best design books 2018

2018-2019-1 20165228 "The foundation of Information security system design" The second week study summary textbook learning content Summary information = bit + context Unsigned encoding: Represents a number greater than or equal to zero based on the traditional binary notation Complement coding: represents the most common way to sign a certificate, a number that can be expressed or positive or negativ

2018-2019 20165219 Summary of storage technology in week 5 of Information Security System Design Basics Random Access Memory: Comparison of SRAM and DRAM, traditional DRAM and enhanced dram Enhanced DRAM: Fast page mode DRAM: allows continuous access to the same row to get services directly from the row buffer. Extended Data Output DRAM: Allows CAS signals to be more time-intensive. Synchronous DRAM: SD

20165237 2017-2018-2 "Java Program Design" Tenth week exam complement and programming problem knowledge points1. A linked list is a data structure consisting of several objects called nodes, each of which contains a reference to the next node.2. The class method provided by the collections class for sorting and finding is as follows: public static sort (ListData Structure-Sort:Topic:In data structures and a

problems encountered in the experiment appearedExecuting tasks: app:assembleDebugThe problem, after Baidu found Androidstudio appeared executing tasks:app:assembleDebug.build.gradle(module:app)in the filetestApplicationId“com.cn.skypiea.test" testInstrumentationRunner "android.test.InstrumentationTestRunner"After you have commented, you can package it successfully.AppearExecution failed for task ‘:app:preDebugAndroidTestBuildThe problem, Baidu found a blog post,Build->Rebuild ProjectYou can the

2018-2019-1 20165210 "Information Security system Design Fundamentals" 4th Week study summary Textbook Learning content Summary ISA Concept: The byte-level encoding of a processor-supported instruction and instruction is called its instruction set architecture Isa.While the processor performance and complexity of each manufacturer is increasing, the different models remain compatible at the IS

processor design, it is often necessary to compare a signal to a number of possible matching signals to detect if a certain instruction code being processed is part of a class of instruction code.Sequential implementation of Y86-64Organize the processing into stages1. For OPL (integer and logical Operations), RRMOVL (register-register transfer) and IRMOVL (immediate count-register transfer)2. For RMMOVL and Mrmov3. For PUSHL and POPL4. For jump, call

for real-time synchronous Replication14.3 use DRBD for real-time synchronization of non-shared storage14.4 other high-availability design solutions14.5 comparison of advantages and disadvantages of various high availability solutionsConclusion 14.615. MySQL Server System Monitoring15.1 Monitoring System Design15.2 running status monitoring15.3 Performance Status MonitoringConclusion 15.4AppendixA ,? Set up an experiment and test environmentA.1 MySQL

, software experience easy to learn, more suitable for children of low age　　2). Sticky good, let students learn quickly, and impressiveThese are basic things, but it is very difficult to actually achieve them.Current work done:　　1). Introduce the left and right sliding effect, the interaction of finger swipe is more suitable for mobile phone application　　2). Identify each speech block area and display a small horn to indicate that this is the appropriate voice areaNot enough, feel the user exper

2018-2019-1 20165333 "Information Security system Design Fundamentals" Third Week study summarySummary of learning contents of textbookThe machine-level representation of the program:Two important abstractions of computer systemsISA (Instruction set architecture): Instruction set architecture, machine-level program format and behavior. Defines the format of the processor status directives and the effect of

typically start with uppercase def __init__ (self,age): self.age =age# gives self an age method with a value of input age,,p.age=age name=" yehaibin " # data properties # for def Qiong (self): print ( ' zhengzaitutan " ,self.age ) del china.name 2.1.4 Increase　　　　classChina:#when declaring a class, it is usually preceded by uppercase def __init__(self,age): Self.age=age#Given to self an age method, the value of the input age,,p.age=ageName='Yehaibin'#Data Properties #

is added to the Dirty page list. The pages in the Dirty page list are then periodically written back to disk by a process (write-back process), so that the data in the disk is eventually consistent with in-memory.11. The page cache is searched by two parameters address_space redemption plus an offset. Each address_space object has a unique cardinality, which is stored in the address_space struct. The cardinality is a binary tree, and you can quickly retrieve the desired page in the cardinality

in memory, because this location can overwrite the return address exactly after an overflow occurs. And strcpy(buffer+100,shellcode); This sentence tells us again, Shellcode is saved in buffer + 100 the position. Below we will detail how to get the address we need to add.Now we're going to get shellcode in memory addressEnter the command:$ gdb stack$ disass mainNext:7, according to the statement strcpy (buffer + 100,shellcode); We calculate Shellcode's address as 0xffffd2d0 (hex) + 0x64 (hex of

Summary of the learning contents of the textbook fourth Chapter processor Architecture Y86-64 instruction set architectureThe "programmer" here refers to the person who writes the program with the assembler code, or the compiler that produces the machine code . The state of y86-64 is similar to x86-64.Y86-64 directive X86-64 's MOVQ instruction is divided into 4 different instructions: IRMOVQ,RRMOVQ,MRMOVQ,RMMOVQ, which explicitly indicates the source and destination format, and the source

, delete the node and set the parent's child reference to null. The color of brothers is the most important thing to delete. Problems and Solutions in teaching material Learning Problem 1: In the deletion of the red/black tree, an iteration termination condition is (current. Color = red), which cannot be understood. Problem 1: because the number of black nodes in each path is the same, when the current node is red, the iteration conditions are met until the current node is red, and al

selection: determine where the desired word starts in the block. Associated High-speed cache:1. group selection in group-connected high-speed cache: Same as group selection in direct ing high-speed cache, group index bit Identification Group.2. Row matching and word selection in the group-connected high-speed cache: each group is considered as a small memory associated with a (Key, value) pair array,3. Input key to return the value in the corresponding array. The cache must search for each row

layer and find it in the cache content at the K layer. You can directly read data at the K layer, which is called cache hit. Cache miss. No data is found at the K layer. The cache at the K layer needs to retrieve the block containing objects from the cache at the K + 1 layer. If the K layer is full, overwrite an existing block. Cool hit, the K layer has nothing, so it does not hit. High-speed cache memory, mainly the size (p426) and probability (p431)Summary of test errors last week

shift x>>k: Move the K-bit right and the value at the left to complement K's most significant bit Logical right Shift x>>>k: Move K-bit right, left complement K 0 Use arithmetic right shift for signed number, logical right shift for unsigned numberInteger representation Information = bit + context unsigned integer: b2u4[0011]=0 2^3+0 2^2+1 2^1+1 2^0=3 Signed integer-complement code: B2t4[1011]=-1 2^3+0 2^2+1 2^1+1 2^0=-5 Unsigned number means you need to append the suf

, and the time command on the video did not exist, so I did the function of adding the previous blog to the experiment.Edit TEST.c FilePS: Laboratory building too card la la la La.The added code is as followsThe experiment used a lot of knowledge of the previous weeks of experiments, which shows the importance of the accumulation of notes.After a long wait finally OKExecute Socket command test, run successfullyExecute the socket-asm command, return 3,,, bright there is a problem,,, back to the S

Today, we have collected 10 excellent free ebook sharing designers. E-books represent the digital publications that people have read and distinguish them from traditional publications that use paper as the carrier. e-books use computer technology to extract certain text, images, sounds, images, and other information. Electronic Books are easier to carry and read

readers to a page, and in contrast, you can create an organized hierarchy between different elements. Keep in mind an important rule: to achieve effective comparisons, contrast must be strong. Don't be afraid to shrink. ? How is it implemented? You can increase the contrast by font selection, line width, color, shape, size, space, and so on. !! The problem to avoiddon't hesitate. If you want to make comparisons, increase your strength. Do not compare a thick line with a thicker line. Do not com