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POJ 1952 buy low, buy lower dp record data, pojdp The longest descending subsequence is added to record the number of longest descending subsequences, and then deduplication is required. The most troublesome thing is to remove duplicates. The basic idea is: duplicate values are displayed in all cases, and then sub-sequences of the same length exist. Here, the sub-sequence of the DP Record ends with the curr

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The longest descending subsequence is added to record the number of longest descending subsequences, and then deduplication is required. The most troublesome thing is to remove duplicates. The basic idea is: duplicate values are displayed in all cases, and then sub-sequences of the same length exist. Here, the sub-sequence of the DP Record ends with the current value, and you must select the longest descending subsequence of this value, then you need to subtract the subsequence that already exis

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)); Memset (C, 0, sizeof (INT) * (n + 1 )); TBL [0] = 1; C [0] = 1; For (INT I = 1; I { TBL [I] = 1; For (Int J = 0; j { If (TBL [J] =-1) continue; If (ARR [J]> arr [I] TBL [I] { TBL [I] = TBL [J] + 1; } } For (Int J = 0; j { If (ARR [J]> arr [I] TBL [I] = TBL [J] + 1) { C [I] + = C [J]; } } If (C [I] = 0) C [I] = 1; // when increasing /* You do not need the following code. For (Int J = 0; j { If (ARR [I] = arr [J] TBL [I] = TBL [J] C [I] = C [J]) { TBL [I] =

Poj 1952 buy low, buy lower maximum descent sub-sequence count, pojlower Question: Calculate the maximum length and number of sub-sequences for n. Analysis: Dp to avoid repeated Counting during counting. Code: // Poj 1952 // sep9 # include