blackberry q1

changes to the z-axis, the y-axis to the x-axis, and the z-axis to the y-axis (regardless of direction). 2.2.34-dollar calculation of the design of Euler's anglefloat q0 = 1, q1 = 0, q2 = 0, q3 = 0; Defining four elementsvoid Imu_update (void){float norm;Float GX = Mpu6500_gyro.x*gyro_gr,gy = MPU6500_GYRO.Y*GYRO_GR,GZ = unit conversion between mpu6500_gyro.z*gyro_gr;//anglesfloat ax = Acc_avg.x,ay = Acc_avg.y,az = acc_avg.z;float q0q0 = q0 * Q0;float

Requirement 1:Use the for loop to create ten files in the/root/scripts/practice/q1/oldboy directory. The names are as follows: Oldboy-1, Oldboy-2, ..... Oldboy-10. Script implementation: #! /Bin/bash # question1shopt-s expand_aliasesalias LL = "ls-L" CD/root/scripts/practice/q1 # first, determine whether the directory exists. If it does not exist, create the directory if [! -E oldboy] Then/bin/mkdir oldboy

To: Http://hi.baidu.com/zhang_bi/blog/item/57edb701a9da6b00728b65db.html There are two types of value assignment statements in OpenGL:Blocking value assignment statement ("= ")AndNon-blocking value assignment statement (". Correct use of the two assignment statements is very important for the design and simulation of the Tilde. The following example shows the difference between blocking and non-blocking assignment. Let's take a look at several paragraphsCodeAnd the corresponding circuit

, the vectors (P1-Q1) and (P2-Q1) are located on both sides of the vector (Q2-Q1), I .e. (P1-Q1) × (Q2-Q1) * (P2-Q1) × (Q2-Q1) Under the same principle, the specific implementatio

-Site Test If the two line segments overlap, the two lines must cross each other. If P1P2 cross-sets q1q2, the vectors (P1-Q1) and (P2-Q1) are located on both sides of the vector (Q2-Q1), I .e. (P1-Q1) × (Q2-Q1) * (P2-Q1) × (Q2-

Three or four yuan to Euler angle conversionAs a result of arctan and arcsin, this does not cover all orientations (the range of values for the corners has been met), so atan2 is needed instead of arctan.Iv. use in other coordinate systemsIn other coordinate systems, the above formula should be adjusted according to the definition of the axis. As in Direct3D, the x-axis of the Cartesian coordinate system changes to the z-axis, the y-axis to the x-axis, and the z-axis to the y-axis (regardless of

Today, the smartphone field is highly competitive, and major mobile phone manufacturers also have their own "dedicated secrets" in terms of smart phones ". As the leader in the mobile phone industry, Nokia's Symbian systems have a large share. However, the advantage of note is declining, and Nokia is worried about the future situation. This is directly related to the impact of other smart systems. The biggest threat is Mac OS, Windows Mobile, and Android. In addition, the old

BZOJ1047[HAOI2007] the ideal squareTest instructionsThere is a matrix of a*b integers, which asks for a n*n square area, which minimizes the difference between the maximum and minimum values of all the numbers in the region. a,b≤1000,n≤100ExercisesDo 4 times the monotone queue. Using the monotone queue to find the maximum minimum value of row J of line I to row j+n-1 of line I, and then use this to find the maximum minimum value of row J of line I to column i+n-1 j+n-1. The last enumeration of t

/4153933833_bdd657cde7_o.pngBut in recent years, the mobile phone operating system market has been sharply volatile. The leading rebel is Apple's iphone OS, with the second shockwave coming from Google's Android, and Palm's webOS in the fun, see Figure 6. It was commented that1. Symbian is too old to escape the fate of the twilight.2. iphone Maverick, take the fine line, become a fashion vane.3. Android slow, free open source, take the mass line, the future most likely to become the mainstream o

very high, and the resource cost is relatively small. It is not necessary to use parallel operations.(2) read a parallel execution planLS @ LEO> select object_type, count (*) from leo_t group by object_type; object type grouping statistics35 rows selected.Execution Plan Parallel Execution Plan----------------------------------------------------------Plan hash value: 852105030Bytes ------------------------------------------------------------------------------------------------------------------|

:1. Serial + SyncThe tasks in the serial queue are executed one after the other, and the synchronization tasks are executed in the order of execution, so the conclusion is that the synchronization tasks in the serial queue will be executed one after the other.dispatch_queue_t q1 = dispatch_queue_create ("Serial queue", dispatch_queue_serial);Dispatch_sync (Q1, ^{[Nsthread Sleepfortimeinterval:5];NSLog (@ "S

1. How to determine whether a basic amplification circuit is a common-base, co-injection or a common set? Remove the input, the output side, the rest is the common end. The following figure: The UI is connected to the base pole, and the UO is the common collector. 2. Basic Amplification Circuit: 2-1. Co-emitting minimal signal amplifier Function: Amplify the small amplitude voltage signal Working principle: Q1 is connected to the common-injection

; Priority_queueLong Long,vectorLong Long>,cmp>Q; for(intI=1; i) {scanf ("%lld",F[i]); Q.push (F[i]); } scanf ("%lld",e); Size=s; while(size!=1) {u[cnt].a=Q.top (); Q.pop (); Size--; U[CNT].B=Q.top (); Q.pop (); Size--; Q.push (u[cnt].a+u[cnt].b); CNT++; Size++; } QueueLong Long>Q1; QueueLong Long>P2; intf=0; Q1.push (u[0].a); Q1.pu

earthworms look likeTwo queues Q1,q2Q2 the state of being in the queue in its own transfer, from small to large order.Then the state shifted out of the Q2, all put into the Q1,Because the transfer cost is 1,q2 and monotonous, so can guarantee Q1 is also monotonousEach time comparing Q1 and Q2 's team head, take out th

Maximum minimum heap dynamic seeking median numberTest instructions: Enter the number of M and output the median at this time when the number entered is an odd number.There are a total of m/2+1 to output, 10 per line.Analysis:Use two priority queues to simulate the maximum minimum heap. The median is x, that is, half the number is smaller than x, and half is larger than X.Just meet the characteristics of the heap.Simulates a number less than X with a priority queue