bitwise computers

I still don't like bitwise operations... Ah... I just saw a post about a netizen's bitwise operation reversing one byte on the Internet and posted it to learn to accumulate...Code: UnsignedCharReverse8 (unsignedCharC){C = (C 0x55) 1| (C 0xaa)>1;C = (C 0x33) 2| (C 0xcc)>2;C = (C 0x0f) 4| (C 0xf0)>4;ReturnC;} Analysis: ItsAlgorithmYes:The first is a group of two digits and two digits. the first half an

Control hardware often involves opening/closing specific bits or viewing their status. The bitwise operator (1. Open the bitOpens a bit that will open the bit in the lottabits corresponding to the bit representationLottabits=lottabits|bit;2. Toggle BitToggle bit, will swap lottabits with bitLottabits=lottabits^bit;3. Close the bitTurns off the bit that corresponds to the bit representation in the Lottabitslottabits=lottabits~bit;4. Test the value of t

Bitwise AND operator "" are binary operators. Its function is the binary phase corresponding to the two numbers involved in the operation. The result bit is 1 only when the two binary numbers are 1. Otherwise, the result bit is 0. The number of involved operations is supplemented. For example:9 5 writeable formula: 00001001 (Binary complement of 9) Amp; 00000101 (Binary complement of 5) 00000001 (Binary complement of 1) Visible9 5 = 1.

"" bits and operators:The bitwise AND operator "" is the binocular operator. Its function is to participate in the operation of the two number of the corresponding binary phase. Only the corresponding two binaries are 1 o'clock, the result bit is 1, otherwise 0. The number of participating operations appears in a complementary fashion.Such as:0000100100000101=00000001The "|" bit or operator:Bitwise OR operator ' | ' is the binocular operator. Its func

"^" Bitwise logical operators Class YSF {public static void Main (string[] args) {System.out.println (5 ^ 10 ^ 10);System.out.println (5 ^ 10 ^ 5);"^" Features: one data to another data bit XOR or two times, the number itself is unchanged}} Need to define third-party variables Class YSF {public static void Main (string[] args) {int x = 10;int y = 5;int temp;temp = x;x = y;y = temp;System.out.println ("x =" + x + ", y =" + y ");Defin

Bitwise Operations implement addition, subtraction, multiplication, division, and four arithmetic operations1. Description How do I use bitwise operations to perform the addition, subtraction, multiplication, and division of integers? 2. SolutionYou need to be familiar with the bit operation implementation of some common functions, specifically: (1) Addition implementationIt is easy to use the "XOR" and "or

Symbol: ^Bitwise XOR, rule: Same as zero, different to one.Practical example: Only one number appears once in a set of data.All other numbers appear in pairs. Please find out the number. (using bit operations)Code implementation:#include The result is: 7This article from "Pzd Chuan Feng" blog, declined reprint!The bitwise XOR of the C language

Tag: XOR represents print AMP analysis based on nbsp operation conversionThe bitwise operator is primarily for binary, and it includes: "and", "or", "XOR".1. With operator ( representation)The operation rules are as follows:The two operands have a bit of 1 and the result is 1, otherwise the result is 0, for example:int a=5;int b=2;System.out.println ("A and B" with the result is: "+ (ab));Operation Result:A and B with the result is: 0Analysis:The valu

By explaining the part of memory, there is a relatively deep understanding of programming. Data structure is an important part of the whole memory, then on the data structure of this aspect of the problem also needs to the binary, bit operation, coding the three aspects of the further elaboration. The above-mentioned data structure is logically carried out in this aspect, now from the principle of elaboration.Our programming is actually dealing with the data, the computer all the time in the com

Bitwise operations are performed directly on the binary. 3:0000 0011 Shift left two bit 0000 1100 >> Right Shift 3>>2–> 3/2/2/2/2 3:0000 0011 Move right two bit 0000 0000 When signed right shift, the highest bit is 0 with 0 complement, the highest bit is 1 with 1 complement. -3 >> 2 -3 1000 0000 0000 0000 0000 0000 0000 0011 Original Code 1111 1111 1111 1111 1111 1111 1111 1100 anti-code 1111 1111 1111 1111 1111 1 111 1111 1101 Complement Move right

Original: http://www.mkyong.com/java/java-convert-ip-address-to-decimal-number/ From the same blog. IP to Digital (the second algorithm.) Move with left, bitwise, or implemented. Efficiency is higher than the previous one. ）： Public long Iptolong (String IPAddress) { long result = 0; string[] Ipaddressinarray = Ipaddress.split ("\;"); for (int i = 3; I >= 0; i--) { Long IP = Long.parselong (ipaddressinarray[3-i]); Left shifting 24,

Operation Performs a bitwise XOR on two expressions. result = expression1 ^ expression2 Parameters Result Any variable . Expression1 Any expression . Expression2 Any expression. Description The ^ operator looks at the value of the binary representation of two expressions and performs a bitwise XOR. The results of this operation are as follows: 0101(expression1)1100(expression2)----1001(Results)

Operation Performs a bitwise OR on two expressions result = expression1 | expression2 Parameters Result Any variable . Expression1 Any expression . Expression2 Any expression. Description | operator to view the values of the binary representations of two expressions and to perform a bitwise OR action. The results of this operation are as follows: 0101(expression1)1100(expression2)----1101(Resul

The bitwise operator in the ECMAScript language, all values are stored in the IEEE-754 64-bit format, but the bitwise operator does not store the 64-bit storage format directly, the value 64 is converted to a 32-bit integer, the operation is executed, and the result is converted to 64 bits. The first 31 bits in the 32-bit are used to represent the value of an integer, the 32nd bit is used to represent the

Operation Performs a bitwise and on two expressions. result = expression1 expression2 Parameters Result Any variable . Expression1 Any expression . Expression2 Any expression. Description The operator looks at the value of the binary representation of two expressions and performs a bitwise AND action. The results of this operation are as follows: 0101(expression1)1100(expression2)----0100(res

On the binary number of the bit operation, the common is "or, and, not" the three simple operations, of course, PHP manual also has "XOR, left shift, right shift" the three operations. How to define PermissionsThe permissions are defined by a value of 2 N, and so on. Why do you define this? This definition guarantees that there is only one 1 in each permission value (binary), and that it corresponds to exactly one permission. Like what: Define (' ADD ', 1); Increased permissions define (' UPD '

1: XOR operation: The symbol ^, also known as the XOR operation, its rule is if the operation of the two binary numbers, the result is 0, the XOR is 1, namely: 0^0=0; 0^1=1; 1^0=1;1^1=0　　2: Performs a bitwise XOR on two expressions.result=expression1^expression2ParametersResultAny variable.Expression1Any expression.Expression2Any expression.DescriptionThe ^ operator looks at the value of the binary notation of two expressions and performs a

value of B is true, the value of x is computed, the result of the operation is the value of x, otherwise, the value of Y is evaluated and the result of the operation is Y. A conditional expression never evaluates both X and Y. The conditional operator is right-associative, that is, a right-to-left grouping is calculated. For example, A?b:c?d:e will be executed by a?b: (c?d:e). [1] condition? Result 1: Result 2The inside? Number is a format requirement. It can also be understood as whether the c

Bitwise operators: ,|,^,are based on binary number movement, and the other binaries are converted to binaryShift the N-bit to the left, which is equal to n times 2, and the N-bit to the right, which is equal to the N-squared divided by 2.^:a^a=0, obey the commutative law, and bind the law a^b^a=a^a^b=b: if the number of a is even, then the result is always B.+ +,--and the operation of a comma-expression:1 int x=3; 2 int y= (++x,x++,x+);The operation o

Unity's LayerUnity uses Int32 to represent 32 layers, and int32 uses binary to represent a total of 32 bits.0000 0000 0000 0000 0000 0000 0000 000031 0See a few examples to turn on Layer 2Layermask mask = 1The 1 on the left of Turn on Layer 0 and Layer 2Layermask mask = 1 Turn on Layer0 and close Layer2Layermask mask = 1 Turn on layer DefaultLasermask mask=1 Script examplesHere is a script example that binds it to the cameraUsing unityengine;Using system.collections; [requirecomponent (typeof (C