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Active Time: 2014.11.23 10:00 to 2014.11.25 20:00
Event Address: http://bbs.phpthinking.com/thread-305-1-1.html
Event
Description
Bessie has gone to the mall's jewelry store and spies a charm bracelet. of course, she 'd like to fill it with the best charms possible from the N (1 ≤ N ≤3,402) available charms. each charm I in the supplied list has a weight Wi (1 ≤ Wi ≤ 400), a 'inclurability 'factor Di (1 ≤ Di ≤ 100 ), and can be used at most once. bessie can only support a charm bracelet whose weight is no more than M (1 ≤m
1. First need a Bluetooth adapter, the bracelet requires Bluetooth 4.02. Settings for the virtual machine:That's how you set it up.3. Plug the Bluetooth adapter into the USB port to seeIndicates that the virtual machine is connected to Bluetooth and, if it is gray, can right-click the Connect connection.4. Restart the Android system to make sure that you are actively connected when the Bluetooth starts.It doesn't matter if the connection unsuccessful
1. Download the appIn the case of being able to surf the internet, search the Xiaomi bracelet app to find2. Install the AppEnter terminal3. Enter in the terminal by the Red zone statement.Go to Super User firstFind the path where the downloaded app is locatedthen enter the pathRun the statement adb install xxx.apk (own apk name) installation4. Installation CompleteInstalling the Android4.4 connection in the VM Xiaomi mobile phone installation mi
1, create a new file, draw a circle fill any color, and then perform the layer style, as shown in the figure:
2. Layer style setting, inner glow parameter modification setting:
3. Bevel and Emboss parameter settings:
4. Contour parameter Setting
5, Layer style gloss settings:
6, color superposition parameter setting
7, the gradient superposition parameter modification setting
8, the approximate effect come
the way Photoshop makes a bracelet
1. Open ps new canvas 500*500 pixels, resolution of the RGB color 8-bit background white
2. Select the elliptical Marquee tool, press and hold shift+ait to draw a circle, so that the drawing circle will not deform, and then fill 50% Gray, do not cancel the selection continue to click Select-Transform the selection to narrow the selection, narrow down shift+ait will not deform.
integrating the view12, the height, the date, the age choice card the better display plan13, share the current page. Principle: Save the current view settings to the cache caches and measure get the bitmap of the current view cache14, sound, vibration of the reminderXV, the notification receives, temporarily uses is polling, considers oneself uses the long connection realizes the notification, through the heartbeat packet to maintain the connection to consider the network and so on the situatio
The simplest knapsack problem, the title should be in addition to the Backpack Test Center: You cannot open a two-dimensional array. I haven't opened the two-dimensional. It is impossible to see the data in light.Too big.There are two ways to improve the province's memory DP:1 array of so-called volumes2 Reverse TableLong time did not do backpack DP, suddenly think such a knapsack problem is very easy.Here are two ways to solve the equation:1 Calbag () is a scrolling array2 CalBag2 () is reverse
Poj 2888 magic bracelet has restrictions (conditional Polay problems)
I learned a combination of mathematics, almost all of which were self-taught. I don't know how to do a lot of things, and it is difficult to find appropriate materials. I think this is the difficulty of a weak school, but I will continue to work hard, in fact, I now think that stupid blog is quite good, the blog address is as follows: http://hi.baidu.com/%B1%BF%D0%A1%BA%A2_shw/blog/
Label: style blog HTTP color Io OS AR for strong Question link: http://poj.org/problem? Id = 3624 Ideas: Classic 0-1 backpack problems: The analysis is as follows: Code: # Include Using Namespace STD; Const Int Max_n = 12880 + 10 ; Int DP [max_n], W [max_n], d [max_n]; Int Max ( Int A, Int B ){Return A> B? A: B ;} Int Main (){ Int N, m; memset (DP, 0 , Sizeof (DP); CIN >>N> M; For ( Int I = 1 ; I I) CIN > W [I]> D [I]; For ( Int I = 1 ; I I) For ( Int J = m; j-W [
For you, millet hand ring 2 users to detailed analysis to share the open wrist switch display of the settings tutorial.
Tutorial Sharing:
1, first you need to upgrade the Millet Sports app to the latest version, this is October 2016 after the new edition of new features.
2, open the Millet Movement app, click "My" below, choose your millet bracelet 2
3, the "Turn wrist switch hand ring information" function open
With this feature turn
Let's take a look at the results of the production:
Let's start by making Photoshop Tutorials:
1. Build a 400*400 document.
2. Set the foreground color and background color to the default color, and perform the filter--the cloud.
3. Perform filters-liquefaction, whatever you like.
4. Make a concentric circle with a positive circle selection.
5. Add layer Style-bevel and emboss.
7. Press Ctrl+u for a bracelet to tune a favor
cases where the initialization is-INF, only DP [0] = 0. This is the requirement: the maximum value that exactly fills up.
For (INT I = 0; I {
// Start from the first item
For (Int J = m; j-V [I]> = 0; j --) // J-V [I]> = 0 to prevent array out-of-bounds, after all, the backpack capacity cannot be negative.
{
// Subtract 1 from the backpack each time to see if this item can be put in.
// Printf ("% d: max (% d, % d)", J, DP [J], DP [J-C [I] + V [I]);
DP [J] = max (DP [J], DP [J-V [I] + C [I])
BonBon, bonbon bracelet
BonBon is a group of Sweet Candy button styles made with CSS3. In the past, we used images or JavaScript to achieve beautiful button effects. As more and more browsers support and improve CSS3, there are no obstacles to using CSS3 to achieve beautiful buttons.
Download the demo plug-in
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Title Link: https://vjudge.net/problem/POJ-3624Test instructions: There are n items, each with a different weight of WI and value Di,bessie can only take away items with a weight of not more than M, if the total value is the largest, and output the total value.Start with the normal DP and then display the hyper memory, and press the code below also hyper memory (DP array too Large) but this method can learn#include #includeusing namespacestd;intn,m;//int w[3403],d[12881];intv,w;intdp[3403][12881
Millet hand Ring Charging specific method:
The first step, first take the hand ring, the left-hand side of the light pressure strap, so that the fuselage exposed, and then pull the fuselage from the strap down, this step is mainly to the strap off the hand ring.
In the second step, as shown in the figure, we identify the direction of the body's charging contact, which corresponds to the proper installation of the hand ring charger.
The third step, the charger installed, we can use the
In the millet handset opens "The Millet hand ring" to enter after clicks "More" (the upper right corner three point icon)
After opening more interfaces we find the "service" and click on it to open the entry, the effect is as follows
Then we find the following "micro-mail Access" option to click on it to open the entry effect below.
After the access, we'll find the following "micro-mail Access" and then we can follow the instructions.
Then will automatically jump
Final effect 1: Create a new file, create a layer, and draw a small positive circle with the oval box selection tool to fill in any color. then double-click the layer to bring up the layer style. the parameter settings are as follows. 2. glow in the
Poj_2888
At the beginning, I was too impetuous to learn polyA. It was just a formula. In fact, it was not based on understanding. Today, I read the black book again, and finally I was able to deduce the polyA formula based on the Burnside theorem.
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