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[Leedcode 123] best time to Buy and Sell Stock III

Say you has an array for which the i-th element is the price of a given-stock on day I.Design an algorithm to find the maximum profit. You are in most of the transactions.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again). Public classSolution { Public intMaxprofit (int[] prices) { /*each point in the

[LeetCode] Best Time to Buy and keep Stock IV, leetcode=

[LeetCode] Best Time to Buy and keep Stock IV, leetcode= Say you have an array for which Ith Element is the price of a given stock on day I . Design an algorithm to find the maximum profit. You may complete at most k transactions. Note:You may not engage in multiple transactions at the same time (ie, you must encrypt the

[Leetcode] best time to Buy and Sell Stock III

Problem Description:Say you has an array for which the i-th element is the price of a given-stock on dayI.Design an algorithm to find the maximum profit. You are in most of the transactions.Note:Engage in multiple transactions on the same time (ie, you must sell the stock before you buy again).Basic idea:Dynamic Planning method‘‘‘// f[k, ii] represents the max pr

Leetcode-best time to buy and keep stock

Say you have an array for which the ith element is the price of a given stock on day I. If you were only permitted to complete at most one transaction (ie, buy one and every one share of the stock), design an algorithm to find the maximum profit. Analysis: the maximum price difference between buying and selling is calculated. You only need to calculate the price

Leetcode best time to buy and other stock II

Say you have an array for whichITh element is the price of a given stock on dayI. Design an algorithm to find the maximum profit. you may complete as your transactions as you like (ie, buy one and every one share of the stock multiple times ). however, you may not engage in multiple transactions at the same time (ie, you must wait the

Leetcode No122. best time to buy and Sell the stock Ii_leetcode

Question: Say you have an array for which the ith element are the price of a given the Design a algorithm to find the maximum profit. You may complete as many transactions as (ie, buy one and sell one share of the stock multiple times). However, you could not engage in multiple transactions at the same time (ie, your must sell the stock before your

122. Best time to Buy and Sell Stock II

First, the topic1, examining2. AnalysisGiven an array of daily prices for a stock, you can trade multiple times to find out how big the profit is.Second, the answer1, Ideas:Method One,Seek the maximum profit, from the back to the front, if the current price to sell, the day before the price of buy, you can complete the transaction, and gain profits. Finally, all profits can be counted. Public int maxPro

best time to Buy and Sell Stock IV solution

Questionsay you had an array for which the ith element was the price of a given stock on day i.design an algorithm to find The maximum profit. Transactions at the most K. For example, given prices = [4,4,6,1,1,4,2,5], and k = 2, return 6.Answer with DP solution. LOCAL[I][J] Represents the number of 0~i, up to J transactions, and the last trade must contain PRICES[J] (that is, the last day must be sold), the maximum value of the proceeds. GLOBAL[I][J]

188 best time to Buy and Sell Stock IV

188 best time to Buy and Sell Stock IVThis question is the best I've ever had to look at the way I've run out of all the Python solutions.classSolution:def __init__(self): Self.start=0 Self.end=0 Self.ans=0 SELF.P= [] defMaxprofit (self, k, prices): I= 1ifLen (prices) : return0 whileI Len (Prices): Self.p.append (Prices[i]-Prices[i-1]) I+ = 1ifK >=Len (SELF.P):returnSUM ([x forXinchSelf.pi

Leetcode--best time to Buy and Sell Stock

Only every time I look at this picture of the C + + does not have a white learning AH ~ ~ ~ usually with the time of the different Miss Eclipse, all kinds of nostalgia java~~~ This is the biggest profit, originally I think is to find the minimum and maximum, the difference is not the maximum profit, and then think, the minimum may be after the maximum value, can not be said to buy back in number 3rd to sell the

[Leetcode] (python): 123-best time to Buy and Sell Stock III

Source of the topic:https://leetcode.com/problems/best-time-to-buy-and-sell-stock-iii/ Test Instructions Analysis:Similar to the above question, Array[i] represents the price of items for the first day, if only 2 times can be traded. Ask for maximum profit. Topic Ideas:This is a dynamic planning issue. It is not difficult to think of splitting the entire array into two parts. Then use two arrays

[Leetcode] best time to buy and stock

Question Say you have an array for which the ith element is the price of a given stock on day I. If you were only permitted to complete at most one transaction (ie, buy one and every one share of the stock), design an algorithm to find the maximum profit. Answer To maximize the benefits, buy at the lowest price and se

121:best time to Buy and Sell Stock "array" "two pointers"

Title Link: click~/* Test instructions: An array, the element I represents the price of the stock of day I, only allowed to buy and sell once, for maximum profit *//** * Ideas: Two pointers, one scan the entire array, the other record the minimum value of the scanned element * During the scan, update the minimum value while updating the maximum profit * Maximum profit: Max (A[j]-a[i]), J>i */class

best time to Buy and Sell Stock

Given a vector, the vector represents the price of a stock in the first day, Y to make the stock yield the largest should be bought on the day I, the first i+n days to sell, to find out the value of the maximum profit is how muchIdea: Record the minimum value with a variable, a variable record the maximum benefit, scan the price from beginning to end, when scanning to the price of the day I, if the price is

111_leetcode_Best Time to Buy and invalid Stock III

Say you have an array for which the ith element is the price of a given stock on day I. Design an algorithm to find the maximum profit. You may complete at most two transactions. Note:You may not engage in multiple transactions at the same time (ie, you must encrypt the stock before you buy again ).1: special case; 2: traverse two numbers from front to back and f

Leetcode: best time to buy and stock

Say you have an array for whichITh element is the price of a given stock on dayI. If you were only permitted to complete at most one transaction (ie, buy one and every one share of the stock), design an algorithm to find the maximum profit. The idea without algorithms is terrible. N ^ 2 definitely times out, but it is still written. Finally, I took a look at oth

[Leetcode] best time to buy and stock

Say you have an array for whichITh element is the price of a given stock on dayI. If you were only permitted to complete at most one transaction (ie, buy one and every one share of the stock), design an algorithm to find the maximum profit. Class Solution { Public : Int Maxprofit (vector Int > Prices ){ Int Profit = 0 , Minprice; Int Len = Prices. Siz

[Leetcode] best time to Buy and Sell Stock I,ii,iii,iv

Three types of stock trading algorithmsFirst, there is no limit to the number of transactionsUse greedy strategy to find the longest increment sequence and accumulate the corresponding profit.Second, only one transactionUsing the dynamic programming algorithm, the minimum price before the corresponding time node is recorded from the point of travel, and the maximum profit at this node is obtained while the minimum price is updated.Three, up to two tim

121. Best time to Buy and Sell Stock

/* * 121. best time to Buy and Sell Stock * This topic is simple, but I still do it wrong. This problem is more than you think. * First the order of Min and Max does not matter. In addition, you can start looping from 0 without waiting for 1 to start */ public Span style= "color: #0000ff;" >int maxprofit (int [] prices) { int min = integer.max_value, MAX = 0; for (int i = 0; i = Math.min (min, pr

[Leetcode] Best time to Buy Stock

Consider that the price of a stock is constantly changing, and selling can only be done after buying. and can only buy and sell once.I want to sweep it at the beginning and ask for the smallest, but certainly not so simple. you're 484 stupid .Because it can only be sold once, if I sell, the possible profit value is, Prices[i]-min, is today's price.Comparing this value to the previous possible maximum, you c

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