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If you open a website in IE and enter the following magic code in your browser, you can modify and copy the page content at will! Magic Code 1 Magic Code 1 Javascript: r = 0; X1 =. 1; Y1 =. 05; x2 =. 25; y2 =. 24; X3 = 1.6; Y3 =. 24; X4 = 300; Y4 = 200; X5 = 300; Y5 = 200; DI = document. images; Dil = di. length; function a () {for (I = 0; I-Dil; I ++) {Dis = di [I]. style; DIS. position = 'absolute '; DIS. left = math. sin (R * X1 + I * X2 +

]; 200 201 _ isRunning = YES; 202 204 205 if (_ isRunning) {// indicates that the timer is running 206 [_ timer setFireDate: [NSDate distantPast]; 207 208} else {211 212 213 [_ timer setFireDate: [NSDate distantFuture]; 214 215} 216 217} 218 221-(void) stop {222225 _ isRunning =! _ IsRunning; 226 229 if (_ isRunning) {// indicates that the timer is running 230 233} else {234 235 [_ timer setFireDate: [NSDate distantFuture]; 236 237} 238 239 _ isRunning = NO; 240 241} 242 245-(void) fuwei {246 25

Ultraviolet A 10626 Buying Coke (memory-based) Address: Click to open the link Buy an 8-point drink, and you have three coins: 1, 5, and 10. Then I asked you to buy a c-bottle drink, and buy one at a time. You have the minimum number of coins. There are several ways to do this: 1: cast 8 points and 2: cast a 5-point 3 points and 1 point 3: If you place a score of 10, find the score of 3. If you place a score of 10, find the score of 5. There are other solutions, but they are not too cost-effecti

(s[i],t); } } for(intI=0; i){ if(i) printf (", "); printf ("%s", S[i]); } printf (". \ n");}return 0;}2034: Sort by area Time Limit (Common/java): 1000ms/10000ms Memory Limit:65536kbyteTotal submit:1163 accepted:433 DescriptionGiven the two-dimensional geometry of triangles, rectangles, and circles, sort from large to small in terms of area.InputThe input data includes multiple lines, one geometry per behavior (no more than 100 geometries). The input formats for the various geome

nature, nature's mutation is a small probability event) randomly changing the value of a gene in a chromosome.Sometimes, in addition to choosing, crossing , and mutating These three operations, we also add other operations (such as reversals ) to specific issues, but select , Cross , mutation is a genetic operation in which all genetic algorithms are common.In this paper, a common application of genetic algorithm-solving complex nonlinear function extremum problem as an example to illustrate h

function apply Apply (X, MARGIN, FUN, ...)Parameters:X:an array, including a matrix.Margin:1: Row action; 2: Column operation FUN: The name of the function The result is the same as that of colmeans,colsums,rowmeans,rowsums, by using apply, which can easily be summed/averaged by ranks. Examples are as follows: > A> A[, 1] [, 2] [, 3] [, 4][1,] 1 4 7 10[2,] 2 5 8 11[3,] 3 6 9 12> Apply (a,1,sum)[1] 22 26 30> Apply (a,2,sum)[1] 6 15 24 33> Apply (a,1,function (x) sum (x) +2)[1] 24 28 32> Apply (a

JavaScript is not a strict object-oriented language, but with some object-oriented features, we can create custom classes in JS with these features.The classes in JavaScript are actually a series of variables and methods that are wrapped in a function keyword.For example, define a car class: function Car (name,number) { this. Carname=name; this. carnumber= number; this. run=function(speed) { alert ("The car Travels at" +speed+ "speeds.) "); }}Ways to use this class:var

) = Math.sqrt ((x1-x2) * (X1-X2) + (y1-y2) * (Y1-y2));2.2 Multi-side shape area conversion formulaFirst I give the formula directly:S (total) =math.abs (0.5* (x1*y2-y1*x2+x2*y3-y2*x3+....+xn*y1-yn*x1)));How is this formula deduced? Let me tell you about it.2.2.1 Triangle area with coordinate pointsWe all know the most common area formula in triangles: S=1/2*a*h.In my previous article (stored procedure Judging two lines coincident point) also mentioned

a real number, it is the same as the transpose of the matrix in linear algebra. If a is a complex matrix, the elements after a transpose are composed of the complex numbers of the elements corresponding to. "A. '" indicates the transpose of array A. If array A is a plural array, it only indicates the transpose of the plural matrix array, and does not perform the matrix or array concatenation operation. [Example 3.17] matrix and array transpose operations.In the command window, enter the follo

Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--> /// /// (X1, Y1) and (X2, Y2) stand for beeline segment 1; /// (X3, Y3) and (X4, Y4) stand for beeline segment 2. /// This method will help us to check whether the two line segments will cross with each other. /// /// Static Bool Iscorssline ( Double X1, Double Y1, Double X2, Double Y2,

video playing performance on the screen is quite good. For other functions, vx969 also supports AB re-reading, Image Browsing, text reading, FM recording, recording, and other functions. It has a built-in mah lithium battery, you can play music for about 15 hours or 6 hours. Meizu X3 1 GB 299 yuan Meizu X3 uses Philips decoding chip, ensuring sound quality, while maintaining outstanding price, 1 GB is only

main () {int a1, b1, a2, b2, x2, x3, y2, y3, ans, m1, m2, n1, n2; while (scanf ("% d", a1, b1, a2, b2 )! = EOF) {m1 = a1; m2 = a2; n1 = b1; n2 = b2; x2 = x3 = y2 = y3 = 0; while (! (A1% 2) |! (A1% 3) {if (a1% 2 = 0) {x2 ++; a1/= 2;} if (a1% 3 = 0) {x3 ++; a1/= 3 ;}} while (! (B1% 2) |! (B1% 3) {if (b1% 2 = 0) {x2 ++; b1/= 2;} if (b1% 3 = 0) {

never be executed. def f1():print('123')return "111" print(456) f1() Case result: 123 Case 3: The result is 123 and 111, because a return value is given to r, print (r) and print 111. Def f1 ():Print ('20140901 ')# In case of return, the function body is terminated immediately,Return "111" # assign 111 to rR = f1 ()Print (r) Case results: 123 and 111 Case 4: When the function does not return, the automatic default return value is None; the return result is 123 and None. Because no return is re

/article/details/26471527But there are several errors that need to be pointed out, not 0 o'clock, which should be obtained:A11= x1-x0 +A13* X1 A12= y1-y0 +A13* Y1 A13=A21 = x3-x0 + A23 * x3 A22= y3-y0 +A23* y3 A23=A31 = x0 a32 = y0 A33 = 1Key code:matrix3x3 a4shapecorrect::squaretoquadrilateral (double x0, double y0, double x1, double y1, double x2,double y2, double x3