best computer virus program

Experimental Purpose:By disassembling a simple C program, analyze the assembly code to understand how the computer worksExperimental process:Programming with VI programs: int g (int x) { return x + 3; } int f (int x) { return g (x); } int main (void) { return F (8) + 1; } Save As Main.c fileUsing Disassembly commandsGcc-s-O main.s main,c-m32-S: Compiled as assembly

"Internet Information Service-default website" stops working and cannot be started. Go to "Administrative Tools-service" and start the world wide web Hing service. The result is displayed with the prompt "unable to start the World Wide Web Publishing Service on the Local Computer" error 127: the specified program cannot be found ".To solve this problem, you can search the Internet for many solutions and try

Recently I learned about network filtering and found that there are manyProgramThe filtering function is shown on the surface, but network data cannot be filtered. In my first step, I want to write a simple program to prevent the computer from connecting to the Internet. After searching for the Internet and the help of msdn, I formed the followingCodeIt is reasonable to say that it can achieve the goal, but

Two or three years without the SQL Server, today because the company needs, and then pick up again to learn (previously used to forget the light). You do not want to encounter an old problem when you first install-"A previous program installation has created a pending file operation on the installation computer." Solution, Locate the PendingFileRenameOperations project in Hkey_local_machine/system/current

The program is written in the scheme language and will be implemented in other languages later.#lang Racket;Fibonacci Logarithm Method;Filter(define (fib N) (Fib-iter1 0 0 1N)) (define (square x) (* x x)) (define (Fib-iter a b p q count) (Cond (= count 0) b);count = 0 o'clock, fib (1) = 0(even. Count);if it is an even number, then the value of P,q is ;p = p^2 + q^2 ;q = 2pq + q^2 ;the number of count is halved( Fib-iter a B (+

Detailed steps are as follows: 1, right click on the taskbar application icon, and then right-click the record you want to delete, click Select "Remove from List"; 2, if you want to clear all records at once, right click on the taskbar blank, select Attributes; 3, switch to the "Start Menu" tab, cancel the "privacy" column in the "store and display the most recent in the" Start menu and taskbar open items "Check, and click OK;" 4, and then right click on the taskbar

1. First of all, we open the Win7 flagship computer's Start menu, and then in the Start menu to find the option we want to query the storage path, as shown in the following figure, the small weave here to find a cool dog music program, after that, we right-click on this option, in the Appear down menu to select Properties. 2. Then there will be this cool Dog music properties Settings window, we will switch the interface to the shortcut in this

About: a previously installed program has created a pending file on the computer. How can this problem be solved? I installed SQL server before and deleted it later. Now, the following error occurs:ProgramInstall a file that has been suspended on the installation computer. You must restart the computer before runnin

Failed to reboot the computer, unable to find a solution to the SQL uninstall problem, as follows Question 1: It is strange that the Control Panel can not find the SQL Uninstall program , and later on the Internet to find the need to repair the Windows Uninstall/install program , website download website: Http://download.microsoft.com/download/7/E/9/7E9188C0-25

final can modify variables, which is another use of final. A Java class that can be inherited by default, but cannot be inherited after the final keyword is added, as follows: Public Final class Base { //...}A non-final class in which the public/protected instance method can be overridden by default, but cannot be overridden after the final keyword is added, as follows: Public class Base { publicfinalvoid Test () { System.out.println ("cannot be overridden" ); }}SummaryIn this s

: Press the number in array B to 0->a, 1->b, 2->c, ..., 24->y, 25->z, convert the rules to ciphertext For example: Encryption July, Matrix A=[11 8;3 7] (semicolon denotes another line) Step1: Convert July to an array a={9, one, one, and one}; STEP2: Divide a into {9, 20},{11, 24} two parts Step3: Because [9,] * [one 8;3 7] = [159, 212] [11, 24] * [11 8;3 7]=[19 3, []] b=[159%, 212%, 193%, [3, 4, one,] Step4: Ciphertext is DELW Your task is: give you ciphertext and matrix A, the ori

Last issue we said B/s technology development chat has what advantages, this issue we come to the simple to say with C/s technology development and what characteristics?650) this.width=650; "src=" http://s3.51cto.com/wyfs02/M00/58/A8/wKioL1S3Xdjz_HIYAADmeB7qilo895.jpg "title=" D.jpg " alt= "Wkiol1s3xdjz_hiyaadmeb7qilo895.jpg"/>Stability and flexibility: the application and service can be separated by C/s technology.Second, security: C/S corresponds to the structure mode, generally only applicabl

How can I determine whether the CPU of a computer is aligned with the big end or small-character end? First, you must understand what is a big end and a small end. The large-end Mode means that the high bytes of the word data are stored in the low address, while the low bytes of the word data are stored in the high address. Small-end format: In contrast to the large-end storage format, the low-end storage format stores the low bytes of word data, and

When executing Rational Rose, if this error occurs, check whether the environment variables have the common address. If the environment variables are not directly matched, click OK. The configuration is as follows: D: \ Program Files \ rational \ common; my win7 directly uses the uppercase common path without the following information. Assume that some of them can be changed again according to the following information. The following information is fr

..12] of String;an array for the abbreviated name of the month, which is the string of the MMM identity that is displayed when using FormatDateTimelongmonthnames:array[1..12] of String;An array that is used to fully represent the name of the month, which is the mmmm identity string that is displayed when using FormatDateTimeshortdaynames:array[1..7] of String;An array that is used to indicate the name of the day of the week, which is the DDD identity string that is displayed when using FormatDat

(scanf ("%d", cass); cass;cass--)111 //for (scanf ("%d", cas), cass=1;cass the //while (~scanf ("%s", s))113 while(~SCANF ("%d",N)) the { theaans=0; thex=l=n+1, y=r=0;117 for(i=1; i"%d", A +i);118 for(i=1; i)119 { - if(!a[i])Continue;121 if(ABS (A[I]-I) >1) {Work1 (i); Break;}122 if(a[i]-i==1) X=min (x,i), y=Max (y,i);123 if(a[i]-i==-1) L=min (l,i), r=Max (y,i);124 } the if(iContinue;126 i

Contrast MoeTime limit:2000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 0 Accepted Submission (s): 0Problem description has 2N individuals, each with an Moe mi (1They are required to be divided into n pairs, so that the sum of the contrast values is maximal.The meaning of the contrast value is as follows: if x and Y are a pair, they contribute | mx-my| point contrast value. The first line of input is a number T, which indicates the number of test instances

- #defineMAX 0x7f7f7f7f to #definePI 3.14159265358979323 + #defineN 100004 - using namespacestd; thetypedefLong LongLL; * intCas,cass; $ intN,m,lll,ans;Panax Notoginseng LL Aans; - LL E[n],sum[n],l[n],r[n]; the LL A; + CharS[n]; A intMain () the { + #ifndef Online_judge - //freopen ("1.txt", "R", stdin); $ //freopen ("2.txt", "w", stdout); $ #endif - inti,j,k; - LL x, y; the //for (scanf ("%d", cass); cass;cass--) - //for (scanf ("%d", cas), cass=1;cassWuyi //while (~scanf ("%s", s)) th

voidWorkintXintc[]) + { A inti; thec[0]=x/ .; + for(i=1; i .); i++) c[i]=c[0]+1; - for(I= (x .)+1;i .; i++) c[i]=c[0]; $ } $ intMain () - { - #ifndef Online_judge the //freopen ("1.txt", "R", stdin); - //freopen ("2.txt", "w", stdout);Wuyi #endif the inti,j,k; - Wu //for (scanf ("%d", cass); cass;cass--) - //for (scanf ("%d", cas), cass=1;cass About //while (~scanf ("%s", s+1)) $ while(~SCANF ("%d",N)) - { -scanf"%d",m); -aans=0; A Work (n,a); + Work (m,b); t

. Start with EIP pointing at 19 lines, EBP esp in 0 position (01234 on the right is set for convenient analysis) 2.PUSHL%ebp, the EBP value stack 3.movl%esp,%ebp, Assign ESP value to EBP 4.subl $4,%esp, move esp down one grid 5.movl $33, (%ESP), save 33 at the point where ESP refers to 6.call F, call the F function, and the EIP 24 press stack, at which point the EIP points to the F function 7.pushl%ebp, and the EBP value is stacked at this time 8. movl %esp,%ebp,将esp值赋给eb