best time to buy imac

Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Analyse:dp[i] = max (dp[i-1], prices[i]-lowest[0,..., i-1]).Runtime:8ms.1 classSolution {2 Public:3 intMaxprofit (vectorint>prices) {4 Const intn =prices.size ();5 if(n = =0)return 0;6 7

Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit. Public classSolution { Public intMaxprofit (int[] prices) { if(Prices.length = = 0) return0; intProfit = 0; intMin = prices[0]; for(inti=0;i){ if(prices[i]min) {min=prices[i];//keep tr

: The profit earned at the current price (if you don't make money, you don't sell).①, if Curmax = 0, means that the current value is smaller than the value of the front;②, Curmax > 0, i.e., Curmax = (price[i-1]-price[i-2] + price[i]-price[i-1]) = Price[i]-price[i-1]. That is, the current price is the maximum value, and the lowest value is subtracted from the front.Max: The maximum profit in the total process. Public int maxProfit2 (int[] prices) { int curmax = 0, max = 0;

Say you have an array for whichITh element is the price of a given stock on dayI. Design an algorithm to find the maximum profit. you may complete as your transactions as you like (ie, buy one and every one share of the stock multiple times ). however, you may not engage in multiple transactions at the same time (ie, you must wait the stock before you buy again )

Say you have an array for which the ith element is the price of a given stock on day I. If you were only permitted to complete at most one transaction (ie, buy one and every one share of the stock), design an algorithm to find the maximum profit. Analysis: the maximum price difference between buying and selling is calculated. You only need to calculate the price difference between today and the lowest price in history, and compare it with the maximum

Say you have an array for whichITh element is the price of a given stock on dayI. If you were only permitted to complete at most one transaction (ie, buy one and every one share of the stock), design an algorithm to find the maximum profit. At the beginning, I thought it was the maximum value minus the minimum value. However, because the purchase occurred before the sale, the minimum value buy and the maxim

Say you have an array for whichITh element is the price of a given stock on dayI. Design an algorithm to find the maximum profit. you may complete as your transactions as you like (ie, buy one and every one share of the stock multiple times ). however, you may not engage in multiple transactions at the same time (ie, you must wait the stock before you buy again

Title:Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.idea: A single scan can be. You just need to find the maximum growth . Max (prices[j]–prices[i]), I From the point of travel, the current price minus the previous lowest price is the maximum profit that can b

Title Link: click~/* Test instructions: An array, the element I represents the price of the stock of day I, allow up to two times to buy and sell, for maximum profit *//** * idea: Record the maximum profit of the day with the Currprofit array, scan the array from start to finish to get the * Currprofit = max (Currpor Fit[i], prices[i]-low) * * Record the maximum profit after the day with a futureprofit array, from the tail to the end of the scan can b

Question: Say you have an array for which the ith element are the price of a given the Design a algorithm to find the maximum profit. You may complete as many transactions as (ie, buy one and sell one share of the stock multiple times). However, you could not engage in multiple transactions at the same time (ie, your must sell the stock before your buy again).

Say you have an array for which the ith element are the price of a given the If you are were only permitted to complete in most one transaction (ie, buy one and sell one share of the "stock", design an AL Gorithm to find the maximum profit. To find the best time to buy and sell a stock, only a single transaction can be completed Solve the idea: ... Code: pub

Class Solution {public: int Maxprofit (vectorint Maxprofit (vectorBest solution, feel good slag.As long as there is an increase can be added to the sum inside ... There is no need to calculate the rising range.Still have to analyze the problem carefully.[Leetcode] best time to Buy and Sell Stock II

Given a vector, the vector represents the price of a stock in the first day, Y to make the stock yield the largest should be bought on the day I, the first i+n days to sell, to find out the value of the maximum profit is how muchIdea: Record the minimum value with a variable, a variable record the maximum benefit, scan the price from beginning to end, when scanning to the price of the day I, if the price is smaller than the minimum value, then replace, if it is larger than the minimum value, the

Problem description: Say you have an array for whichITh element is the price of a given stock on dayI. Design an algorithm to find the maximum profit. You may complete at mostTwoTransactions. Note:You may not engage in multiple transactions at the same time (ie, you must encrypt the stock before you buy again ). Solution: 1 public int maxProfit(int[] prices) { 2 if (prices.length