best time to buy imac

Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Example 1:Input: [7, 1, 5, 3, 6, 4]output:5max. difference = 6-1 = 5 (Not 7-1 = 6, as selling-price needs-be-larger than buying price)Example 2:Input: [7, 6, 4, 3, 1]output:0in this case, no transaction was done, i.

First, the topic1, examining2. AnalysisGiven an array of daily prices for a stock, you can trade multiple times to find out how big the profit is.Second, the answer1, Ideas:Method One,Seek the maximum profit, from the back to the front, if the current price to sell, the day before the price of buy, you can complete the transaction, and gain profits. Finally, all profits can be counted. Public int maxProfit11 (int[] prices) { int total = 0;

LeetCode: Best Time to Buy and Stock Description: Say you have an array for which the ith element is the price of a given stock on day I. If you were only permitted to complete at most one transaction (ie, buy one and every one share of the stock), design an algorithm to find the maximum profit. Idea: traverse the array and save the minimum low of the eleme

Questionsay you had an array for which the ith element was the price of a given stock on day i.design an algorithm to find The maximum profit. Transactions at the most K. For example, given prices = [4,4,6,1,1,4,2,5], and k = 2, return 6.Answer with DP solution. LOCAL[I][J] Represents the number of 0~i, up to J transactions, and the last trade must contain PRICES[J] (that is, the last day must be sold), the maximum value of the proceeds. GLOBAL[I][J] Represents the number of 0~i, up to J transac

Topic:Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Analysis: One-dimensional dynamic programming (hard counting is OK)Dp[i] is the maximum profit for the [0,1,2...i] interval, the one-dimensional dynamic programming equation for the problem is as followsDP[I+1

Topic:Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Analytical:Greedy method, find the lowest and highest price of the day, the low into the higher, note the lowest day before the highest day.Turning the original price sequence into a differential sequence, the

Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.The subject only needs to be traversed once, maintaining two pointers, one pointing to the lowest price before I, one pointing to the lowest price, and the highest price before I, if prices[i] is higher than high, t

[i]=max{a[i-1],0}+subprices[i]The solution to the problem is max{a[i]}The code for the above analysis is as follows:Runtime:8msClass Solution {public: int Maxprofit (vectorYou can also count the lowest prices for those days, the highest price for that day, and then subtract the lowest value from the highest value.The initial state can be defined as the maximum amount of money that can be earned on the day I sell. set Array prices=[2,3,1,4,5,3,6]But the state transition equation can be defined

Say you had an array for which the ith element was the price of a given stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.This is very intuitive, the direct difference between the highest value on the line, the start of the tle once, because the use of O (n^2)method, and later found O (n) to be able.The first code:classSolution { Publi

Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.First, the problem is converted to a mathematical language: array a[n], and for any i The results can be obtained using O (n^2) method.The following dynamic planning methods are analyzed:For input prices[n], if know

Title: Given an array of shapes, indicating stock movements, stocks can buy and sell at random times. The maximum profit that can be savedAlgorithm: the equivalent of the rise in the stock trend sumFor example: Stock trend: 1,1,3,2,5,7,1,3,2,0. The maximum profit is (3-1) + (5-2) + (7-5) + (3-1) =9public class Solution {public int maxprofit (int[] prices) { if (0 = = prices.length) { //Empty array Retu RN 0; } int maxprofile

title :Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.1 Public classSolution {2 Public intMaxprofit (int[] prices)3 {4 intMaxprofit=0;5 intMinelement= integer.max_value;6 for(inti=0;i)7 {8Minelement=math.min (Minelement

after finishing;Calculates the sum of a continuous array element and the maximum value of the summation. Public classSolution { Public intMaxprofit (int[] prices) { if(Prices = =NULL|| Prices.length ) return0; for(intI=prices.length-1; i>0; i--) {Prices[i]= Prices[i]-prices[i-1]; } prices[0] = 0; intMaxprofit = 0; intProfit = 0; for(inti=0; i) {Profit+=Prices[i]; if(Profit ) {Profit= 0; } Else if(Profit >Maxprofit) {Maxprofit=profit; } } returnM

Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Analysis: Greedy algorithm. Record the minimum value of the price that appears earlier, and then update the maximum benefit with Max (Maxprofit, Prices[i]-min). The code is as follows:classSolution { Public: intM

Say you has an array for which the i-th element is the price of a given-stock on day I.If you were-permitted-to-complete at most one transaction (ie, buy one and sell one share of the stock), design an AL Gorithm to find the maximum profit.Example 1:Input: [7, 1, 5, 3, 6, 4]output:5max. difference = 6-1 = 5 (Not 7-1 = 6, as selling-price needs-be-larger than buying price)Example 2:Input: [7, 6, 4, 3, 1]output:0in this case, no transaction was done, i.

121. Best Time to Buy and keep Stock, sellstock Say you have an array for whichITh element is the price of a given stock on dayI. If you were only permitted to complete at most one transaction (ie, buy one and every one share of the stock), design an algorithm to find the maximum profit. Example 1: Input: [7, 1, 5, 3, 6, 4]Output: 5max. difference = 6-1 = 5 (not