sum (Max (Max (High-low,abs (High-ref (close,1)), ABS (Low-ref (close,1)), 25) ; Var2:=high-ref (high,1); Var3:=ref (low,1)-low; Var4:=sum (IF (var2>0 and var2>var3,var2,0), 25); Var5:=sum (IF (var3>0 and var3>var2,var3,0), 25); VAR6:=VAR4*100/VAR1; VAR7:=VAR5*100/VAR1; Var8:=ma (ABS (VAR7-VAR6)/(VAR7+VAR6) *100,15); Var9:= (Var8+ref (var8,15))/2; Buyy:=zig (3,10); Selll:=ma (buy

Test instructions: Given a sequence, the element I represents the price of this stock for the first day, asking how much money can be earned at the best time to buy and sell? Buy only once, and only 1 shares, assuming unlimited cost.Idea: To find a low-priced time to buy, at the highest price when the sale of profits will be the biggest. But time is not a conflic

In recent years, with the rise of the e-commerce platform, the products are constantly attracting our eyes, in the face of high prices so that users have to reluctantly and deterred. In the face of the majority of users difficult to choose, but the attention of a piece of Hi-Buy will be committed to creating a shopping and entertainment in one, 100% fair and impartial, 100% authentic protection of the new shopping platform.A piece of Hi-

Best time to Buy and Sell Stock ITopic:Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Ideas:Just find the maximum difference, max (prices[j]–prices[i]), I /** * @param {number[]} prices * @return {number}*/varMaxprofi

How to buy 100 chickens with 100 bucks? Known Rooster 5 pieces One, hen 3 pieces One, chick a piece of money 3 only:A For loop nesting is required, and by optimizing the code, you can speed up the operation.DOCTYPE HTML>HTMLLang= "en">Head> MetaCharSet= "UTF-8"> title>hundred dollars to buy hundred chickenstitle>Head>Body>P>How to buy 100 chickens with 100

Original title address: https://oj.leetcode.com/problems/best-time-to-buy-and-sell-stock-iii/Test instructionsSay you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You are in most of the transactions.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).The idea of solving pro

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. A functional and practical, easy to use the U disk does not need to go through the complex to buy, through the above four purchase to decide, we can also go to the shop on-site experience, easy to feel the right U disk, improve efficiency, the moment will all the orderly, no longer afraid of a wide range of documents and fast-paced work. Large Capacity high speed From the development of the U disk this year, 18GB capacity of U disk has become th

Description a regular game before the start of the ticket work is underway. Each ticket is 50 yuan, the existing K (1 21 21 1Sample Output01HINT The main idea: DP is to see the relationship between the two states do not look at the whole, so dp[i][j] = Dp[i-1][j] is certainly satisfied, if the number of n is greater than or equal to M, the current can find the open, dp[i][j] + = dp[i][j-1];#include #includeusing namespacestd;intMain () {intT; scanf ("%d",T); while(t--){ intdp[ -][ -]; Me

There is a set of arrays representing the price of the stockHow do I get the most profit from a one-time sale?1 Public intMaxprofit (int[] prices) {2 if(prices.length==0)return0;3 intMaxprofit=0;4 intMin=prices[0];5 for(inti=0;i)6 {7maxprofit=prices[i]-min>maxprofit?prices[i]-Min:maxprofit;8Min=prices[i]prices[i]:min;9 }Ten One returnMaxprofit; A - -}best time to