best network cable tester

The tree backpack as a group backpack, the return of the temporary negative is also possible, and the value of the income is also very large, so no longer let the income of the current subscript, put into the array to save, set F[x][t] for the X-root of the sub-tree select T to watch the program, The biggest benefit of the TV station (let you ask what is not necessarily exist in the array inside, it may be set to subscript and then judge the feasibility)This problem is very special, the general

- inthead[n],cur; - ints,t; -queueint>Q; + intCap[n],fr[n]; - + voidAdd_edge (intLintRintf) A { ated[cur]=(Edge) {head[l],r,f}; -head[l]=cur++; -Ed[cur]= (Edge) {head[r],l,0}; -head[r]=cur++; - } - in intn,m; - int Get; to BOOLek () + { -memset (Cap,0,sizeof(CAP)); thecap[s]=INF; * while(!q.empty ()) Q.pop (); $ Q.push (s);Panax Notoginseng while(!q.empty ()) - { the intu=Q.front (); Q.pop (); + for(inti=head[u];i!=-1; i=ed[i].nxt) A if(!cap[ed[i].t

The simple query of this function solves the problem I have encountered. Learn a lot about the knowledge and implementation of the SYS file system for the Linux kernel. Thanks to the @win of the crowd for their hints. The network card has the function of carrier interception physically, when the network connection is complete or the network link is disconnected,

} the About intMain () the { the while(SCANF ("%d%d", n,m)! =EOF) the { + inta,b,ans=INF; -memset (Cap,0,sizeof(CAP)); thenodes=2*N;Bayi for(intI=0; i) thecap[i][i+n]=1; the for(intI=0; i) - { -scanf"(%d,%d)",a,b); thecap[a+n][b]=cap[b+n][a]=INF; the } the for(intv=1; v) the { -ans=min (Ans,max_flow (n,v)); the } the if(ans==INF) theans=N;94printf"%d\n", ans); the }

Links:http://poj.org/problem?id=1966Test Instructions: an undirected graph, n points, M edges, to find the vertex connectivity of this graph.idea: vertex connectivity, that is, the number of cut points in the minimum cut point set, the general method of finding the vertex connectivity of undirected graphs is to transform to the minimum cut of the network flow.Build diagram:(1) The original image of each point I split, split for I ' and I ', I ' to I '

Silver" crime is not even customer magnetic stripe information need. Officer Liu said, "net silver" crime through the Trojan program remote control of your computer, even if the use of the bank's U-Shield also useless, will be criminals steal your bank card information, "because your computer has been controlled by criminals." ” In response to the "net silver" crime, Officer Liu gave a simple method, that is, when the use of net silver if suddenly the computer appears abnormal display (such as

(inti = head[x]; I i =Edge[i].next) { intv =edge[i].to; if(EDGE[I].W dep[v] = = Dep[x] +1) {k=Dinic (V,min (rest, EDGE[I].W)); if(!k) Dep[v] =0; EDGE[I].W-=K; Edge[i^1].W + =K; Rest-=K; } } returnFlow-rest;}BOOLBFs () {memset (DEP,0,sizeof(DEP)); Queueint>Q; Q.push (s); Dep[s]=1; while(!Q.empty ()) { intx =Q.front (); Q.pop (); for(inti = head[x]; I i =Edge[i].next) { intv =edge[i].to; if(EDGE[I].W !)Dep[v]) {Q.push (v); DEP[V]= Dep[x] +1; if(v =