best time to buy imac

I. Title DescriptionSay you had an array for which the i-th element was the price of a given stock on day I.Design an algorithm to find the maximum profit. You are in most of the transactions.Note:you engage in multiple transactions at the same time (ie, you must sell the stock before you buy again).Two. Topic analysisCompared with the first two questions, this problem limits the number of trades traded, up

Topic Say you has an array for which the I-th element is the price of a given-stock on day I. If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit. Method It is similar to finding the maximum and minimum values in an array at the same time. Constraints: The minimum value can only be pr

best time to Buy and Sell Stock IIIProblem:Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You are in most of the transactions.Ideas:Dynamic planningMy Code: Public classSolution { Public intMaxprofit (int[] prices) { if(Prices = =NULL|| Prices.length return0; intSize =prices.length; int[] left =New int[size]; int

Description:Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. Transactions at the most K.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).Credits:Special thanks to @Freezen for adding this problem and creating all test cases.Dynamic planning, Recursive: reference: http

/* * 121. best time to Buy and Sell Stock * This topic is simple, but I still do it wrong. This problem is more than you think. * First the order of Min and Max does not matter. In addition, you can start looping from 0 without waiting for 1 to start */ public Span style= "color: #0000ff;" >int maxprofit (int [] prices) { int min = integer.max_value, MAX = 0; for (int i = 0; i = Math.min (min, pr

Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. Transactions at the most K .Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).Feel this problem is too difficult, because the request can only be traded, so in consideration of peaks, trough the basis to consider the num

Topic:Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Ideas:1. The goal is to find the difference in the array of two values (the maximum difference), if the large number after the small number2. Iterate through the array, set a current min min (initially integer

TopicSay you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.It's time complexity, a line of code from the truth ... Still did not think out, looked at the discuss only then knew the answer.Codepublic class Solution {public

An extension of the best time to Buy and Sell Stock III. The idea was still to use dynamic programming (see here for detailed introduction). However, in this problem, some trick (the quickprofit function below) are required to pass the TLE.The code is rewritten below.1 classSolution {2 Public:3 intMaxprofit (intK, vectorint>prices) {4 intn =prices.size ();5 if(k >= N/2)returnQuickprofit

Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You are in most of the transactions.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).1 Public classSolution {2 Public intMaxprofit (int[] prices) {3 if(prices.length) {4 return0;5 }6 7

Original title address: https://leetcode.com/problems/best-time-to-buy-and-sell-stock/The content is in the code and comments, it is not wordy.Class Solution {Public:int Maxprofit (vectorbest time to Buy and Sell Stock--leetcode

[LeetCode] Best Time to Buy and keep Stock IV, leetcode= Say you have an array for which Ith Element is the price of a given stock on day I . Design an algorithm to find the maximum profit. You may complete at most k transactions. Note:You may not engage in multiple transactions at the same time (ie, you must encrypt the stock before you

Problem Description:Say you has an array for which the i-th element is the price of a given-stock on dayI.Design an algorithm to find the maximum profit. You are in most of the transactions.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).Basic idea:Dynamic Planning method‘‘‘// f[k, ii] represents the max profit up until prices[ii] (Note: NOT ending wi

Given an array, the first element of it is the price of the first day of a given stock.Design an algorithm to calculate the maximum profit you can get. You can do as many trades as possible (buy and sell a stock).Note: You cannot participate in multiple transactions at the same time (you must sell the prior stock before buying again).C++classSolution { Public: intMaxprofit (vectorint>prices) { i

Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.public class Solution {public int maxprofit (int[] prices) { if (prices.length　　(Array) 121. best time to Buy and S

Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Idea: Note that the maximum-minimum value cannot be simply set. Selling must take place after the purchase, the smallest worth before the maximum value.classSolution { Public: intMaxprofit (vectorint> prices) {

Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit. Public classSolution { Public intMaxprofit (int[] prices) { intMax = 0; intMin =Integer.max_value; intSize =prices.length; for(inti=0;i) { intTMP = prices[i]-min; Max= Tmp>max?Tmp:max; if(prices[

Consider that the price of a stock is constantly changing, and selling can only be done after buying. and can only buy and sell once.I want to sweep it at the beginning and ask for the smallest, but certainly not so simple. you're 484 stupid .Because it can only be sold once, if I sell, the possible profit value is, Prices[i]-min, is today's price.Comparing this value to the previous possible maximum, you can get the maximum possible value for the fir

Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Example 1:Input: [7, 1, 5, 3, 6, 4]output:5max. difference = 6-1 = 5 (Not 7-1 = 6, as selling price needsinput: [7, 6, 4, 3, 1]output:0in this case, no transaction are done, i.e. Max Profit = 0.The code is as follow

Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.We solve the problem by examples:Suppose the input array is: [2, 1, 3, 4, 5, 4].Then, the corresponding diagram is as the following:5/ \4/4/ \ /3 32/\ /1So, what we actually has to does is to find the difference val